Problem 28
Question
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$-8,-2,-\frac{1}{2},-\frac{1}{8}, \dots$$
Step-by-Step Solution
Verified Answer
Common ratio is \( \frac{1}{4} \); fifth term is \(-\frac{1}{32} \); nth term is \( a_n = -8 \left(\frac{1}{4}\right)^{(n-1)} \).
1Step 1: Determine the Common Ratio
In a geometric sequence, each term is obtained by multiplying the previous term by a constant called the common ratio \( r \). To find \( r \), divide the second term by the first term: \[ r = \frac{-2}{-8} = \frac{1}{4}. \] Verify this ratio by checking other consecutive terms: \[ r = \frac{-\frac{1}{2}}{-2} = \frac{1}{4}. \] Thus, the common ratio is \( \frac{1}{4}. \)
2Step 2: Calculate the Fifth Term of the Sequence
To find the fifth term of a geometric sequence, use the formula \( a_n = a_1 \cdot r^{(n-1)} \), where \( a_1 \) is the first term and \( r \) is the common ratio. Here, \( n = 5 \). Therefore, \[ a_5 = -8 \cdot \left(\frac{1}{4}\right)^{5-1} = -8 \cdot \left(\frac{1}{4}\right)^4 = -8 \cdot \frac{1}{256} = -\frac{1}{32}. \] The fifth term is \(-\frac{1}{32}\).
3Step 3: Express the General Formula for the nth Term
The general formula for the \( n \)th term of a geometric sequence is \( a_n = a_1 \cdot r^{(n-1)} \). Substituting the known values, the sequence formula becomes: \[ a_n = -8 \cdot \left(\frac{1}{4}\right)^{(n-1)}. \] This formula can be used to find any term in the sequence.
Key Concepts
Common Rationth Term FormulaSequence Analysis
Common Ratio
In a geometric sequence, understanding the **common ratio** is key because it tells us how each term in the sequence relates to the previous one. Think of the common ratio as the factor you multiply a term by to get the next term in the sequence. For example, if we look at our sequence: -8, -2, -\(\frac{1}{2}\), -\(\frac{1}{8}\), ...We find the common ratio by dividing a term by the one before it. In this case, \[ r = \frac{-2}{-8} = \frac{1}{4}. \]To check our work, let's verify the ratio with other terms:- From \(-2\) to \(-\frac{1}{2}\): \[ r = \frac{-\frac{1}{2}}{-2} = \frac{1}{4}. \]When your ratios are consistent, you've found your common ratio! In this sequence, it's \(\frac{1}{4}\). This consistency confirms that you're following the pattern correctly.
nth Term Formula
Once you know the common ratio, you can find any term in the sequence using the **nth term formula**. The formula is \[ a_n = a_1 \cdot r^{(n-1)} \]where:
- \(a_n\) is the term you want to find,
- \(a_1\) is the first term,
- \(r\) is the common ratio,
- \(n\) is the term number.
Sequence Analysis
**Sequence analysis** involves looking closely at a pattern to understand how it develops. In geometric sequences, the relationship between terms is rooted in multiplication. By analyzing a sequence, you can predict future terms, identify patterns, and even derive the formula. For our sequence, observing the values helps us see:
- Each term is negative, following the negative nature of the first term.
- The terms decrease in absolute value, showing division by the common ratio \(\frac{1}{4}\).
- The sequence representation with the nth term formula: \[ a_n = -8 \cdot \left(\frac{1}{4}\right)^{(n-1)} \]
- By understanding these patterns, we can make informed guesses, computations, and derive meaningful conclusions about the data's behavior in this and similar sequences.
Other exercises in this chapter
Problem 28
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$\frac{7}{6}, \frac{5}{3}, \frac{13}{6}, \f
View solution Problem 28
Find the first three terms in the expansion of $$\left(x+\frac{1}{x}\right)^{40}$$
View solution Problem 28
Find the \(n\) th term of a sequence whose first several terms are given. $$\frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}, \dots$$
View solution Problem 29
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$25,26.5,28,29.5, \dots$$
View solution