Problem 28
Question
Find the exact value of the expression. $$ \tan \left(\sin ^{-1} \frac{4}{5}\right) $$
Step-by-Step Solution
Verified Answer
The exact value of \( \tan \left( \sin^{-1} \frac{4}{5} \right) \) is \( \frac{4}{3} \).
1Step 1: Understand the Problem
We need to find the exact value of \( \tan(\sin^{-1}(\frac{4}{5})) \). This involves understanding the relationship between sine, arc sine, and tangent functions.
2Step 2: Use Inverse Sine Definition
Let \( \theta = \sin^{-1}\left(\frac{4}{5}\right) \). It means that \( \sin \theta = \frac{4}{5} \), and we need to find \( \tan \theta \).
3Step 3: Construct a Right Triangle
Construct a right triangle with angle \( \theta \), where the opposite side is 4 (numerator of the sine fraction), and the hypotenuse is 5 (denominator of the sine fraction).
4Step 4: Find the Adjacent Side
Use the Pythagorean theorem \( a^2 + b^2 = c^2 \) to find the adjacent side (\( a \)). Substitute \( a = 4 \) and \( c = 5 \) to get:\[ a^2 + 4^2 = 5^2 \] \[ a^2 + 16 = 25 \] \[ a^2 = 9 \] \[ a = 3 \].
5Step 5: Calculate the Tangent Value
Tangent of angle \( \theta \) is the ratio of the opposite to the adjacent side in the triangle. Thus, \( \tan \theta = \frac{4}{3} \).
6Step 6: Verify Conclusion
Since all steps follow the logic of trigonometry functions, the calculated \( \tan \theta \) value is correct.
Key Concepts
Inverse Trigonometric FunctionsRight Triangle TrigonometryPythagorean Theorem
Inverse Trigonometric Functions
Inverse trigonometric functions allow us to find angles when given a trigonometric ratio. Unlike regular trigonometric functions that give us the ratio from an angle, inverse functions work inversely. They help us decode these ratios back into an angle. These functions include arcsine (\( \sin^{-1} \)), arccosine (\( \cos^{-1} \)), and arctangent (\( \tan^{-1} \)).
When you see something like \( \sin^{-1} \left(\frac{4}{5}\right) \), you are being asked to find the angle whose sine is \( \frac{4}{5} \).
When you see something like \( \sin^{-1} \left(\frac{4}{5}\right) \), you are being asked to find the angle whose sine is \( \frac{4}{5} \).
- The arcsine output is an angle, usually in radians or degrees.
- Arcsine’s range is from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\).
Right Triangle Trigonometry
Right triangle trigonometry involves analyzing triangles where one angle is 90 degrees. This understanding is fundamental to solving many trigonometric problems.
For a given angle in a right triangle:
In our example problem, constructing a right triangle with angle \( \theta \) helps visualize its trigonometric ratios. If \( \sin \theta = \frac{4}{5} \), then the triangle has an opposite side of length 4 and a hypotenuse of length 5. Using these attributes, we can swiftly derive other trigonometric values for that angle.
For a given angle in a right triangle:
- The opposite side is the side opposite the angle.
- The adjacent side is next to the angle and is part of forming it.
- The hypotenuse is the longest side, opposite the right angle.
In our example problem, constructing a right triangle with angle \( \theta \) helps visualize its trigonometric ratios. If \( \sin \theta = \frac{4}{5} \), then the triangle has an opposite side of length 4 and a hypotenuse of length 5. Using these attributes, we can swiftly derive other trigonometric values for that angle.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry used to relate the sides of a right triangle. It states:\[ a^2 + b^2 = c^2 \]where \( a \) and \( b \) are the legs of the triangle, and \( c \) is the hypotenuse.
In our example problem, knowing two sides of the right triangle allows us to calculate the third. For instance, given the opposite side as 4 and the hypotenuse as 5, we can find the adjacent side using:
In our example problem, knowing two sides of the right triangle allows us to calculate the third. For instance, given the opposite side as 4 and the hypotenuse as 5, we can find the adjacent side using:
- \( a^2 + 4^2 = 5^2 \)
- Simplifying gives: \( a^2 + 16 = 25 \)
- Then, \( a^2 = 9 \) and so \( a = 3 \)
Other exercises in this chapter
Problem 27
Evaluate the expression without using a calculator. $$ \sin 30^{\circ} \cos 60^{\circ}+\sin 60^{\circ} \cos 30^{\circ} $$
View solution Problem 27
The measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with the given angle. $$ 50^{\circ}
View solution Problem 28
Find the exact value of the trigonometric function. $$ \tan \frac{5 \pi}{6} $$
View solution Problem 28
Evaluate the expression without using a calculator. $$ \left(\sin 60^{\circ}\right)^{2}+\left(\cos 60^{\circ}\right)^{2} $$
View solution