Problem 28
Question
For each of these rate laws, state the reaction order with respect to the hypothetical substances \(\mathrm{A}\) and \(\mathrm{B}\), and give the overall order. (a) Rate \(=k[\mathrm{~A}][\mathrm{B}]^{3}\) (b) Rate \(=k[\mathrm{~A}][\mathrm{B}]\) (c) Rate \(=k[\mathrm{~A}]\) (d) Rate \(=k[\mathrm{~A}]^{3}[\mathrm{~B}]\)
Step-by-Step Solution
Verified Answer
(a) A: 1, B: 3, overall: 4; (b) A: 1, B: 1, overall: 2; (c) A: 1, B: 0, overall: 1; (d) A: 3, B: 1, overall: 4.
1Step 1: Identify Reaction Orders for Substance A
For each given rate law, determine the power to which the concentration of substance A, \( [\mathrm{A}] \), is raised. This value corresponds to the order of the reaction with respect to A. (a) Here, \( [\mathrm{A}] \) has a power of 1, so the order with respect to \( \mathrm{A} \) is 1.(b) \( [\mathrm{A}] \) also has a power of 1, making the order with respect to \( \mathrm{A} \) also 1. (c) Again, \( [\mathrm{A}] \) has a power of 1, so the order with respect to \( \mathrm{A} \) is 1.(d) In this case, \( [\mathrm{A}] \) is raised to the power of 3, so the order with respect to \( \mathrm{A} \) is 3.
2Step 2: Identify Reaction Orders for Substance B
Similarly, for each rate law, determine the power to which the concentration of substance B, \( [\mathrm{B}] \), is raised. This value corresponds to the order of the reaction with respect to B.(a) \( [\mathrm{B}] \) is raised to the power of 3, so the order with respect to \( \mathrm{B} \) is 3.(b) \( [\mathrm{B}] \) is raised to the power of 1, making the order with respect to \( \mathrm{B} \) 1.(c) \( [\mathrm{B}] \) does not appear in the rate law, meaning the order with respect to \( \mathrm{B} \) is 0.(d) \( [\mathrm{B}] \) is raised to the power of 1, so the order with respect to \( \mathrm{B} \) is 1.
3Step 3: Calculate the Overall Reaction Order
To find the overall reaction order, add together the order for \( \mathrm{A} \) and the order for \( \mathrm{B} \) for each rate law.(a) The overall order is \(1 + 3 = 4\).(b) The overall order is \(1 + 1 = 2\).(c) The overall order is \(1 + 0 = 1\).(d) The overall order is \(3 + 1 = 4\).
Key Concepts
Rate LawChemical KineticsReaction Rate Expressions
Rate Law
Rate law in chemical reactions describes how the concentration of reactants affects the rate at which a chemical reaction proceeds. It is usually expressed in the form of a mathematical equation that relates the rate of reaction to the concentrations of reactants involved. The general form is:
\[ \text{Rate} = k[A]^m[B]^n \]
where:
\[ \text{Rate} = k[A]^m[B]^n \]
where:
- \( k \) is the rate constant, a proportionality factor that is specific to a particular reaction at a given temperature.
- \([A]\) and \([B]\) are the concentrations of reactants A and B.
- \(m\) and \(n\) represent the orders of the reaction with respect to A and B, respectively.
Chemical Kinetics
Chemical kinetics is the branch of chemistry that deals with understanding the speed or rate of a chemical reaction and the factors that influence this rate. It not only tells us how fast a reaction occurs, but also provides insight into the mechanism by which the reaction proceeds.
Several factors can influence the rate of reaction:
Several factors can influence the rate of reaction:
- Concentration of reactants: Higher concentration often leads to increased reaction rates as there are more particles available to collide and react.
- Temperature: Generally, increasing the temperature raises reaction rates as particles move faster and collide more often with greater energy.
- Presence of a catalyst: Catalysts lower the activation energy required for a reaction, increasing the rate without being consumed in the process.
Reaction Rate Expressions
Reaction rate expressions are mathematical representations that describe how the rate varies with the concentration of the reacting species. They offer a way to quantitatively express the relationship between the reaction rate and the concentrations of the reactants.
For example, given the rate laws from the exercise:
Reaction rate expressions are powerful tools in both theoretical and applied chemistry, providing insights needed in industrial applications, such as the design of reactors and the production of key chemical products.
For example, given the rate laws from the exercise:
- (a) \( \text{Rate} = k[A][B]^3 \)
- (b) \( \text{Rate} = k[A][B] \)
- (c) \( \text{Rate} = k[A] \)
- (d) \( \text{Rate} = k[A]^3[B] \)
Reaction rate expressions are powerful tools in both theoretical and applied chemistry, providing insights needed in industrial applications, such as the design of reactors and the production of key chemical products.
Other exercises in this chapter
Problem 26
For the reaction \(2 \mathrm{NO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{N}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
View solution Problem 27
The transfer of an oxygen atom from \(\mathrm{NO}_{2}\) to CO has been studied at \(540 \mathrm{~K}\) : \(\mathrm{CO}(\mathrm{g})+\mathrm{NO}_{2}(\mathrm{~g}) \
View solution Problem 29
For each of the rate laws below, determine the order of the reaction with respect to the hypothetical substances \(\mathrm{X}, \mathrm{Y},\) and \(\mathrm{Z}\).
View solution Problem 30
A reaction \(\mathrm{A}+\mathrm{B} \longrightarrow\) products is found to be secondorder in B. Which rate equation cannot be correct? (a) Rate \(=k[\mathrm{~A}]
View solution