Problem 28
Question
(a) Write a chemical equation that illustrates the autoionization of water. (b) Write the expression for the ion-product constant for water, \(K_{w}\). Why is \(\left[\mathrm{H}_{2} \mathrm{O}\right]\) absent from this expression? (c) A solution is described as basic. What does this statement mean?
Step-by-Step Solution
Verified Answer
(a) The chemical equation for the autoionization of water is: \(\mathrm{H_2O} + \mathrm{H_2O} \rightleftharpoons \mathrm{H_3O^+} + \mathrm{OH^-}\).
(b) The ion-product constant for water, \(K_w\), is given by: \(K_w = [\mathrm{H_3O^+}][\mathrm{OH^-}]\). The concentration of water, \([\mathrm{H_2O}]\), is not included in the expression because it is a liquid.
(c) A solution is basic if its pH is greater than 7, meaning the concentration of hydroxide ions (\(\mathrm{OH^-}\)) is greater than the concentration of hydronium ions (\(\mathrm{H_3O^+}\)).
1Step 1: (a) Autoionization of Water Chemical Equation
In the autoionization of water, two water molecules react to form a hydronium ion (\(\mathrm{H_3O^+}\)) and a hydroxide ion (\(\mathrm{OH^-}\)). The chemical equation for this process is:
\[
\mathrm{H_2O} + \mathrm{H_2O} \rightleftharpoons \mathrm{H_3O^+} + \mathrm{OH^-}
\]
2Step 2: (b) Ion-Product Constant for Water
The ion-product constant for water (\(K_w\)) is the equilibrium constant for the autoionization of water. This constant helps us understand the relationship between the concentration of hydronium ions, \([\mathrm{H_3O^+}]\), and hydroxide ions, \([\mathrm{OH^-}]\), in water. The expression for \(K_w\) is:
\[
K_w = [\mathrm{H_3O^+}][\mathrm{OH^-}]
\]
Since water is a liquid, its concentration is not included in the equilibrium constant expression.
3Step 3: (c) Basic Solution Definition
A solution is described as basic if it has a pH greater than 7. This means that the concentration of hydroxide ions (\(\mathrm{OH^-}\)) in the solution is greater than the concentration of hydronium ions (\(\mathrm{H_3O^+}\)). In a basic solution, \(K_w\) remains unchanged; however, the ratio of hydroxide ions to hydronium ions shifts in favor of hydroxide ions.
Key Concepts
Chemical EquilibriumIon-Product ConstantpH Scale
Chemical Equilibrium
Chemical equilibrium is a fundamental concept in chemistry, referring to a state in which reactants and products of a chemical reaction exist at constant levels. This state occurs when the rate of the forward reaction equals the rate of the backward reaction. In the case of the autoionization of water, a constant dynamic equilibrium is established.
The chemical equilibrium for autoionization can be represented by the equation:
In equilibrium, small changes in conditions, such as temperature or pressure, can shift the balance, illustrating the dynamic nature of chemical reactions. Understanding this helps in predicting how changes might affect ion concentrations in water.
The chemical equilibrium for autoionization can be represented by the equation:
- \( \mathrm{2H_2O} \rightleftharpoons \mathrm{H_3O^+} + \mathrm{OH^-} \)
In equilibrium, small changes in conditions, such as temperature or pressure, can shift the balance, illustrating the dynamic nature of chemical reactions. Understanding this helps in predicting how changes might affect ion concentrations in water.
Ion-Product Constant
The ion-product constant, symbolized as \(K_w\), is a special equilibrium constant that applies to the autoionization of water. It reflects the concentrations of hydronium and hydroxide ions in pure water or aqueous solutions.
The equation representing this relationship is:
The reason \([\mathrm{H_2O}]\) is not part of the expression for \(K_w\) is because it is a pure liquid. Pure liquids and solids do not appear in equilibrium constant expressions since their concentrations are constant and negligible compared to the concentrations of gases or solutions.
The equation representing this relationship is:
- \( K_w = [\mathrm{H_3O^+}][\mathrm{OH^-}] \)
The reason \([\mathrm{H_2O}]\) is not part of the expression for \(K_w\) is because it is a pure liquid. Pure liquids and solids do not appear in equilibrium constant expressions since their concentrations are constant and negligible compared to the concentrations of gases or solutions.
pH Scale
The pH scale is an essential tool in understanding acidity and basicity of solutions. It represents how acidic or basic a solution is based on the concentration of hydronium ions.
The equation linking pH with the concentration of hydronium ions is:
In basic solutions, the concentration of hydroxide ions \([\mathrm{OH^-}]\) exceeds that of hydronium ions \([\mathrm{H_3O^+}]\). Despite this shift, the product of these ion concentrations remains constant at the ion-product constant \(K_w\). Knowing the pH can help predict how a solution will interact chemically and the potential impact on chemical reactions involved.
The equation linking pH with the concentration of hydronium ions is:
- \( \text{pH} = -\log[\mathrm{H_3O^+}] \)
In basic solutions, the concentration of hydroxide ions \([\mathrm{OH^-}]\) exceeds that of hydronium ions \([\mathrm{H_3O^+}]\). Despite this shift, the product of these ion concentrations remains constant at the ion-product constant \(K_w\). Knowing the pH can help predict how a solution will interact chemically and the potential impact on chemical reactions involved.
Other exercises in this chapter
Problem 26
Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the equation: (a) \(\mathrm{N
View solution Problem 27
If a neutral solution of water, with \(\mathrm{pH}=7.00\), is heated to \(50^{\circ} \mathrm{C}\), the pH drops to 6.63 . Does this mean that the concentration
View solution Problem 29
Calculate \(\left[\mathrm{H}^{+}\right]\) for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral: (a) \(\left[\math
View solution Problem 30
Calculate \(\left[\mathrm{OH}^{-}\right]\) for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral: (a) \(\left[\mat
View solution