Problem 28
Question
Convert the polar equation to rectangular form and sketch its graph. $$ r=-2 $$
Step-by-Step Solution
Verified Answer
The rectangular form of the given equation \(-2\), is \(x^2 + y^2 = 4\), which represents a circle with a radius of 2 centered at the origin. The graph is a circle reflected across the origin.
1Step 1: Convert Polar Equation to a Rectangular Form
Recall that the polar coordinates are related to the rectangular coordinates through the formulas: \(x=r \cos(\theta)\) and \(y=r \sin(\theta)\). The given polar equation is \(r = -2\). Insert this into the equations for the conversion. Since \( r = -2 \), we can replace \( r \) in the conversion formulas directly to get \(x = -2 \cos(\theta)\) and \(y = -2 \sin(\theta)\).
2Step 2: Solving for the Rectangular Coordinate
Although we have equations for x and y, a single equation is needed that relates x and y to draw a graph in rectangular form. Since we know that \(x^2 + y^2 = r^2\) in polar coordinates, substitute \( r = -2 \) into this equation to get \(x^2 + y^2 = (-2)^2 = 4\). This is the equation of a circle centered at the origin with a radius of 2 in rectangular coordinates.
3Step 3: Sketch the Graph
Draw a circle centered at the origin with a radius of 2. Since the initial r-value given was negative, indicating a direction opposite from the usual direction, the actual graph would be the reflection of the circle across the origin.
Other exercises in this chapter
Problem 28
Find the area of the region. Inside \(r=2 a \cos \theta\) and outside \(r=a\)
View solution Problem 28
Find all points (if any) of horizontal and vertical tangency to the curve. Use a graphing utility to confirm your results. $$ x=t^{2}-t+2, \quad y=t^{3}-3 t $$
View solution Problem 29
In Exercises \(27-38,\) find a polar equation for the conic with its focus at the pole. (For convenience, the equation for the directrix is given in rectangular
View solution Problem 29
Conjecture (a) Use a graphing utility to graph the curves represented by the two sets of parametric equations. \(x=4 \cos t \quad x=4 \cos (-t)\) \(y=3 \sin t \
View solution