Problem 28
Question
If \(f(x)=\frac{x+8}{2 x-1}\) and \(g(x)=\frac{x-2}{x-5},\) find each function value. $$ g(-5) $$
Step-by-Step Solution
Verified Answer
The value of \( g(-5) \) is \( \frac{7}{10} \).
1Step 1: Understand the function
The given function is \( g(x) = \frac{x-2}{x-5} \). To solve for \( g(-5) \), we need to substitute \( x = -5 \) into this function.
2Step 2: Substitute the value into the function
Substitute \( x = -5 \) into \( g(x) = \frac{x-2}{x-5} \). This gives us \( g(-5) = \frac{-5-2}{-5-5} \).
3Step 3: Perform the calculations
Calculate the numerator: \( -5 - 2 = -7 \). Next, calculate the denominator: \( -5 - 5 = -10 \). So, \( g(-5) = \frac{-7}{-10} \).
4Step 4: Simplify the expression
The simplified form of \( \frac{-7}{-10} \) is \( \frac{7}{10} \) because a negative divided by a negative is positive.
Key Concepts
Function EvaluationNumerator and DenominatorSimplifying Fractions
Function Evaluation
Function evaluation is the process of finding the value of a function at a specific point. To evaluate the function, you simply substitute the given value into the variable of the function and perform the necessary operations. For instance, if we have a function \( g(x) = \frac{x-2}{x-5} \), and we want to find \( g(-5) \), we substitute \( x = -5 \) into the function. This substitution results in \( g(-5) = \frac{-5-2}{-5-5} \). After plugging in the value, it becomes a straightforward arithmetic problem. By solving this, you effectively learn what output the function produces when the input is \( -5 \). Remember, the key part of function evaluation is accurately substituting the given value into every occurrence of the variable.
Numerator and Denominator
In the context of rational functions, understanding the numerator and the denominator is crucial. These are the two components of any fraction where the numerator is the top part and the denominator is the bottom part. For the function \( g(x) = \frac{x-2}{x-5} \), the numerator is \( x - 2 \), and the denominator is \( x - 5 \). When evaluating a function like \( g(-5) \), you calculate each part separately:
- Numerator: Substitute \( x = -5 \), compute \( -5 - 2 = -7 \).
- Denominator: Again substitute \( x = -5 \), compute \( -5 - 5 = -10 \).
Simplifying Fractions
After evaluating a function and obtaining a fraction, simplifying fractions is the next step. This process involves reducing the fraction to its smallest form. In our example, we obtained \( g(-5) = \frac{-7}{-10} \). Simplification checks if the result can be presented in a more readable form. Here, notice that both the numerator and the denominator are negative. When both signs are negative, they cancel each other out, making the fraction positive. Thus, \( \frac{-7}{-10} \) simplifies to \( \frac{7}{10} \).
- Recognize opposite signs in both parts and use the rule that a negative divided by a negative equals a positive.
- Check for common factors (none in this case) to reduce further if possible.
Other exercises in this chapter
Problem 27
Sketch the graph of each function. $$ h(x)=-\sqrt{x}+3 $$
View solution Problem 27
Graph each piecewise-defined function. $$ f(x)=\left\\{\begin{array}{ll} 2 x & \text { if } \quad x
View solution Problem 28
Determine whether each relation is also a function. \(x=y^{2}+2\)
View solution Problem 28
Sketch the graph of each function. $$ f(x)=-\sqrt{x+3} $$
View solution