Problem 28
Question
Describe the set graphed below using interval notation. $$ |4 x-24.8|=32.4 $$
Step-by-Step Solution
Verified Answer
The set in interval notation is \([-1.9, 14.3]\).
1Step 1: Understand the Equation Type
The equation given is an absolute value equation: \(|4x - 24.8| = 32.4\). An absolute value equation \(|A| = B\) means that either \(A = B\) or \(A = -B\). This is because the absolute value of any number is its distance from zero, so it can be either positive or negative.
2Step 2: Set Up Two Equations
Based on the properties of absolute values, the equation \(|4x - 24.8| = 32.4\) can be split into two separate equations:1. \(4x - 24.8 = 32.4\) 2. \(4x - 24.8 = -32.4\)
3Step 3: Solve the First Equation
Solve \(4x - 24.8 = 32.4\) by first adding 24.8 to both sides to isolate the term with \(x\):\[4x = 32.4 + 24.8\]This simplifies to:\[4x = 57.2\]Next, divide both sides by 4 to solve for \(x\):\[x = \frac{57.2}{4}\]\[x = 14.3\]
4Step 4: Solve the Second Equation
Solve \(4x - 24.8 = -32.4\) by first adding 24.8 to both sides:\[4x = -32.4 + 24.8\]This simplifies to:\[4x = -7.6\]Next, divide both sides by 4 to solve for \(x\):\[x = \frac{-7.6}{4}\]\[x = -1.9\]
5Step 5: Write Solution in Interval Notation
Now that we have the solutions \(x = 14.3\) and \(x = -1.9\), these represent the two points between which the set is defined. Thus, the interval in which the solutions exist is \([-1.9, 14.3]\). In interval notation, this is written as a closed interval because the solutions include the endpoints \(-1.9\) and \(14.3\).
Key Concepts
Absolute Value EquationsSolving EquationsInterval Solutions
Absolute Value Equations
Absolute value equations are a fundamental concept in algebra. They involve expressions within absolute value bars, such as \(|4x - 24.8| = 32.4\). The absolute value refers to the distance a number is from zero on the number line, regardless of direction, making it always non-negative. When solving an equation like \(|A| = B\), we need to understand that there are two possibilities:
- Either the expression inside the absolute value equals \(B\), which can be positive,
- or it equals \(-B\), to cover the negative possibility.
Solving Equations
Solving equations involves finding the values of variables that make the equation true. With absolute value equations, this becomes a little more interesting. Once the absolute value expression is understood and broken down into two cases—as either equal to a positive number or a negative number—you must solve each resulting equation independently. Let's look at our example:
- First, solve the equation \(4x - 24.8 = 32.4\).
- Add 24.8 to both sides to isolate the term with \(x\): \(4x = 57.2\).
- Then divide by 4: \(x = 14.3\).
- Next, solve \(4x - 24.8 = -32.4\) similarly by first adding 24.8 to both sides: \(4x = -7.6\).
- Then, divide by 4 to solve for \(x\): \(x = -1.9\).
Interval Solutions
Interval solutions are a way of expressing the range of possible solutions obtained from an equation in a concise manner. After solving an absolute value equation, like \(|4x - 24.8| = 32.4\), you find specific solutions for \(x\) where the expression inside the absolute value equals the given number or its negative counterpart.These solutions define a segment or interval on the number line.
- In our example, we have obtained two solutions: \(x = 14.3\) and \(x = -1.9\).
- These points represent the endpoints of the interval.
- The interval solution is \([-1.9, 14.3]\).
- Expressing this in interval notation, use brackets \([]\) to denote a closed interval, indicating that the endpoints are included in the solution:
Other exercises in this chapter
Problem 27
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. \(2 x-1>3\) and \(x+8 \leq 11\)
View solution Problem 27
Graph each inequality. $$ 3 x \geq-y+3 $$
View solution Problem 28
Graph the solution set of each system of inequalities on a rectangular coordinate system. $$0 \geq x>-4$$
View solution Problem 28
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. \(5 x-3 \geq 2\) and \(6 \geq 4 x-3\)
View solution