Problem 28
Question
Exer. 27-44: Find an equation in \(x\) and \(y\) that has the same graph as the polar equation. Use it to help sketch the graph in an \(r \theta\)-plane. $$ r \sin \theta=-2 $$
Step-by-Step Solution
Verified Answer
The Cartesian equation is \( y = -2 \). It's a horizontal line at \( y = -2 \).
1Step 1: Convert Polar Equation to Cartesian Coordinates
The given polar equation is \( r \sin \theta = -2 \). We know that in polar coordinates, \( r \sin \theta = y \). Thus, the equation becomes \( y = -2 \) in Cartesian coordinates.
2Step 2: Identify the Equation Type
The equation \( y = -2 \) represents a horizontal line in the Cartesian coordinate system that is 2 units below the x-axis.
3Step 3: Graph in Cartesian Coordinates
To visualize this, draw a horizontal line that intersects the y-axis at \( y = -2 \). This line extends infinitely in the x-direction.
4Step 4: Sketch the Graph in Polar Coordinates
In the polar coordinate system, the line \( r \sin \theta = -2 \) indicates that for any angle \( \theta \), the distance \( r \) causes the point to remain at a vertical position \( y = -2 \). It's a straight horizontal line at \( y = -2 \) on the Cartesian plane seen through polar perspective.
Key Concepts
Polar CoordinatesCartesian CoordinatesGraphing Equations
Polar Coordinates
Polar coordinates are a way of describing the location of a point based on its distance from a central point, known as the origin, and the angle it makes with a reference direction, typically the positive x-axis. In the polar coordinate system, each point is represented as \(r, \theta\), where \(r\) is the radius or distance from the origin, and \(\theta\) is the angle in radians or degrees.
- The radius \(r\) can be positive or negative. A positive \(r\) indicates movement along the direction of the angle \(\theta\), while a negative \(r\) suggests movement in the opposite direction.
- The angle \(\theta\) is measured counter-clockwise from the positive x-axis.
Cartesian Coordinates
Cartesian coordinates describe a point in a plane using two perpendicular axes that intersect at a point called the origin. These axes are typically labeled the x-axis (horizontal) and the y-axis (vertical). Each point in a Cartesian coordinate system is represented as \(x, y\), where \(x\) denotes the horizontal position and \(y\) denotes the vertical position.In contrast to polar coordinates:
- Coordinates are determined by a grid-like system, making it useful for linear measurement and straightforward calculation of distances and angles.
- In many contexts, Cartesian coordinates are often preferred for their simplicity and ease of visualizing linear relationships.
Graphing Equations
Graphing equations involves plotting points on a coordinate plane to visually represent an equation. This visualization allows for understanding relationships between variables at a glance. In both polar and Cartesian systems, the goal is to present the underlying mathematical relationship in a form that is easy to interpret.For Cartesian coordinates:
- Equations like \(y = mx + b\) (a linear equation) draw straight lines, with \(m\) as the slope and \(b\) as the y-intercept.
- Graphing involves marking points that satisfy the equation and connecting them to reveal the shape of the graph.
- Equations such as \(r = a \; or \; \theta = b\) determine curves based on radii and angles.
- This system is advantageous for capturing spirals and circles through polar equations, leveraging the natural circular symmetry they offer.
Other exercises in this chapter
Problem 27
Exer. 19-30: Find an equation for the ellipse that has its center at the origin and satisfies the given conditions. \(x\)-intercepts \(\pm 2, \quad y\)-intercep
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Exer. 25-32: Find a polar equation of the conic with focus at the pole that has the given eccentricity and equation of directrix. $$ e=3, \quad r=-4 \sec \theta
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Find an equation for the hyperbola that has its center at the origin and satisfies the given conditions. Foci \(F(0, \pm 10)\), asymptotes \(y=\pm \frac{1}{3} x
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Exer. 19-30: Find an equation of the parabola that satisfies the given conditions. Vertex at the origin, symmetric to the \(y\)-axis, and passing through the po
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