Problem 28
Question
Find the midpoint of the line segment connecting the given points. Then show that the midpoint is the same distance from each point. \((2,7),(4,3)\)
Step-by-Step Solution
Verified Answer
The Midpoint of the two points in the given exercise is (3,5) and the distance from each point to the midpoint is \(\sqrt{5}\)
1Step 1: Calculate the Midpoint
The coordinates of our two points are (2,7) and (4,3). We substitute these into the midpoint formula:\n Midpoint = \((\frac{2+4}{2}, \frac{7+3}{2}) = (3,5)\)
2Step 2: Calculate the Distance between Point 1 and the Midpoint
We proceed to calculate the distance between the first point (2,7) and the Midpoint(3,5) using the distance formula:\n Distance = \(\sqrt{(3-2)^2+(5-7)^2} = \sqrt{1+4} = \sqrt{5}\)
Key Concepts
Distance FormulaCoordinate GeometryLine Segments
Distance Formula
The distance formula is a fundamental idea in coordinate geometry. It helps us determine the distance between two points in a coordinate plane. Imagine you have two points, \( (x_1,y_1) \) and \( (x_2,y_2) \), forming a diagonal line when plotted. The distance formula comes from the Pythagorean theorem, which effectively measures straight-line distance.
The formula is:\[Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Here, \( (x_2-x_1) \) represents the horizontal gap, and \( (y_2-y_1) \) the vertical gap. Squaring these differences helps us deal with negative values and get a positive distance. This step-by-step process provides a practical way to find precise distances between any two given points.
The formula is:\[Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Here, \( (x_2-x_1) \) represents the horizontal gap, and \( (y_2-y_1) \) the vertical gap. Squaring these differences helps us deal with negative values and get a positive distance. This step-by-step process provides a practical way to find precise distances between any two given points.
Coordinate Geometry
Coordinate geometry, also called analytic geometry, involves using a coordinate plane to understand and solve geometric problems. While traditional geometry is primarily about shapes and spaces, coordinate geometry gives these visual ideas a numerical basis. This makes it easier to apply algebraic methods.In a coordinate plane, each point has unique coordinates \( (x, y) \). The "x" marks its position relative to the horizontal axis, and the "y" denotes its spot against the vertical axis.
Some of the main tools in coordinate geometry include:
Some of the main tools in coordinate geometry include:
- The distance formula to find the distance between points.
- The midpoint formula to determine the center point of a line segment.
- Equations of lines, which illustrate relationships between points.
Line Segments
Line segments are fundamental components of geometry that define the part of a line bounded by two endpoints. In the context of coordinate geometry, they often link two points and can be analyzed using various formulas, like the distance formula for finding their length.
A line segment has:
A line segment has:
- Endpoints: Where it starts and ends, each defined by coordinates.
- Length: Found using the distance between endpoints.
- Midpoint: Found using the midpoint formula to discover its center.
Other exercises in this chapter
Problem 27
Simplify the expression. $$ \sqrt{18} \cdot \sqrt{5} $$
View solution Problem 27
Solve the equation. $$ \sqrt{5 x+1}+2=6 $$
View solution Problem 28
Graph the points. Determine whether they are vertices of a right triangle. $$ (-1,1),(-3,3),(-7,-1) $$
View solution Problem 28
Find the term that should be added to the expression to create a perfect square trinomial. $$ x^{2}+16 x $$
View solution