Problem 28
Question
(a) Use a graph of the integrand to make a rough estimate of the integral. Explain your reasoning. (b) Use a computer or calculator to find the value of the definite integral. $$\int_{0}^{1} 3^{t} d t$$
Step-by-Step Solution
Verified Answer
Estimate: 1 to 3, Exact: ~2.186.
1Step 1: Understanding the Integrand
The integrand given is the function \( 3^t \). Since it is an exponential function with base greater than 1, we know that it will be increasing as \( t \) increases from 0 to 1.
2Step 2: Sketching the Graph
Sketch the graph of \( 3^t \) over the interval [0, 1]. At \( t = 0 \), \( 3^0 = 1 \) and at \( t = 1 \), \( 3^1 = 3 \). This means the graph starts at 1 and rises smoothly to 3. The graph is an increasing curve.
3Step 3: Estimating the Area Under the Curve
The area under the curve from \( t = 0 \) to \( t = 1 \) represents the integral. Since the graph is above the line \( y = 1 \) and below \( y = 3 \), a rough estimate of the integral's value is between 1 and 3. We can improve our estimate by considering the curve's upward slope is more rapid near \( t = 1 \). Thus, a reasonable estimate could be closer to 2.
4Step 4: Calculating Using Technology
Use a computer or calculator to find the precise value of the integral: \( \int_{0}^{1} 3^t \, dt \). Inputting this into a calculation tool gives approximately 2.186.
Key Concepts
Exponential FunctionArea Under the CurveGraphing Integrals
Exponential Function
An exponential function is a mathematical expression where the variable is in the exponent. In this case, our function is \( 3^t \). The distinctive trait of an exponential function is its rapid growth. As the base (here, 3) is greater than 1, the function will increase quickly as you move from left to right along the x-axis. For exponential functions:
- The graph will be a smooth curve.
- If the base is greater than 1, like 3, the function grows.
- As \( t \) increases, \( 3^t \) becomes significantly larger.
Area Under the Curve
The definite integral of a function over an interval, such as \( \int_{0}^{1} 3^t \, dt \), represents the area under the function’s curve between two points. In simple terms, it sums up infinitely small rectangles into which the area is divided.For the exponential function \( 3^t \):
- We are interested in the interval from \( t = 0 \) to \( t = 1 \).
- The curve starts at \( y = 1 \) and rises to \( y = 3 \).
- The area under the curve will fall between these two y-values.
Graphing Integrals
Graphing integrals starts with sketching the function described by the integrand. For our function \( 3^t \), the graph forms a curve that helps visualize the area under it. Graphing is invaluable in providing a visual interpretation of the function, making it easier to estimate integrals.When graphing \( 3^t \):
- At \( t = 0 \), the value is 1, and at \( t = 1 \), it equals 3, showing a clear upward trend.
- By plotting these points and smoothly connecting them, you can see how the area accumulates under the curve.
- It helps visually bound the integral's area between our two horizontal lines, \( y = 1 \) and \( y = 3 \).
Other exercises in this chapter
Problem 27
(a) Use a graph of the integrand to make a rough estimate of the integral. Explain your reasoning. (b) Use a computer or calculator to find the value of the def
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