Problem 28
Question
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots .\) $$ 1,3,5,7,9, \ldots $$
Step-by-Step Solution
Verified Answer
The expression for \(a_n\) is \(a_n = 1 + 2n\).
1Step 1: Observe the sequence
First, observe the given sequence: 1, 3, 5, 7, 9, .... It is an arithmetic sequence where each number increases by a common difference.
2Step 2: Identify the first term and common difference
In this sequence, the first term, denoted as \(a_0\), is 1 and the common difference \(d\) is 2. This is because each term increases by 2 from the previous one.
3Step 3: Use the formula for an arithmetic sequence
The general formula for the \(n\)-th term of an arithmetic sequence is \(a_{n} = a_{0} + n imes d\), where \(a_0\) is the first term and \(d\) is the difference between terms.
4Step 4: Substitute known values into the formula
Substitute \(a_0 = 1\) and \(d = 2\) into the formula: \(a_n = 1 + n imes 2\).
5Step 5: Simplify the expression
Simplify the expression to find the formula for \(a_n\): \[a_n = 1 + 2n\].
Key Concepts
Understanding Common DifferenceAnalyzing the SequenceFinding the Term Formula
Understanding Common Difference
In arithmetic sequences, each term after the first is obtained by adding a constant number to the previous term. This constant is known as the "common difference." The common difference, often denoted by \(d\), is a fundamental part of arithmetic sequences.
The sequence given in the exercise is 1, 3, 5, 7, 9, ... . If we inspect the sequence, each number increases by the same fixed amount. Let's see how this works:
The sequence given in the exercise is 1, 3, 5, 7, 9, ... . If we inspect the sequence, each number increases by the same fixed amount. Let's see how this works:
- The difference between 3 and 1 is 2.
- The difference between 5 and 3 is again 2.
- This pattern continues for the subsequent terms as well.
Analyzing the Sequence
Sequence analysis involves understanding the structure and pattern of a sequence. For arithmetic sequences, like the one given in the exercise, each term is an addition of the common difference to the preceding term.
Analyzing this sequence, 1, 3, 5, 7, 9, ..., we notice:
Analyzing this sequence, 1, 3, 5, 7, 9, ..., we notice:
- The sequence begins at 1, known as the "first term" or \(a_0\).
- Each number is formed by adding 2 to the previous number.
- The sequence grows by this consistent difference \(d\), which is 2.
Finding the Term Formula
Having identified the first term and the common difference, we can derive a formula to find any term in the sequence. This formula is known as the "term formula." It helps us find out the value of the \(n\)-th term directly without having to list all previous terms.
The formula for the \(n\)-th term \(a_n\) in an arithmetic sequence is:
The formula for the \(n\)-th term \(a_n\) in an arithmetic sequence is:
- \( a_n = a_0 + n \times d \)
- The first term \(a_0\) is 1.
- The common difference \(d\) is 2.
- \( a_n = 1 + 2n \)
- \( a_n = 2n + 1 \)
Other exercises in this chapter
Problem 28
Assume that the discrete logistic equation is used with parameters \(R\) and \(K .\) Write the equation in the canonical form \(x_{t+1}=r x_{t}\left(1-x_{t}\rig
View solution Problem 28
Find the recursion for a population that triples in size every unit of time and that has 84 individuals at time \(0 .\)
View solution Problem 29
Assume that the discrete logistic equation is used with parameters \(R\) and \(K .\) Write the equation in the canonical form \(x_{t+1}=r x_{t}\left(1-x_{t}\rig
View solution Problem 29
Find the recursion for a population that quadruples in size everv unit of time and that has 30 individuals at time 0 .
View solution