Problem 28
Question
A description of a line is given. Find parametric equations for the line. The line crosses the \(x\) -axis where \(x=-2\) and crosses the \(z\) -axis where \(z=10\) .
Step-by-Step Solution
Verified Answer
The parametric equations are \( x(t) = -2 + 2t \), \( y(t) = 0 \), and \( z(t) = 10t \).
1Step 1: Identify Two Points
The line crosses the x-axis where \( x = -2 \) and the z-axis where \( z = 10 \). This information gives us two points on the line. The point on the x-axis can be written as \((-2, 0, 0)\) since \( y = 0 \) at the x-axis. Similarly, the point on the z-axis is \((0, 0, 10)\) because \( y = 0 \) and \( x = 0 \) on the z-axis.
2Step 2: Determine the Direction Vector
To find the direction vector of the line, subtract the coordinates of the point on the x-axis from the coordinates of the point on the z-axis: \( (0, 0, 10) - (-2, 0, 0) = (2, 0, 10) \). Thus, the direction vector of the line \( \vec{d} \) is \( (2, 0, 10) \).
3Step 3: Write the Parametric Equations
With the point on the x-axis \((-2, 0, 0)\) as the starting point and \( (2, 0, 10) \) as the direction vector, the parametric equations can be written. Let \( t \) be the parameter. The equations are: \( x(t) = -2 + 2t \), \( y(t) = 0 + 0t = 0 \), and \( z(t) = 0 + 10t \).
4Step 4: Verify the Parametric Equations
Substitute \( t = 0 \) into the parametric equations. This gives \( x(0) = -2 \), \( y(0) = 0 \), and \( z(0) = 0 \), which corresponds to the known point on the x-axis. Substituting \( t = 1 \) gives \( x(1) = 0 \), \( y(1) = 0 \), and \( z(1) = 10 \), which matches the known point on the z-axis. Therefore, the calculations are verified.
Key Concepts
Direction Vector3D Coordinate SystemLine Intersections
Direction Vector
In geometry, a direction vector is crucial for defining a line through space. When a line is described in three dimensions, the direction vector indicates the line's magnitude and orientation. This vector is derived by connecting two distinct points that lie on the line. For example, consider two points, \((-2, 0, 0)\) and \( (0, 0, 10)\), on the same line.
The direction vector is calculated by subtracting the coordinates of the starting point from the coordinates of the ending point. In this case:
This direction vector \(\vec{d}\) serves as a directional "arrow" that projects the line forward or backward across the 3D space, guiding us in constructing the line's parametric equations.
The direction vector is calculated by subtracting the coordinates of the starting point from the coordinates of the ending point. In this case:
- Starting point: \((-2,0,0)\)
- Ending point: \( (0,0,10)\)
This direction vector \(\vec{d}\) serves as a directional "arrow" that projects the line forward or backward across the 3D space, guiding us in constructing the line's parametric equations.
3D Coordinate System
The 3D coordinate system is a framework that enables us to conceptualize geometric figures in three-dimensional space. It involves three axes—typically labeled as \(x\), \(y\), and \(z\)—which are perpendicular to each other. Each point in this system is represented by an ordered triplet \( (x, y, z) \) that locates its position in space.
Here's a closer look at how the axes are structured:
Here's a closer look at how the axes are structured:
- \(x\)-axis: This axis runs left to right, and all points on it have their \(y\) and \(z\) coordinates as zero.
- \(y\)-axis: Vertically-oriented, this axis has points with zero \(x\) and \(z\) values.
- \(z\)-axis: Extending in depth, points lying only on the \(z\)-axis have \(x\) and \(y\) coordinates of zero.
Line Intersections
Line intersections in a 3D space refer to the points where lines cross each other or intersect with the coordinate axes. Identifying these intersections requires analyzing the parametric equations of the lines. These intersections provide the exact points where the line meets or crosses another line or plane.
For instance, if a line crosses the \(x\)-axis at \(x = -2\), and the \(z\)-axis at \(z = 10\), it informs us about specific intersection points, namely \((-2, 0, 0)\) and \( (0, 0, 10)\).
For instance, if a line crosses the \(x\)-axis at \(x = -2\), and the \(z\)-axis at \(z = 10\), it informs us about specific intersection points, namely \((-2, 0, 0)\) and \( (0, 0, 10)\).
- The point \((-2, 0, 0)\) indicates that the line intersects the \(x\)-axis when both \(y\) and \(z\) are zero.
- The point \( (0, 0, 10)\) shows intersection with the \(z\)-axis, where \(x\) and \(y\) are zero.
Other exercises in this chapter
Problem 27
\(27-30\) Write the given vector in terms of \(\mathbf{i}\) and \(\mathbf{j}\) . $$ \mathbf{u}=\langle 1,4\rangle $$
View solution Problem 28
Two vectors \(\mathbf{u}\) and \(\mathbf{v}\) are given. Find their dot product \(\mathbf{u} \cdot \mathbf{v} .\) $$ \mathbf{u}=3 \mathbf{j}-2 \mathbf{k}, \quad
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Find the component of \(\mathbf{u}\) along \(\mathbf{v}\) $$ \mathbf{u}=7 \mathbf{i}, \quad \mathbf{v}=8 \mathbf{i}+6 \mathbf{j} $$
View solution Problem 28
Find the area of \(\triangle P Q R\) $$ P(3,-2,6), Q(-1,-4,-6), R(3,4,6) $$
View solution