Problem 28
Question
Determine the amount of heat (in kJ) given off when \(1.26 \times 10^{4} \mathrm{~g}\) of \(\mathrm{NO}_{2}\) are produced according to the equation $$ \begin{array}{l} 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \\ \qquad \Delta H=-114.6 \mathrm{~kJ} / \mathrm{mol} \end{array} $$
Step-by-Step Solution
Verified Answer
About \(-15686.58\,\text{kJ}\) of heat is released.
1Step 1: Determine the Molar Mass of NO2
To find how much energy is released, first calculate the molar mass of \(\mathrm{NO}_2\). It is calculated by adding the atomic masses: \(14.01\) (for nitrogen) + \(2 \times 16.00\) (for two oxygens) which equals \(46.01\, \text{g/mol}\).
2Step 2: Calculate Moles of NO2 Produced
Next, use the weight of \(\mathrm{NO}_2\) produced, which is \(1.26 \times 10^4 \text{ g}\), to find the moles. Use the formula: \(\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}\). Thus, \[\text{Moles of } \mathrm{NO}_2 = \frac{1.26 \times 10^4 \text{ g}}{46.01 \text{ g/mol}} \approx 273.87 \text{ mol}\].
3Step 3: Calculate Total Energy Change
Since the reaction gives off \(-114.6\,\text{kJ/mol}\) for the formation of \(2\) moles of \(\mathrm{NO}_2\), calculate the total energy released. Thus, for \(273.87\,\text{mol}\) of \(\mathrm{NO}_2\), the energy released is \[\Delta H = \frac{-114.6\,\text{kJ}}{2 \text{ mol}} \times 273.87 \text{ mol} \approx -15686.58 \text{ kJ}\].
4Step 4: Provide Final Answer with Sign Indicating Exothermic Reaction
The energy released when \(1.26 \times 10^4 \text{ g}\) of \(\mathrm{NO}_2\) is produced is approximately \(-15686.58\,\text{kJ}\). The negative sign indicates the reaction is exothermic.
Key Concepts
Molar MassExothermic ReactionEnergy Calculation
Molar Mass
The molar mass of a compound is a fundamental concept when working with chemical equations. Essentially, it tells us how much one mole of a substance weighs in grams. This value is crucial for converting between grams and moles, which are the units most chemical reactions are written in.
To find the molar mass of a compound like nitrogen dioxide (\(\mathrm{NO}_2\), you add up the atomic masses of its constituent atoms. Here, nitrogen contributes an atomic mass of 14.01 grams per mole, and each oxygen atom contributes 16.00 grams per mole. Since there are two oxygen atoms, we calculate the molar mass as:
To find the molar mass of a compound like nitrogen dioxide (\(\mathrm{NO}_2\), you add up the atomic masses of its constituent atoms. Here, nitrogen contributes an atomic mass of 14.01 grams per mole, and each oxygen atom contributes 16.00 grams per mole. Since there are two oxygen atoms, we calculate the molar mass as:
- Nitrogen: 14.01 g/mol
- Oxygen: 2 x 16.00 = 32.00 g/mol
Exothermic Reaction
An exothermic reaction is a chemical reaction that releases energy to its surroundings. This release generally occurs in the form of heat, making the surroundings feel warmer. The energy released during such reactions is represented by a negative enthalpy change, denoted as \(\Delta H\).
In our reaction: \[ 2 \mathrm{NO}(g) + \mathrm{O}_2(g) \rightarrow 2 \mathrm{NO}_2(g) \]The enthalpy change \(\Delta H\) is -114.6 kJ/mol. The negative sign here signifies that energy is released when nitrogen monoxide (NO) reacts with oxygen (\(O_2\)) to form nitrogen dioxide (\(NO_2\)). The energy is released because the products of the reaction (\(\mathrm{NO}_2\)) are at a lower energy state than the reactants (\(\mathrm{NO}\) and \(\mathrm{O}_2\)).
Overall, understanding whether a reaction is exothermic or endothermic (absorbing energy) is essential for predicting energy changes and determining the reaction's impact on its surroundings.
In our reaction: \[ 2 \mathrm{NO}(g) + \mathrm{O}_2(g) \rightarrow 2 \mathrm{NO}_2(g) \]The enthalpy change \(\Delta H\) is -114.6 kJ/mol. The negative sign here signifies that energy is released when nitrogen monoxide (NO) reacts with oxygen (\(O_2\)) to form nitrogen dioxide (\(NO_2\)). The energy is released because the products of the reaction (\(\mathrm{NO}_2\)) are at a lower energy state than the reactants (\(\mathrm{NO}\) and \(\mathrm{O}_2\)).
Overall, understanding whether a reaction is exothermic or endothermic (absorbing energy) is essential for predicting energy changes and determining the reaction's impact on its surroundings.
Energy Calculation
Calculating the energy change in a reaction allows us to understand the extent of energy absorbed or released. When you know the moles of a substance involved, and the energy change per mole, you can compute the total energy released or absorbed.
In this exercise, the reaction between NO and \(\mathrm{O}_2\) to form \(\mathrm{NO}_2\) involves an enthalpy change of \(-114.6\) kJ for every two moles of \(\mathrm{NO}_2\) produced.
To find out the total energy change when \(273.87\) moles of \(\mathrm{NO}_2\) are produced, we use the relation:\[\Delta H = \frac{-114.6\,\text{kJ}}{2 \text{ mol}} \times 273.87 \text{ mol}\]This calculation results in a total energy release of \(-15686.58\,\text{kJ}\). The negative sign indicates the process is exothermic. Such calculations help chemists and engineers predict energy changes in reactions, which is crucial for designing and scaling up chemical processes.
In this exercise, the reaction between NO and \(\mathrm{O}_2\) to form \(\mathrm{NO}_2\) involves an enthalpy change of \(-114.6\) kJ for every two moles of \(\mathrm{NO}_2\) produced.
To find out the total energy change when \(273.87\) moles of \(\mathrm{NO}_2\) are produced, we use the relation:\[\Delta H = \frac{-114.6\,\text{kJ}}{2 \text{ mol}} \times 273.87 \text{ mol}\]This calculation results in a total energy release of \(-15686.58\,\text{kJ}\). The negative sign indicates the process is exothermic. Such calculations help chemists and engineers predict energy changes in reactions, which is crucial for designing and scaling up chemical processes.
Other exercises in this chapter
Problem 26
A gas expands and does \(P V\) work on the surroundings equal to \(325 \mathrm{~J}\). At the same time, it absorbs \(127 \mathrm{~J}\) of heat from the surround
View solution Problem 27
The first step in the industrial recovery of zinc from the zinc sulfide ore is roasting; that is, the conversion of \(\mathrm{ZnS}\) to \(\mathrm{ZnO}\) by heat
View solution Problem 29
Consider the reaction $$\begin{aligned}2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow & 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \\ \Delta H=&+483.6 \mathrm{~kJ} /
View solution Problem 30
Consider the reaction$$\begin{aligned}\mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{HCl}(g) & \\\\\Delta H=-184.6 \mathrm{~kJ} / \mathrm{mol} \
View solution