Problem 28
Question
Dot multiplication is positive definite Show that dot multiplication of vectors is positive definite; that is, show that \(\mathbf{u} \cdot \mathbf{u} \geq \mathbf{0}\) for every vector \(\mathbf{u}\) and that \(\mathbf{u} \cdot \mathbf{u}=0\) if and only if \(\mathbf{u}=\mathbf{0}\)
Step-by-Step Solution
Verified Answer
The dot product \(\mathbf{u} \cdot \mathbf{u}\) is positive definite because it is non-negative and zero only when \(\mathbf{u} = \mathbf{0}\).
1Step 1: Definition of Dot Product
The dot product of a vector \(\mathbf{u} = \begin{bmatrix} u_1 & u_2 & \cdots & u_n \end{bmatrix}^T\) with itself is given by \(\mathbf{u} \cdot \mathbf{u} = u_1^2 + u_2^2 + \cdots + u_n^2\).
2Step 2: Show Non-Negativity
Since each term \(u_i^2\) is a square, it is always non-negative. Thus, \(\mathbf{u} \cdot \mathbf{u} = u_1^2 + u_2^2 + \cdots + u_n^2 \geq 0\) for every vector \(\mathbf{u}\).
3Step 3: Determine Condition for Equality
The equality \(\mathbf{u} \cdot \mathbf{u} = 0\) holds if and only if each term \(u_i^2 = 0\). This implies that \(u_i = 0\) for all \(i\), meaning \(\mathbf{u} = \mathbf{0}\).
4Step 4: Conclusion
Therefore, the dot product \(\mathbf{u} \cdot \mathbf{u}\) is non-negative and equals zero if and only if \(\mathbf{u}\) is the zero vector, confirming that it's positive definite.
Key Concepts
Dot ProductPositive DefiniteVector Analysis
Dot Product
The dot product is a fundamental operation in vector calculus that combines two equal-length sequences of numbers into a single number. Given two vectors \(\mathbf{u} = \begin{bmatrix} u_1 & u_2 & \cdots & u_n \end{bmatrix}^T\) and \(\mathbf{v} = \begin{bmatrix} v_1 & v_2 & \cdots & v_n \end{bmatrix}^T\), the dot product is calculated as:
- \(\mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + \cdots + u_nv_n\)
Positive Definite
A quadratic form (an expression where vectors multiply with each other) is said to be positive definite if the result is always positive, except when the vector itself is zero. Mathematically, for a vector \(\mathbf{u}\), its corresponding quadratic form is positive definite if:
- \(\mathbf{u} \cdot \mathbf{u} \geq 0\)
- \(\mathbf{u} \cdot \mathbf{u} = 0\) if and only if \(\mathbf{u} = \mathbf{0}\)
Vector Analysis
Vector analysis is the branch of mathematics that deals with vectors and vector operators. It is a tool used predominantly in physics and engineering to describe things like force, velocity, and other vector quantities. Key aspects of vector analysis include operations like the dot product and cross product, which facilitate the understanding of the magnitude and directionality of forces and motions in space.
Understanding vector operations is crucial in fields such as electromagnetism, fluid dynamics, and more. The dot product, in particular, can express projections and compute work done, providing insight into how vectors interact within a multidimensional space.
Vector analysis, by using concepts like positive definiteness, helps ensure that mathematical models accurately reflect physical realities—like ensuring forces behave predictably under transformation.
Understanding vector operations is crucial in fields such as electromagnetism, fluid dynamics, and more. The dot product, in particular, can express projections and compute work done, providing insight into how vectors interact within a multidimensional space.
Vector analysis, by using concepts like positive definiteness, helps ensure that mathematical models accurately reflect physical realities—like ensuring forces behave predictably under transformation.
Other exercises in this chapter
Problem 28
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