Problem 28
Question
For Problems \(1-34\), solve each equation. $$ 9^{x}=\frac{1}{27} $$
Step-by-Step Solution
Verified Answer
The solution is \(x = -\frac{3}{2}\).
1Step 1: Recognize Base Relation
Notice that both sides of the equation can be expressed with the same base. Since 9 and 27 are powers of 3, we can rewrite the equation in terms of base 3. Recall that \(9 = 3^2\) and \(27 = 3^3\). Hence, the equation becomes \((3^2)^x = \frac{1}{3^3}\).
2Step 2: Simplify the Equation
Apply the power of a power property \((a^m)^n = a^{mn}\) to the left side of the equation: \((3^2)^x\). This becomes \(3^{2x}\). Apply the negative exponent rule to the right side: \(\frac{1}{3^3} = 3^{-3}\). The equation is now \(3^{2x} = 3^{-3}\).
3Step 3: Set Exponents Equal
Since the bases are the same, we equate the exponents to solve for \(x\). Therefore, we have the equation \(2x = -3\).
4Step 4: Solve for x
To isolate \(x\), divide both sides of the equation by 2: \(x = \frac{-3}{2}\).
Key Concepts
Base ConversionNegative ExponentsPower of a Power
Base Conversion
Understanding base conversion is essential when working with exponential equations, like the one in our exercise. Base conversion often allows us to express numbers in terms of a common base, making them easier to compare or manipulate.
To convert numbers into a common base, we identify a base that both numbers are powers of. In the given problem, both 9 and 27 can be expressed using base 3:
To convert numbers into a common base, we identify a base that both numbers are powers of. In the given problem, both 9 and 27 can be expressed using base 3:
- 9 is the same as \( 3^2 \)
- 27 is the same as \( 3^3 \)
Negative Exponents
Negative exponents represent reciprocals of numbers with positive exponents. This concept is crucial because it allows us to handle fractions in equations more easily.
When you see a negative exponent, it means take the reciprocal of the base raised to the corresponding positive exponent. For example, a negative exponent on the right side of our equation appears as \( \frac{1}{3^3} \), which can be rewritten as \( 3^{-3} \).
Understanding this concept can simplify many algebraic processes:
When you see a negative exponent, it means take the reciprocal of the base raised to the corresponding positive exponent. For example, a negative exponent on the right side of our equation appears as \( \frac{1}{3^3} \), which can be rewritten as \( 3^{-3} \).
Understanding this concept can simplify many algebraic processes:
- If \( a^{-n} = \frac{1}{a^n} \), then rewriting fractions using negative exponents can help you compare or solve equations faster.
- They also allow us to maintain consistency when performing operations on both sides of an equation, as shown by aligning \( 3^{2x} \) on the left with \( 3^{-3} \) on the right.
Power of a Power
The power of a power rule is a fundamental property in exponential equations, which is used extensively in our solution. When you have an expression like \((a^m)^n\), it can be simplified to \(a^{mn}\).
In this problem, the left side of the equation, \((3^2)^x\), can be simplified using the power of a power rule. Applying the rule directly gives \(3^{2x}\).
This property simplifies expressions involving multiple layers of exponents by reducing them to a single exponent. Consider these benefits:
In this problem, the left side of the equation, \((3^2)^x\), can be simplified using the power of a power rule. Applying the rule directly gives \(3^{2x}\).
This property simplifies expressions involving multiple layers of exponents by reducing them to a single exponent. Consider these benefits:
- It reduces the complexity of equations, making them easier to solve.
- This property is particularly useful when aligning exponents after converting bases.
Other exercises in this chapter
Problem 28
For Problems \(21-40\), evaluate each expression. $$ \log _{2} \sqrt[3]{2} $$
View solution Problem 28
Two years ago Daniel invested some money at \(8 \%\) interest compounded annually. Today it is worth $$\$758.16$$. How much did he invest two years ago?
View solution Problem 29
For Problems \(23-32\), approximate each of the following logarithms to three decimal places. $$ \log _{9} 0.0017 $$
View solution Problem 29
For Problems \(21-30\), use your calculator to find each natural logarithm. Express answers to four decimal places. \(\ln 0.0314\)
View solution