Problem 28
Question
Exer. 21-46: Express the complex number in trigonometric form with \(0 \leq \theta<2 \pi\). $$ -10+10 i $$
Step-by-Step Solution
Verified Answer
Trigonometric form: \(10\sqrt{2}(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})\).
1Step 1: Identify the Real and Imaginary Parts
The given complex number is \(-10 + 10i\). Here, the real part (\(a\)) is \(-10\) and the imaginary part (\(b\)) is \(10\).
2Step 2: Calculate the Magnitude
The magnitude \(r\) of a complex number \(a + bi\) is given by \(r = \sqrt{a^2 + b^2}\). Substituting \(a = -10\) and \(b = 10\), we get \[r = \sqrt{(-10)^2 + (10)^2} = \sqrt{100 + 100} = \sqrt{200} = 10\sqrt{2}.\]
3Step 3: Find the Argument
The argument \(\theta\) of the complex number is \(\tan^{-1}\left(\frac{b}{a}\right)\). Here, \(\theta = \tan^{-1}\left(\frac{10}{-10}\right) = \tan^{-1}(-1)\). Since the complex number \(-10 + 10i\) lies in the second quadrant, we add \(\pi\) to the principal value to get \(\theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4}.\)
4Step 4: Write the Trigonometric Form
Using the magnitude and argument, express the complex number in trigonometric form as \[r(\cos \theta + i \sin \theta).\] Substitute \(r = 10\sqrt{2}\) and \(\theta = \frac{3\pi}{4}\) to get \(10\sqrt{2}(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})\).
Key Concepts
Complex NumbersMagnitude of Complex NumbersArgument of Complex NumbersPolar Coordinates
Complex Numbers
Complex numbers are numbers that have both a real part and an imaginary part, typically expressed in the form \(a + bi\), where:
- \(a\) is the real component.
- \(b\) is the imaginary component, paired with the imaginary unit \(i\), satisfying \(i^2 = -1\).
Magnitude of Complex Numbers
The magnitude or modulus of a complex number is a measure of its size or distance from the origin in the complex plane. For a complex number \(a + bi\), the magnitude is calculated using the formula: \[r = \sqrt{a^2 + b^2}\]This value provides the length of the vector representing the complex number. For the given complex number \(-10 + 10i\), the magnitude is calculated as:
- \((-10)^2 = 100\)
- \(10^2 = 100\)
- The sum \(100 + 100 = 200\)
- Taking the square root, \(\sqrt{200} = 10\sqrt{2}\)
Argument of Complex Numbers
The argument of a complex number is the angle that the vector representing the complex number makes with the positive x-axis in the complex plane. It is noted as \(\theta\) and can be calculated using the tangent function: \[\theta = \tan^{-1}\left(\frac{b}{a}\right)\]However, the location of the complex number in the plane (quadrant) also affects the calculation. For \(-10 + 10i\), where \(a = -10\) and \(b = 10\), we first calculate:
- \(\tan^{-1}\left(\frac{10}{-10}\right) = \tan^{-1}(-1)\)
- \(\theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4}\)
Polar Coordinates
Polar coordinates express a complex number in terms of its magnitude (radius) and angle (argument). This is useful for simplifying the multiplication and division of complex numbers, among other computations. The trigonometric form of a complex number is given by:\[r(\cos \theta + i \sin \theta)\]where:
- \(r\) is the magnitude.
- \(\theta\) is the argument.
Other exercises in this chapter
Problem 27
If \(\mathbf{v}=\langle a, b\rangle\), prove that the magnitude of \(2 \mathbf{v}\) is twice the magnitude of \(\mathbf{v}\).
View solution Problem 27
Exer. 21-28: Given that \(a=\langle 2,-3\rangle, \quad b=\langle 3,4\rangle\), and \(c=\langle-1,5\rangle\), find the number. $$ \operatorname{comp}_{\mathrm{b}
View solution Problem 28
Exer. 23-30: Find the solutions of the equation. $$ x^{3}-64 i=0 $$
View solution Problem 28
If \(\mathbf{v}=\langle a, b\rangle\) and \(k\) is any real number, prove that the magnitude of \(k \mathbf{v}\) is \(|k|\) times the magnitude of \(\mathbf{v}\
View solution