Problem 28
Question
Determine the common ratio, the fifth term, and the \(n\)th term of the geometric sequence. $$ -8,-2,-\frac{1}{2},-\frac{1}{8}, \dots $$
Step-by-Step Solution
Verified Answer
The common ratio is \( \frac{1}{4} \), the fifth term is \( -\frac{1}{32} \), and the nth term is \( a_n = -8 \cdot \left(\frac{1}{4}\right)^{n-1} \).
1Step 1: Identify the First Term
The first term of the given geometric sequence is the first number in the list: \( a_1 = -8 \).
2Step 2: Determine the Common Ratio
The common ratio \( r \) of a geometric sequence is found by dividing the second term by the first term. Using the terms \(-8\) and \(-2\), calculate \( r = \frac{-2}{-8} = \frac{1}{4} \).
3Step 3: Calculate the Fifth Term
The formula for the \(n\)th term of a geometric sequence is \( a_n = a_1 \cdot r^{n-1} \). To find the fifth term, substitute \( n=5 \), \( a_1 = -8 \), and \( r = \frac{1}{4} \): \[a_5 = -8 \cdot \left(\frac{1}{4}\right)^{4} = -8 \cdot \frac{1}{256} = -\frac{1}{32}.\]
4Step 4: Write the nth Term Formula
Substitute \( a_1 = -8 \) and \( r = \frac{1}{4} \) into the nth term formula \( a_n = a_1 \cdot r^{n-1} \):\[ a_n = -8 \cdot \left(\frac{1}{4}\right)^{n-1}. \]
Key Concepts
Common RatioNth TermFirst TermFifth Term
Common Ratio
The common ratio in a geometric sequence is an important factor that helps determine the relationship between successive terms. In simple terms, it is the number you multiply by each term to get the next one.
In our example sequence,
This means each term is one-fourth of the term before it, indicating the sequence is decreasing.
In our example sequence,
- First term (\(-8\))
- Second term (\(-2\))
This means each term is one-fourth of the term before it, indicating the sequence is decreasing.
Nth Term
Figuring out the nth term in a geometric sequence allows you to calculate the value of any term in the sequence without listing all preceding ones. This is especially helpful for large values of \(n\).
The formula for the nth term is: \(a_n = a_1 \cdot r^{n-1}\). Here, \(a_1\) is the first term, \(r\) is the common ratio, and \(n\) is the term number you are calculating for.
To use the formula effectively:
The formula for the nth term is: \(a_n = a_1 \cdot r^{n-1}\). Here, \(a_1\) is the first term, \(r\) is the common ratio, and \(n\) is the term number you are calculating for.
To use the formula effectively:
- Substitute the first term (\(-8\)) and the ratio (\(\frac{1}{4}\))
- Plug in the value of \(n\)
First Term
The first term of a geometric sequence is crucial as it serves as the starting point for finding any other terms in the series. In our sequence \(-8, -2, -\frac{1}{2}, -\frac{1}{8}, \dots \), the first term is \(a_1 = -8\).
When using the nth term formula, the first term defined as \(a_1\) plays a pivotal role. The sequence builds on this number using the common ratio.
In practical terms, knowing the first term provides a concrete foundation, allowing you to understand the sequence better right from the beginning.
When using the nth term formula, the first term defined as \(a_1\) plays a pivotal role. The sequence builds on this number using the common ratio.
In practical terms, knowing the first term provides a concrete foundation, allowing you to understand the sequence better right from the beginning.
Fifth Term
The fifth term is a specific instance of understanding how to use the nth term formula. Calculating the fifth term showcases how patterns unfold throughout the sequence. Using our formula \(a_n = a_1 \cdot r^{n-1} \) and substituting \(n = 5\):
Understanding this term specifically demonstrates how sequences shrink or grow over a few steps, emphasizing the significance of the common ratio and the pattern it establishes.
- First term (\(a_1 = -8\))
- Common ratio (\(r = \frac{1}{4}\))
Understanding this term specifically demonstrates how sequences shrink or grow over a few steps, emphasizing the significance of the common ratio and the pattern it establishes.
Other exercises in this chapter
Problem 27
Find the \(n\)th term of a sequence whose first several terms are given. \(1, \frac{3}{4}, \frac{5}{9}, \frac{7}{16}, \frac{9}{25}, \dots\)
View solution Problem 28
Find the first three terms in the expansion of $$ \left(x+\frac{1}{x}\right)^{40} $$
View solution Problem 28
Find the \(n\)th term of a sequence whose first several terms are given. \(\frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}, \dots\)
View solution Problem 29
Find the middle term in the expansion of \(\left(x^{2}+1\right)^{18}\)
View solution