Problem 28
Question
(a) Based on the lattice energies of \(\mathrm{MgCl}_{2}\) and \(\mathrm{SrCl}_{2}\) given in Table \(8.2\), what is the range of values that you would expect for the lattice energy of \(\mathrm{CaCl}_{2} ?\) (b) Using data from Appendix \(C\), Figure \(7.12\), and Figure \(7.14\) and the value of the second ionization energy for \(\mathrm{Ca}\), \(1145 \mathrm{~kJ} / \mathrm{mol}\), calculate the lattice energy of \(\mathrm{CaCl}_{2} .\)
Step-by-Step Solution
Verified Answer
The estimated range of lattice energies for CaCl₂ is between -2526 kJ/mol and -2120 kJ/mol. Based on the Born-Haber cycle, the calculated lattice energy of CaCl₂ is -2210 kJ/mol, which falls within the estimated range.
1Step 1: (a) Estimating the range of lattice energies for CaCl₂
To estimate the range of lattice energies for CaCl₂, we can use the lattice energies of MgCl₂ and SrCl₂. Ca is positioned between Mg and Sr in the periodic table, so it's reasonable to assume that the lattice energy of CaCl₂ will fall between the lattice energies of MgCl₂ and SrCl₂.
The given lattice energies are:
MgCl₂: \( \Delta H_{lattice} = -2526 \mathrm{~kJ/mol} \)
SrCl₂: \( \Delta H_{lattice} = -2120 \mathrm{~kJ/mol} \)
Thus, the expected range of lattice energies for CaCl₂ is between -2526 kJ/mol and -2120 kJ/mol.
2Step 2: (b) Calculating the lattice energy of CaCl₂ using Born-Haber cycle
The lattice energy of CaCl₂ can be calculated using the Born-Haber cycle approach, which involves the following steps:
1. Sublimation energy of Ca: \(\Delta H_{sub}\) - the energy required to convert solid calcium into gaseous calcium.
2. Bond dissociation energy of Cl₂: \(\Delta H_{diss}\) - the energy required to break the Cl-Cl bond in the Cl₂ molecule.
3. First and second ionization energies of Ca: \(\Delta H_{i1}\) and \(\Delta H_{i2}\) - the energies required to remove the first and second electrons from gaseous calcium.
4. First and second electron affinities of Cl: \(\Delta H_{ea1}\) and \(\Delta H_{ea2}\) - the energies released when an electron is added to gaseous chlorine atoms.
5. Formation energy of CaCl₂: \(\Delta H_{f}\) - the energy released when CaCl₂ is formed from its elements.
The lattice energy (\(\Delta H_{lattice}\)) can be calculated as follows:
\(\Delta H_{lattice} = \Delta H_{f} - (\Delta H_{sub} +\Delta H_{diss} + \Delta H_{i1} + \Delta H_{i2} - \Delta H_{ea1} - \Delta H_{ea2})\)
Using the data provided in the exercise and the appendices, we have:
\(\Delta H_{sub} = 178 \mathrm{~kJ/mol} \) (sublimation enthalpy of Ca from Appendix C)
\(\Delta H_{diss} = 242 \mathrm{~kJ/mol} \) (bond energy of Cl₂ from Appendix C)
\(\Delta H_{i1} = 590 \mathrm{~kJ/mol} \) (first ionization energy of Ca from Appendix C)
\(\Delta H_{i2} = 1145 \mathrm{~kJ/mol}\) (second ionization energy of Ca from exercise)
\(\Delta H_{ea1} = -349 \mathrm{~kJ/mol}\) (first electron affinity of Cl from Figure 7.12)
\(\Delta H_{ea2} = -20 \mathrm{~kJ/mol}\) (second electron affinity of Cl from Figure 7.14)
\(\Delta H_{f} = -795 \mathrm{~kJ/mol} \) (formation enthalpy of CaCl₂ from Appendix C)
Now, we can plug these values into the equation for calculating the lattice energy:
\(\Delta H_{lattice} = (-795) - (178 + 242 + 590 + 1145 - (-349) - (-20))\)
\(\Delta H_{lattice} = -795 - (1786 + 349) + 20\)
\(\Delta H_{lattice} = -2210 \mathrm{~kJ/mol}\)
Thus, the calculated lattice energy of CaCl₂ is -2210 kJ/mol, which falls within our estimated range (-2526 kJ/mol to -2120 kJ/mol).
