Problem 28
Question
\(\bullet$$\bullet\) Two unequal charges repel each other with a force \(F .\) If both charges are doubled in magnitude, what will be the new force in terms of \(F ?\)
Step-by-Step Solution
Verified Answer
The new force is \( 4F \).
1Step 1: Identify Given Information
We are given two charges which repel each other with a force \( F \). These charges are unequal, and both charges are doubled.
2Step 2: Recall the Formula for Electrostatic Force
The formula for the force between two charges is given by Coulomb's law: \[ F = k \frac{q_1 q_2}{r^2} \]where \( F \) is the force, \( q_1 \) and \( q_2 \) are the charges, \( r \) is the distance between the charges, and \( k \) is Coulomb's constant.
3Step 3: Determine the Effect of Doubling the Charges
Since both charges are doubled, the new charges are \( 2q_1 \) and \( 2q_2 \). Substitute into Coulomb's law:\[ F' = k \frac{(2q_1)(2q_2)}{r^2} = k \frac{4q_1 q_2}{r^2} \]
4Step 4: Simplify the Expression
The expression for the new force becomes:\[ F' = 4 \left(k \frac{q_1 q_2}{r^2}\right) \]Since \( k \frac{q_1 q_2}{r^2} = F \), the new force \( F' \) is:\[ F' = 4F \]
5Step 5: Conclusion
Doubling each charge results in the force being multiplied by 4.
Key Concepts
Electrostatic ForceChargesCoulomb's Constant
Electrostatic Force
Electrostatic force is the force of attraction or repulsion between electrically charged objects. The strength and direction of this force depend on the nature of the charges and their separation. We use Coulomb's Law to calculate it, given by the equation:
\[ F = k \frac{q_1 q_2}{r^2} \]
This force can either be attractive (if charges are opposite) or repulsive (if charges are similar).
\[ F = k \frac{q_1 q_2}{r^2} \]
This force can either be attractive (if charges are opposite) or repulsive (if charges are similar).
- Attractive Force: When one charge is positive and the other is negative.
- Repulsive Force: When both charges are either positive or both are negative.
Charges
Charges are properties of matter that cause them to experience a force when placed in an electromagnetic field. They come in two types: positive and negative. Each charge influences the other through an invisible field around them. This is known as the electric field.
- Positive Charge: Is typically represented by a plus sign (+).
- Negative Charge: Is represented by a minus sign (-).
- Neutral: When there's no net charge.
Coulomb's Constant
Coulomb's constant, denoted as \( k \), is an essential part of Coulomb's Law. It helps to calculate the force between two point charges. Its value in vacuum is approximately \( 8.99 \times 10^9 \) N m²/C².
- Denotes strength of the electrostatic force.
- A higher constant means a stronger interaction between charges per unit distance.
Other exercises in this chapter
Problem 21
\(\bullet$$\bullet\) Two point charges are located on the \(y\) axis as \(\mathrm{fol}\) lows: charge \(q_{1}=-1.50 \mathrm{nC}\) at \(y=-0.600 \mathrm{m},\) an
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\(\bullet$$\bullet\) Two point charges are placed on the \(x\) axis as follows: Charge \(q_{1}=+4.00 \mathrm{nC}\) is located at \(x=0.200 \mathrm{m},\) and cha
View solution Problem 30
\(\bullet$$\bullet$$\bullet\) A charge \(+Q\) is located at the origin and a second charge, \(+4 Q,\) is at distance \(d\) on the \(x\) -axis. Where should a th
View solution Problem 31
\(\bullet\) A small object carrying a charge of \(-8.00 \mathrm{nC}\) is acted upon by a downward force of 20.0 \(\mathrm{nN}\) when placed at a certain point i
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