Problem 28
Question
Evaluate the expression without using a calculator. $$\left(\sin 60^{\circ}\right)^{2}+\left(\cos 60^{\circ}\right)^{2}$$
Step-by-Step Solution
Verified Answer
The expression evaluates to 1, as confirmed by trigonometric identities.
1Step 1: Know the Trigonometric Values
We need to know the standard trigonometric values. The value of \( \sin 60^{\circ} \) is \( \frac{\sqrt{3}}{2} \) and the value of \( \cos 60^{\circ} \) is \( \frac{1}{2} \).
2Step 2: Square Each Value
Now, square each of the values obtained in Step 1. This means we calculate \((\sin 60^{\circ})^2 = \left(\frac{\sqrt{3}}{2}\right)^2 = \frac{3}{4}\) and \((\cos 60^{\circ})^2 = \left(\frac{1}{2}\right)^2 = \frac{1}{4}\).
3Step 3: Add the Results
Add the squared values obtained in Step 2. So, \( (\sin 60^{\circ})^2 + (\cos 60^{\circ})^2 = \frac{3}{4} + \frac{1}{4} = 1 \).
4Step 4: Verify Using the Pythagorean Identity
According to the Pythagorean identity, for any angle \( \theta \), \( \sin^2 \theta + \cos^2 \theta = 1 \). We've confirmed that this identity holds true for \( 60^{\circ} \), matching our result in Step 3.
Key Concepts
Pythagorean IdentityStandard Trigonometric ValuesAngle EvaluationManual Calculation
Pythagorean Identity
The Pythagorean Identity is one of the most fundamental relationships in trigonometry. It states that for any angle \( \theta \), the square of the sine of \( \theta \) plus the square of the cosine of \( \theta \) is equal to 1. This can be expressed mathematically as:\[\sin^2 \theta + \cos^2 \theta = 1\]This identity is derived from the Pythagorean theorem itself, applicable in a unit circle, where the hypotenuse is equal to the radius, which is 1. Therefore, any point on the unit circle maintains this identity. In our exercise with an angle of 60 degrees, verifying this identity involves confirming that the sum of \( (\sin 60^{\circ})^2 \) and \( (\cos 60^{\circ})^2 \) equals 1. This consistency underpins much of trigonometric analysis in mathematics.
Standard Trigonometric Values
Trigonometric functions such as sine and cosine are periodic and have certain standard values at common angles. These include 0°, 30°, 45°, 60°, and 90° among others. Knowing these values helps in quick evaluations without a calculator. For 60°, the important values are:
- \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \)
- \( \cos 60^{\circ} = \frac{1}{2} \)
Angle Evaluation
When evaluating angles, understanding their positioning and reference angles on the unit circle is crucial. For instance, 60 degrees is located in the first quadrant of the unit circle, where both sine and cosine values are positive. This makes 60° a simple angle for demonstrating basic trigonometric functions. Because trigonometric functions repeat every 360 degrees, knowing values at key benchmarks (like 60°) allows for evaluations of co-terminal angles—those that reach the same point on the circle. Recognizing these positional relationships aids in solving trigonometric problems efficiently.
Manual Calculation
Manual calculations in trigonometry involve methodically applying known formulas and identities without the aid of a calculator. The steps used in the original exercise demonstrate the process:
- Determine standard angle values (e.g., \( \sin 60^{\circ} \), \( \cos 60^{\circ} \)).
- Perform algebraic operations such as squaring these values.
- Add the results to see if they fit known identities like \( \sin^2 \theta + \cos^2 \theta = 1 \).
Other exercises in this chapter
Problem 28
Find the exact value of the expression. $$\tan \left(\sin ^{-1} \frac{4}{5}\right)$$
View solution Problem 28
Use the Law of sines to solve for all possible triangles that satisfy the given conditions. $$b=73, \quad c=82, \quad \angle B=58^{\circ}$$
View solution Problem 28
The measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with the given angle. $$135^{\circ}$
View solution Problem 29
Find the area of the triangle whose sides have the given lengths. \(a=9, \quad b=12, \quad c=15\)
View solution