Problem 278
Question
Determine the equation of the hyperbola using the information given. (0, 10), (0, ?10) and eccentricity of 2.5
Step-by-Step Solution
Verified Answer
The equation of the hyperbola is \(\frac{y^2}{100} - \frac{x^2}{525} = 1\).
1Step 1: Identify the Vertices
We are provided with the points \((0, 10)\) and \((0, -10)\) which represent the vertices of the hyperbola. This means the hyperbola is vertical, and its center is at the origin \((0, 0)\). The distance between the center and each vertex is known as \(a\), hence \(a = 10\).
2Step 2: Calculate the Distance from Center to Foci
The eccentricity \(e\) of a hyperbola is given by the formula \(e = \frac{c}{a}\), where \(c\) is the distance from the center to each focus. We have \(e = 2.5\) and \(a = 10\). Solving \(2.5 = \frac{c}{10}\), we find \(c = 2.5 \cdot 10 = 25\).
3Step 3: Use the Relationship Between a, b, and c
For hyperbolas, we have the relationship \(c^2 = a^2 + b^2\). Plugging in our values, \(25^2 = 10^2 + b^2\), or \(625 = 100 + b^2\). Solving for \(b^2\), we get \(b^2 = 525\).
4Step 4: Write the Equation of the Hyperbola
Since the hyperbola is vertical, its standard form is \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\). Substituting \(a^2 = 100\) and \(b^2 = 525\), the equation becomes \(\frac{y^2}{100} - \frac{x^2}{525} = 1\).
Key Concepts
EccentricityVertices of a HyperbolaDistance from Center to FociRelationship Between a, b, and c in Hyperbolas
Eccentricity
The eccentricity (\( e \)) of a hyperbola helps us understand its shape. It's a measure of how much the conic section deviates from being circular. For hyperbolas, \( e \) is always greater than 1.
It is calculated using the formula \( e = \frac{c}{a} \), where \( c \) is the distance from the center to each focus, and \( a \) is the distance from the center to each vertex.
It is calculated using the formula \( e = \frac{c}{a} \), where \( c \) is the distance from the center to each focus, and \( a \) is the distance from the center to each vertex.
- An eccentricity of 2.5 means the hyperbola is fairly elongated.
- If it were closer to 1, the hyperbola would appear less stretched and more rounded.
Vertices of a Hyperbola
Vertices are significant points in a hyperbola, situated along the transverse axis, which is the line passing through these points. In this exercise, the vertices are at \((0, 10)\) and \((0, -10)\).
Since both vertices lie on the y-axis, this hyperbola is vertical.
Identifying the direction (vertical or horizontal) is crucial because it dictates the form of the hyperbola's equation.
The distance from the center to the vertex is denoted as \(a\). Here, \(a = 10\).
Since both vertices lie on the y-axis, this hyperbola is vertical.
Identifying the direction (vertical or horizontal) is crucial because it dictates the form of the hyperbola's equation.
The distance from the center to the vertex is denoted as \(a\). Here, \(a = 10\).
- The main transverse axis length is \(2a = 20\)
- Horizontal orientation would shift the points to the x-axis, but in this case, the y-values are what matter.
Distance from Center to Foci
The foci of a hyperbola are key points lying outside the vertex on the hyperbola's main axis. They are essential for defining the curve.
Using the given eccentricity, \(e = 2.5\), and the formula \(e = \frac{c}{a}\), we calculated that \(c = 25\).
This tells us the foci are \(25\) units away from the center, which invites deeper exploration into the hyperbola's breadth.
Using the given eccentricity, \(e = 2.5\), and the formula \(e = \frac{c}{a}\), we calculated that \(c = 25\).
This tells us the foci are \(25\) units away from the center, which invites deeper exploration into the hyperbola's breadth.
- Foci are located at \((0, 25)\) and \((0, -25)\).
- This placement impacts the hyperbola's openness and stretch.
Relationship Between a, b, and c in Hyperbolas
In hyperbolas, there is an intrinsic mathematical relationship between \(a\), \(b\), and \(c\), given by the equation \(c^2 = a^2 + b^2\).
Here, \(c = 25\), \(a = 10\), and we solve for \(b\). This relationship ensures that all components of the hyperbola are accurately represented.
Solving the equation \(625 = 100 + b^2\), we find that \(b^2 = 525\).
Here, \(c = 25\), \(a = 10\), and we solve for \(b\). This relationship ensures that all components of the hyperbola are accurately represented.
Solving the equation \(625 = 100 + b^2\), we find that \(b^2 = 525\).
- The value of \(b\) holds implications for the hyperbola’s side-to-side stretch (conjugate axis).
- In this context, even though the hyperbola appears vertically oriented, \(b\) tells us about its outward stretch along the x-axis.
Other exercises in this chapter
Problem 273
Determine the equation of the hyperbola using the information given. Endpoints of the conjugate axis located at (0, 3), (0, ?3) and foci located (4, 0), (?4, 0)
View solution Problem 276
Determine the equation of the hyperbola using the information given. Endpoints of the conjugate axis located at (3, 2), (3, 4) and focus located at (3, 7)
View solution Problem 279
Consider the following polar equations of conics. Determine the eccentricity and identify the conic. $$ r=\frac{-1}{1+\cos \theta} $$
View solution Problem 280
Consider the following polar equations of conics. Determine the eccentricity and identify the conic. $$ r=\frac{8}{2-\sin \theta} $$
View solution