Problem 28
Question
Given a function \(f(x, y)\) that is defined and differentiable on an open ball containing the point \(\left(x_{0}, y_{0}\right)\), show that the function \(f\) decreases most rapidly in the direction of \(-\nabla f\left(x_{0}, y_{0}\right)\).
Step-by-Step Solution
Verified Answer
The function decreases most rapidly in the direction of \(-\nabla f(x_0, y_0)\), with the rate \(-\|\nabla f(x_0, y_0)\|\).
1Step 1: Understanding the Gradient
The gradient of a function, denoted as \( abla f(x, y) \), is a vector that indicates the direction of the steepest ascent at any point \( (x, y) \). At the point \( (x_0, y_0) \), the gradient \( abla f(x_0, y_0) \) gives us this direction.
2Step 2: Direction for Steepest Descent
The direction in which the function decreases most rapidly is in the opposite direction of the gradient. Therefore, the direction of steepest descent is given by \( -abla f(x_0, y_0) \).
3Step 3: Directional Derivative
The rate of change of the function \( f \) in the direction of a unit vector \( \mathbf{u} \) is given by the directional derivative: \( D_\mathbf{u} f(x, y) = abla f(x, y) \cdot \mathbf{u} \). To find the rate of steepest decrease, we need to evaluate this for \( \mathbf{u} = -\frac{abla f(x_0, y_0)}{\|abla f(x_0, y_0)\|} \), which is the unit vector in the direction of \( -abla f(x_0, y_0) \).
4Step 4: Calculating the Rate of Decrease
Compute the directional derivative in the direction of \( -abla f(x_0, y_0) \): \[ D_{-\mathbf{u}} f(x_0, y_0) = abla f(x_0, y_0) \cdot \left(-\frac{abla f(x_0, y_0)}{\|abla f(x_0, y_0)\|}\right) = -\|abla f(x_0, y_0)\| \]This result shows that the function decreases most rapidly in the direction of \( -abla f(x_0, y_0) \), with the rate of decrease being \(-\|abla f(x_0, y_0)\|\).
5Step 5: Conclusion
The maximum rate of decrease occurs in the direction \( -abla f(x_0, y_0) \), confirming that this is indeed the direction of steepest descent for the function \( f \).
Key Concepts
Differentiable FunctionsDirectional DerivativeSteepest Descent
Differentiable Functions
Differentiable functions are the main players in the world of calculus. Think of them as functions that have a smooth graph without any sharp turns or jumps. This smoothness allows us to talk about derivatives, which are rates of change of the function.
- If a function is differentiable at a point, it must also be continuous at that point.
- The derivative of a function at a certain point gives us the slope of the tangent line at that point.
- In multiple dimensions, we talk about the gradient, which generalizes the idea of a derivative to multidimensional spaces.
Directional Derivative
The directional derivative extends the idea of a derivative in a specified direction. It's like asking: how does my function change if I walk in this particular direction?
- Take a unit vector \( \mathbf{u} \) in the direction you want to measure the change.
- The directional derivative is computed as: \( D_\mathbf{u} f(x, y) = abla f(x, y) \cdot \mathbf{u} \).
- The dot product \( abla f(x, y) \cdot \mathbf{u} \) helps us project the gradient onto the direction of \( \mathbf{u} \).
Steepest Descent
Steepest descent is a concept that's about finding the quickest way down a hill. In mathematical terms, for a function \( f \), it is the direction where \( f \) decreases at the maximum rate.
- This direction is precisely the opposite of where the gradient points, which is \( -abla f(x_0, y_0) \).
- When you compute \( -abla f(x_0, y_0) \), you're effectively flipping the gradient vector.
- The size of this vector, or its magnitude \( \| abla f(x_0, y_0) \| \), tells us how fast the function is decreasing.
Other exercises in this chapter
Problem 28
Find the linear approximation of $$ f(x, y)=\left(x^{2}+y^{2}\right) e^{-\left(x^{2}+y^{2}\right)} $$ at \((0,0)\), and use it to approximate \(f(0.01,0.05) .\)
View solution Problem 28
Choose three numbers \(x, y\), and \(z\) so that their sum is equal to 75 and their product is maximal.
View solution Problem 28
Show that the equilibrium \(\left[\begin{array}{l}0 \\ 0\end{array}\right]\) of $$ \begin{array}{l} x_{1}(t+1)=\frac{3 x_{2}(t)}{2\left(1+\left(x_{1}(t)\right)^
View solution Problem 29
(a) Write $$h(x, y)=e^{x y}$$ as a composition of two functions. (b) For which values of \((x, y)\) is \(h(x, y)\) continuous?
View solution