Problem 28
Question
Find the indicated term of each geometric sequence. $$ a_{4}=16, r=0.5, n=8 $$
Step-by-Step Solution
Verified Answer
The 8th term is 1.
1Step 1: Identify the Formula for the nth Term
In a geometric sequence, the nth term is given by the formula: \[ a_n = a_1 imes r^{(n-1)} \] where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number.
2Step 2: Calculate the First Term
We know the 4th term, \( a_4 = 16 \), and \( r = 0.5 \). Using the formula for the nth term, we can calculate the first term \( a_1 \):\[ a_4 = a_1 imes r^{(4-1)} \]\[ 16 = a_1 imes (0.5)^3 \]\[ 16 = a_1 imes 0.125 \]\[ a_1 = \frac{16}{0.125} \]\[ a_1 = 128 \]
3Step 3: Use the Formula to Find the 8th Term
Now that we have \( a_1 = 128 \), we can find the 8th term (\( a_8 \)) using the formula:\[ a_8 = a_1 imes r^{(8-1)} \]\[ a_8 = 128 imes (0.5)^7 \]\[ a_8 = 128 imes 0.0078125 \]\[ a_8 = 1 \]
Key Concepts
Nth Term FormulaCommon RatioFirst Term
Nth Term Formula
When dealing with geometric sequences, one important tool is the formula for the nth term. This formula helps us find any term within the sequence without needing to list every term. The formula is:\[ a_n = a_1 \times r^{(n-1)} \]Where:
- \( a_n \) is the nth term we're trying to find.
- \( a_1 \) is the first term of the sequence.
- \( r \) is the common ratio between consecutive terms.
- \( n \) is the position of the term in the sequence.
Common Ratio
The common ratio is a fundamental feature of geometric sequences. It describes the factor by which we multiply one term to get to the next. In our example, the common ratio \( r \) is given as 0.5.Here's how the common ratio works:
- If the common ratio is greater than 1, the terms in the sequence will grow larger.
- If the common ratio is between 0 and 1, as in this case, the terms will shrink.
- If the common ratio is negative, the sequence will alternate in sign.
First Term
Finding the first term \( a_1 \) is often necessary to solve for other terms in a geometric sequence. In our exercise, the first term was not directly given, so we had to calculate it using the 4th term and the common ratio.To solve for \( a_1 \), we rearrange the nth term formula:Given \( a_4 = 16 \) and \( r = 0.5 \), the formula was:\[ a_4 = a_1 \times r^{(4-1)} \]By isolating \( a_1 \), we find:\[ a_1 = \frac{16}{0.125} = 128 \]The first term acts like a starting point for any geometric sequence. Once it's known, and with knowledge of the common ratio, any subsequent term can be calculated using the nth term formula.
Other exercises in this chapter
Problem 28
Write each repeating decimal as a fraction. \(0 . \overline{7}\)
View solution Problem 28
In the book Roots, author Alex Haley traced his family history back many generations to the time of his ancestors was brought to America from Africa. If you cou
View solution Problem 28
Find the indicated term of each arithmetic sequence. \(a_{1}=-4, d=-9, n=20\)
View solution Problem 28
Find \(a_{1}\) for each arithmetic series described. $$ d=0.5, n=31, S_{31}=573.5 $$
View solution