Problem 28
Question
Graphically show the difference between the given curves. Assume that \(a>0\) and \(b>\) o, $$ \begin{array}{l} x=a \cos \frac{t}{2}, y=a \sin \frac{t}{2}, \quad 0 \leq t \leq \pi \\ x=a \cos \left(-\frac{t}{2}\right), y=a \sin \left(-\frac{t}{2}\right), \quad-\pi \leq t \leq 0 \end{array} $$
Step-by-Step Solution
Verified Answer
The curves represent the top and bottom halves of a circle when combined.
1Step 1: Understand the Parametric Equations
We are given two sets of parametric equations. The first set is \( x = a \cos\left(\frac{t}{2}\right) \) and \( y = a \sin\left(\frac{t}{2}\right) \) with \( 0 \leq t \leq \pi \). The second set is \( x = a \cos\left(-\frac{t}{2}\right) \) and \( y = a \sin\left(-\frac{t}{2}\right) \) with \( -\pi \leq t \leq 0 \). Both equations describe arcs of circles using parameter \( t \).
2Step 2: Simplify the Parametric Equations
Since \(\cos\) and \(\sin\) are even and odd functions respectively, we have:1. \(\cos\left(-\frac{t}{2}\right) = \cos\left(\frac{t}{2}\right)\). 2. \(\sin\left(-\frac{t}{2}\right) = -\sin\left(\frac{t}{2}\right)\).This implies the second set of equations represents a reflection across the x-axis of the curve represented by the first set.
3Step 3: Identify the Shapes of the Curves
Both parametric equations describe semi-circular arcs. For the first equation, as \(t\) varies from 0 to \(\pi\), it forms the upper half of a circle of radius \(a\). For the second equation, as \(t\) varies from \(-\pi\) to 0, it forms the lower half of the same circle (since the x-coordinate is unchanged but the y-coordinate is reflected).
4Step 4: Graph the Curves
To graph both sets of parametric equations, consider a coordinate system where:- The first curve, \( (x, y) = (a \cos\frac{t}{2}, a \sin\frac{t}{2}) \), traces out the upper semi-circle from \((a, 0)\) to \((-a, 0)\).- The second curve, \( (x, y) = (a \cos\frac{t}{2}, -a \sin\frac{t}{2}) \), traces out the lower semi-circle from \((a, 0)\) to \((-a, 0)\).
5Step 5: Visualize the Entire Circle
In conjunction, these curves form a complete circle centered at the origin with radius \(a\). The first set forms the top half from \(x = a\) to \(x = -a\) above the x-axis, and the second set forms the mirrored bottom half of the circle below the x-axis.
Key Concepts
Circular ArcsGraphing CurvesReflection Across the X-axis
Circular Arcs
When we talk about circular arcs drawn using parametric equations, we are discussing segments of a circle, described step by step, as the parameter varies. Here's how it works:
- The circle is positioned in a plane with a fixed radius.
- Using trigonometric functions, we can specify the position along the circle via angle parameters. For example, \(x = a \cos\left(\frac{t}{2}\right)\) and \(y = a \sin\left(\frac{t}{2}\right)\) tell us the x and y positions on the circle based on angle \(t\).
- In the example, as \(t\) moves from \(0\) to \(\pi\), they trace out the top half of the circle, starting and ending at the x-axis.
Graphing Curves
Graphing parametric curves involves plotting points that follow a set of rules to showcase a specific shape. This concept is central for grasping how curves are visualized on a graph. For the circular arcs we've discussed:
- Position the center of your graph at the origin, \( (0,0)\).
- Calculate points incrementally. For instance, with the first equation \(x = a \cos\left(\frac{t}{2}\right)\) and \(y = a \sin\left(\frac{t}{2}\right)\), you plot points where \(0 \leq t \leq \pi\).
- These plots depict, point-by-point, one smooth half of a circle.
Reflection Across the X-axis
Reflection across the x-axis can be thought of as a mirror image of a curve. This concept is evident in our parametric equations. When you follow these steps, you can see the result:
- In the context of parametric equations, modifying the equation for the y-coordinate, such as using negative signs, reflects the curve across the x-axis.
- The second set, \( x = a \cos\left(-\frac{t}{2}\right) \) and \( y = a \sin\left(-\frac{t}{2}\right) \), switches the y direction but keeps x the same. This reflects the curve downwards.
Other exercises in this chapter
Problem 28
Find a polar equation of the parabola with focus at the origin and the given vertex. $$ (2,0) $$
View solution Problem 28
Find polar coordinates that satisfy (a) \(r>0,-\pi
View solution Problem 29
$$ r^{2}=-25 \cos 2 \theta $$
View solution Problem 29
Find a polar equation of the parabola with focus at the origin and the given vertex. $$ \left(\frac{1}{4}, 3 \pi / 2\right) $$
View solution