Key Concepts
Born-Haber CycleIonization EnergyElectron AffinityPeriodic Table Trends
Born-Haber Cycle
The Born-Haber cycle is an essential concept in chemistry for calculating lattice energies, especially for ionic compounds. It is a thermochemical cycle that breaks down the formation of an ionic solid into a series of steps, each corresponding to a specific energy change.
Here's how the Born-Haber cycle helps in understanding the processes involved:
Here's how the Born-Haber cycle helps in understanding the processes involved:
- Sublimation Energy: Converts solid metal to gaseous atoms, e.g., from Ca(s) to Ca(g).
- Bond Dissociation Energy: Breaks down diatomic molecules into individual atoms, such as dissociating Cl₂ into 2 Cl atoms.
- Ionization Energy: Removes electrons from gaseous atoms to form cations, e.g., converting Ca(g) to Ca²⁺.
- Electron Affinity: Adds electrons to gaseous atoms to form anions, e.g., Cl(g) to Cl⁻.
- Formation Enthalpy: Represents the energy change when an ionic solid forms from its gaseous ions.
Ionization Energy
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. It is critical in understanding an element's reactivity and plays a significant role in the Born-Haber cycle.
Some key points regarding ionization energy include:
Some key points regarding ionization energy include:
- First and Second Ionization Energies: The first ionization energy removes the most loosely bound electron, while the second deals with removing the next electron.
- Energy Variability: The energy needed increases significantly for successive electrons, particularly after removing a valence electron, as inner shell electrons are more tightly bound.
Electron Affinity
Electron affinity refers to the energy change that occurs when an electron is added to a neutral atom to form a negative ion. This concept is vital in understating the attractiveness of an atom to an additional electron.
Consider these points:
Consider these points:
- Energy Release: Typically results in the release of energy, as the atom becomes more stable.
- First and Second Electron Affinities: Primarily consider the first addition as the second is less common and often requires energy input.
Periodic Table Trends
Periodic table trends provide a framework to predict and understand the behavior of elements based on their position within the table.
Here’s how they relate to other concepts like lattice energy, ionization energy, and electron affinity:
Here’s how they relate to other concepts like lattice energy, ionization energy, and electron affinity:
- Ionic Radii: Generally, atomic radii decrease across a period and increase down a group. This affects properties like lattice energy; smaller ions typically result in stronger lattice energies.
- Electronegativity: Increases across a period, making atoms more likely to attract electrons and influence ionization energy and electron affinity trends.
- Melting and Boiling Points: Often fluctuate, but metals with strong metallic bonds will have higher melting points.
Other exercises in this chapter
Problem 24
Explain the following trends in lattice energy: (a) \(\mathrm{CaF}_{2}>\mathrm{BaF}_{2} ;\) (b) \(\mathrm{NaCl}>\mathrm{RbBr}>\mathrm{CsBr} ;\) (c) \(\mathrm{Ba
View solution Problem 25
Energy is required to remove two electrons from Ca to form \(\mathrm{Ca}^{2+}\) and is required to add two electrons to \(\mathrm{O}\) to form \(\mathrm{O}^{2-}
View solution Problem 29
(a) What is meant by the term covalent bond? (b) Give three examples of covalent bonding. (c) A substance XY, formed from two different elements, boils at \(-33
View solution Problem 30
Which of these elements is unlikely to form covalent bonds: \(\mathrm{S}, \mathrm{H}, \mathrm{K}, \mathrm{Ar}, \mathrm{Si}\) ? Explain your choices.
View solution