Problem 28
Question
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{lll} 1 & 0 & 0 \\ 3 & 0 & 0 \\ 2 & 5 & 5 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The given matrix does not have an inverse because its determinant is equal to zero.
1Step 1: Checking if the matrix has an inverse
A matrix has an inverse only if it's a square matrix and its determinant is non-zero. The given matrix is a square matrix. So, calculate the determinant of the given matrix. The determinant (Det) of a 3x3 matrix: \[Det(A)=a(ei−fh)−b(di−fg)+c(dh−eg)\]By substituting the values of the given matrix into the determinant equation, \( Det = 1*(0*5 - 0*0) - 0*(3*5 - 0*0) + 0*(3*0 - 2*0) = 0 \). The determinant is zero, therefore, the matrix does not have an inverse.
2Step 2: Conclusion
As the determinant of the matrix is zero, we concluded that our matrix does not possess an inverse. Only square matrices with non-zero determinants can have an inverse. Since our matrix does not fulfill that criteria, it drastically simplifies our problem, as there are no further steps necessary.
Key Concepts
Determinant CalculationSquare MatricesInverse Matrix
Determinant Calculation
Calculating the determinant is a critical step in determining if a matrix has an inverse. The determinant is a special number associated with square matrices, and it provides important properties about the matrix. For a 3x3 matrix, the determinant can be found using the following formula:\[Det(A) = a(ei−fh)−b(di−fg)+c(dh−eg)\]This formula involves multiplying and subtracting elements from the matrix systematically.
In essence, for any 3x3 matrix, you'll need to:
In essence, for any 3x3 matrix, you'll need to:
- Take an element from the top row,
- Multiply it by a 2x2 determinant formed by deleting the row and column of the element,
- Repeat the process for each element in the top row, adjusting signs accordingly.
Square Matrices
A square matrix is a matrix with the same number of rows and columns. They are special because only these matrices can potentially have an inverse. The characteristics of square matrices include:
When dealing with matrices, identifying whether you're working with a square matrix is crucial because only these types can offer solutions via the inverse, provided their determinant is non-zero.
- Consistent dimensions, such as 2x2, 3x3, etc.,
- A main diagonal from top left to bottom right.
When dealing with matrices, identifying whether you're working with a square matrix is crucial because only these types can offer solutions via the inverse, provided their determinant is non-zero.
Inverse Matrix
An inverse matrix is essentially a matrix that reverses the effect of the original matrix. To have an inverse, a matrix must be square and its determinant must be non-zero. The process of finding an inverse involves several steps, primarily:
This property of an inverse matrix is used when solving systems of equations, where finding the inverse allows one to find unique solutions to the system by matrix operations.
- Calculate the determinant to ensure the matrix can have an inverse,
- If non-zero, apply techniques such as the adjugate method, paired with dividing by the determinant.
This property of an inverse matrix is used when solving systems of equations, where finding the inverse allows one to find unique solutions to the system by matrix operations.
Other exercises in this chapter
Problem 27
Write the matrix in row-echelon form. (Note: Row-echelon forms are not unique.) $$ \left[\begin{array}{rrrr} 1 & -1 & -1 & 1 \\ 5 & -4 & 1 & 8 \\ -6 & 8 & 18 &
View solution Problem 28
Find all (a) minors and (b) cofactors of the matrix. $$ \left[\begin{array}{rrr} -2 & 9 & 4 \\ 7 & -6 & 0 \\ 6 & 7 & -6 \end{array}\right] $$
View solution Problem 28
Find \(A B\), if possible. $$ A=\left[\begin{array}{rrr} 1 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & -2 \end{array}\right], B=\left[\begin{array}{rrr} 3 & 0 & 0 \\ 0 & -1
View solution Problem 28
Write the matrix in row-echelon form. (Note: Row-echelon forms are not unique.) $$ \left[\begin{array}{rrrr} 1 & -3 & 0 & -7 \\ -3 & 10 & 1 & 23 \\ 1 & 0 & 1 &
View solution