Problem 28
Question
Find a polynomial function \(P(x)\) having leading coefficient \(1,\) least possible degree, real coefficients, and the given zeros. $$1+2 i \text { and } 2 \text { (multiplicity } 2)$$
Step-by-Step Solution
Verified Answer
The polynomial is \(x^4 - 6x^3 + 9x^2 + 4x - 12\).
1Step 1: Identify the Zeros
The given zeros of the polynomial are \(1 + 2i\) and \(2\) with multiplicity 2. Since the polynomial must have real coefficients, the complex conjugate of \(1 + 2i\), which is \(1 - 2i\), should also be a zero.
2Step 2: Construct Linear Factors
Each zero corresponds to a linear factor of the polynomial. For the zero \(1 + 2i\), the factor is \((x - (1 + 2i))\), and for the zero \(1 - 2i\), the factor is \((x - (1 - 2i))\). The zero with multiplicity, 2, corresponds to \((x - 2)^2\). Therefore, the factors of the polynomial are \((x - (1+2i))(x - (1-2i))\) and \((x-2)^2\).
3Step 3: Multiply the Complex Conjugate Factors
Multiply the complex conjugate factors to form a quadratic polynomial with real coefficients. This is done by expanding \[(x - (1 + 2i))(x - (1 - 2i)) = (x - 1 - 2i)(x - 1 + 2i) = ((x - 1)^2 - (2i)^2) = (x - 1)^2 - 4\].Now, expand \((x - 1)^2\) to get:\[(x - 1)^2 = x^2 - 2x + 1\].Substitute back:\[x^2 - 2x + 1 - 4 = x^2 - 2x - 3\].
4Step 4: Multiply with the Factor from the Multiple Root
Now multiply the result from Step 3 by the factor corresponding to the root with multiplicity, \((x - 2)^2\), which expands to \[(x - 2)^2 = x^2 - 4x + 4\]. The polynomial can be found by multiplying \((x^2 - 2x - 3)\) by \((x^2 - 4x + 4)\).
5Step 5: Polynomial Expansion
Perform polynomial multiplication:\[(x^2 - 2x - 3)(x^2 - 4x + 4)\].Distribute all terms:-\((x^2)\cdot(x^2 - 4x + 4) = x^4 - 4x^3 + 4x^2\).-\((-2x)\cdot(x^2 - 4x + 4) = -2x^3 + 8x^2 - 8x\).-\((-3)\cdot(x^2 - 4x + 4) = -3x^2 + 12x - 12\).Sum all these terms:\[x^4 - 4x^3 + 4x^2 - 2x^3 + 8x^2 - 8x - 3x^2 + 12x - 12\].
6Step 6: Combine Like Terms
Combine the same degree terms from the expansion:- \(x^4\) term: \(x^4\)- \(x^3\) terms: \(-4x^3 - 2x^3 = -6x^3\)- \(x^2\) terms: \(4x^2 + 8x^2 - 3x^2 = 9x^2\)- \(x\) terms: \(-8x + 12x = 4x\)- Constant term: \(-12\)The polynomial is \[x^4 - 6x^3 + 9x^2 + 4x - 12\].
7Step 7: Verify the Leading Coefficient
Check that the leading coefficient of the polynomial \(x^4 - 6x^3 + 9x^2 + 4x - 12\) is 1, which matches the requirement in the problem statement.
Key Concepts
Complex ConjugatesMultiplicity of RootsPolynomial ExpansionReal Coefficients
Complex Conjugates
In the world of polynomial functions, complex numbers often come in pairs known as complex conjugates. A complex conjugate is obtained by changing the sign of the imaginary part of a complex number. For example, given a complex number like \(1 + 2i\), its complex conjugate is \(1 - 2i\).
- When working with polynomials that have real coefficients, it is essential that complex roots appear in conjugate pairs. This ensures that when a polynomial is expanded, the imaginary parts cancel out, resulting in a polynomial with real coefficients.
Multiplicity of Roots
Multiplicity refers to how many times a particular root appears in a polynomial. For instance, if the root \(2\) has multiplicity 2, it means that \((x-2)\) is squared in the factorized form of the polynomial.
- Roots with higher multiplicity imply that the polynomial will "touch" its axis at the root but not cross it (for even multiplicity) or will flatten out at that point (for odd multiplicity).
- Including the multiplicity of roots in polynomial expressions reflects crucial information about the behavior and nature of the graph of these functions.
Polynomial Expansion
Polynomial expansion involves transforming a product of factors into a sum or difference of terms. When dealing with polynomials, expansion is the process where each term in each factor is distributed across terms of other factors. This results in a single polynomial expression.
- A typical procedure starts by multiplying linear factors together, like \((x-a)(x-b)\).
- The power of expansion in polynomials allows for simplification and combining like terms, which manifests in the polynomial's simplest form.This also makes further calculus problems (such as finding derivatives) more manageable.
Real Coefficients
Polynomials can have coefficients that are real numbers. Real coefficients are essential in specific scenarios, especially when attempting to ensure that the polynomial's graph is tangible and observable.
- A polynomial with real coefficients will not have terms that result in any unexplainable imaginary graph segments.
- Real coefficients ensure the polynomial functions over real number fields, which is crucial for real-world applications where complex coefficients don't make sense.
Other exercises in this chapter
Problem 27
Find each quotient when \(P(x)\) is divided by the binomial following it. $$P(x)=x^{3}+2 x^{2}-3 ; \quad x-1$$
View solution Problem 27
For each quadratic function defined , (a) use the vertex formula to find the coordinates of the vertex and (b) graph the function. Do not use a calculator. $$y=
View solution Problem 28
Solve each problem. A raised wooden walkway is being constructed through a wetland. The walkway will have the shape of a right triangle with one leg 700 yards l
View solution Problem 28
Write each number in simplest form, without a negative radicand. $$-7+\sqrt{-100}$$
View solution