Problem 28
Question
Find all solutions of the given trigonometric equation if \(x\) is a real number and \(\theta\) is an angle measured in degrees. $$ \sec 2 x=2 $$
Step-by-Step Solution
Verified Answer
All solutions for \( x \) are \( x = 30^\circ + 180^\circ n \) and \( x = 150^\circ + 180^\circ n \) for any integer \( n \).
1Step 1: Rewrite the Equation in Terms of Cosine
Since the secant function is the reciprocal of the cosine function, we can rewrite secant as a cosine. Therefore, the equation \( \sec 2x = 2 \) becomes \( \frac{1}{\cos 2x} = 2 \).
2Step 2: Solve for Cosine Function
Take the reciprocal of both sides to solve for the cosine function. This results in \( \cos 2x = \frac{1}{2} \).
3Step 3: Find General Solutions for Cosine
We know that the cosine of \( 60^\circ \) (or \( \frac{\pi}{3} \) radians) and \( 300^\circ \) (or \( \frac{5\pi}{3} \) radians) is \( \frac{1}{2} \). Therefore, \( 2x = 60^\circ + 360^\circ n \) and \( 2x = 300^\circ + 360^\circ n \), with \( n \) being an integer, capture all possible angles.
4Step 4: Solve for x
Divide all terms in the solution of \( 2x \) by 2 to solve for \( x \). The first solution gives \( x = 30^\circ + 180^\circ n \) and the second solution gives \( x = 150^\circ + 180^\circ n \), where \( n \) is an integer.
5Step 5: Verify the Solutions
Since the solutions are based on trigonometric identities and transformations, verify by putting some values of \( n \) into the solutions for \( x \) and checking if the original equation \( \sec 2x = 2 \) holds true. Due to periodicity, the expressions will satisfy the equation for all integer \( n \).
Key Concepts
Secant FunctionCosine FunctionGeneral Solutions for Trigonometric EquationsPeriodicity in Trigonometry
Secant Function
The secant function, often denoted as \( \sec \theta \), is a fundamental trigonometric function. It is the reciprocal of the cosine function. In mathematical terms, this means that \( \sec \theta = \frac{1}{\cos \theta} \). Understanding this relationship is crucial when solving trigonometric equations involving secant.
- The secant function is undefined where the cosine function is zero. This is because division by zero is not possible.
- Throughout trigonometry, secant is less commonly used compared to sine and cosine but is just as important for its unique properties.
Cosine Function
The cosine function, denoted as \( \cos \theta \), is one of the primary trigonometric functions. It measures the adjacent side over the hypotenuse in a right triangle. When dealing with trigonometric equations, cosine often appears because of its relation to secant.
- Cosine ranges from -1 to 1. This bounded range can help simplify and verify solutions.
- It is a periodic function, repeating itself every \( 360^\circ \) or \( 2\pi \) radians, which makes it consistent over repeated cycles.
General Solutions for Trigonometric Equations
Finding the general solution for a trigonometric equation involves identifying all the possible angles that satisfy the equation. For trigonometric equations like \( \cos 2x = \frac{1}{2} \), there are specific angles, such as \( 60^\circ \) and \( 300^\circ \), known for their cosine values.
- To obtain the general solution, add multiples of the full period of the trig function (360° for cosine) to each specific angle: \( 2x = 60^\circ + 360^\circ n \) and \( 2x = 300^\circ + 360^\circ n \), where \( n \) is an integer.
- This ensures that all possible solutions are captured because the function repeats.
Periodicity in Trigonometry
Periodicity is a core concept in trigonometry, referring to how functions like sine, cosine, and secant repeat their values in regular intervals. For both sine and cosine, this period is \( 360^\circ \) or \( 2\pi \) radians.
- The periodicity allows trigonometric functions to cycle through their range of values consistently, which is why general solutions are possible.
- By utilizing these periods, solutions to equations can be expressed in terms of a single solution plus multiples of the function's period.
Other exercises in this chapter
Problem 28
Find the amplitude and period of the given function. Sketch at least one cycle of the graph. $$ y=\frac{5}{2} \cos 4 x $$
View solution Problem 28
Verify the given identity. $$ \tan ^{2} \beta-\sin ^{2} \beta=\tan ^{2} \beta \sin ^{2} \beta $$
View solution Problem 28
Find the exact value of the given trigonometric expression. Do not use a calculator. $$ \arccos \left(\cos \frac{2 \pi}{3}\right) $$
View solution Problem 28
In Problems \(25-32,\) convert the given angle from degrees to radians. $$ 215^{\circ} $$
View solution