Problem 28
Question
Find the indefinite integral and check your result by differentiation. $$ \int(5-x) d x $$
Step-by-Step Solution
Verified Answer
The indefinite integral of \(5-x\) is \(5x - \frac{x^2}{2} + C\).
1Step 1: Integration
Take the integral of the function \(5-x\) with respect to \(x\). It's important to remember that the integral of a constant \(c\) is \(cx\) and the integral of \(x^n\) is \(\frac{x^{n+1}}{n+1}\). So, in this case, integrating \(5\) with respect to \(x\) yields \(5x\), and integrating \(-x\) yields \(-\frac{x^2}{2}\). Adding these two results gives the indefinite integral of \(5-x\), which is \(5x - \frac{x^2}{2} + C\), where \(C\) is the constant of integration.
2Step 2: Checking the result by differentiation
Now, differentiate the result of the indefinite integral, which is \(5x - \frac{x^2}{2} + C\), with respect to \(x\). The derivative of \(5x\) is \(5\), the derivative of \(-\frac {x^2}{2}\) is \(-x\) and the derivative of the constant \(C\) is \(0\). Adding these derivatives together gives the original function, \(5 - x\). This verifies that the integral was computed correctly.
Other exercises in this chapter
Problem 28
Use the Log Rule to find the indefinite integral. $$ \int \frac{e^{x}}{1+e^{x}} d x $$
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Find the indefinite integral and check the result by differentiation. $$ \int \frac{t+2 t^{2}}{\sqrt{t}} d t $$
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Use the Trapezoidal Rule with \(n=4\) to approximate the definite integral. $$ \int_{0}^{2} \frac{1}{x+1} d x $$
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Sketch the region bounded by the graphs of the functions and find the area of the region. $$ f(y)=\sqrt{y}, y=9, x=0 $$
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