Problem 28
Question
For a second-order reaction, \(2 \mathrm{~A} \longrightarrow\) Product, a straight line is obtained if we plot (a) concentration vs time (b) log (conc.) vs time (c) log (conc.) vs time \(^{1}\) (d) (concc')vs time"
Step-by-Step Solution
Verified Answer
For a second-order reaction, plot \( \frac{1}{[A]} \) versus time to get a straight line (option d).
1Step 1: Identify Reaction Order
For the given reaction \(2 \text{A} \rightarrow \text{Product}\), it's specified to be a second-order reaction. Second-order reactions have the general form \(A + A \rightarrow \ ext{Products}\).
2Step 2: Understand Rate Law
The rate law for a second-order reaction is generally given by \( \text{Rate} = k[A]^2\), where \(k\) is the rate constant and \([A]\) is the concentration of \(A\).
3Step 3: Derive Integrated Rate Law
For a second-order reaction, the integrated rate law can be expressed as \( \frac{1}{[A]} = kt + \frac{1}{[A]_0}\), where \([A]_0\) is the initial concentration of \(A\).
4Step 4: Determine Linear Plot
The integrated rate law \( \frac{1}{[A]} = kt + \frac{1}{[A]_0} \) suggests that plotting \( \frac{1}{[A]} \) versus time \(t\) will yield a straight line for a second-order reaction. This corresponds to option (d) if \(\text{(conc')} = \frac{1}{[A]}\).
5Step 5: Identify the Correct Plot
Option (d), where \((\text{conc'}) \) represents \( \frac{1}{[A]} \), matches the need for a straight-line plot for second-order reactions when plotted against time.
Key Concepts
Rate lawIntegrated rate lawReaction kineticsConcentration vs time plot
Rate law
In the context of chemical kinetics, the rate law is a mathematical expression that describes the rate of a reaction in terms of the concentration of reactants. For a second-order reaction like the one given, where two molecules of the same species react to form products – represented as \(2 ext{A} \rightarrow \text{Products}\) – the rate law has a particular significance. It is formulated as \( ext{Rate} = k[A]^2 \).
This equation indicates that the reaction rate depends quadratically on the concentration \([A]\) of the reactant. As a result, doubling the concentration of \(A\) quadruples the rate of reaction. This distinct feature of second-order reactions allows for greater insight into how molecular interactions influence reaction speed and progression. The rate constant \(k\) is particularly crucial here, typically influenced by temperature and solvent conditions in which the reaction takes place.
This equation indicates that the reaction rate depends quadratically on the concentration \([A]\) of the reactant. As a result, doubling the concentration of \(A\) quadruples the rate of reaction. This distinct feature of second-order reactions allows for greater insight into how molecular interactions influence reaction speed and progression. The rate constant \(k\) is particularly crucial here, typically influenced by temperature and solvent conditions in which the reaction takes place.
Integrated rate law
The integrated rate law for a second-order reaction provides a relationship between concentration and time as the reaction progresses. For second-order reactions, the integrated rate law is expressed as:\[\frac{1}{[A]} = kt + \frac{1}{[A]_0}\]Here, \([A]_0\) represents the initial concentration of reactant \(A\), and \([A]\) is the concentration of \(A\) at any time \(t\).
- The formula is derived from the basic rate law by integrating over time, providing a clear way to predict reactant concentrations at different time intervals.
- The slope of the plot from this equation reveals the rate constant \(k\), enabling further analysis of the reaction's kinetics.
Reaction kinetics
Reaction kinetics is a fundamental domain in chemistry that studies the rates at which chemical processes occur. This area provides understanding into factors that influence reaction rates, such as concentration, temperature, and catalysts. For any reaction type, including second-order reactions, kinetics involves determining:
- The rate law for the reaction, which mathematically describes the rate.
- The order of the reaction, which tells us how concentration affects reaction rate.
- Activation energy, which indicates the energy barrier that must be overcome for a reaction to occur.
Concentration vs time plot
The relationship between concentration and time is often depicted graphically to interpret the kinetics of a reaction. For second-order reactions, a key strategy for visual analysis is plotting \( \frac{1}{[A]} \) against time \(t\). The formula for the integrated rate law \(\frac{1}{[A]} = kt + \frac{1}{[A]_0}\) implies that this plot should yield a straight line.
- This linear plot indicates that the reaction follows second-order kinetics, where the line's slope equals the rate constant \(k\).
- From this graph, one can easily assess how the concentration of \(A\) decreases more rapidly over time as the reaction progresses.
Other exercises in this chapter
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