Problem 276
Question
In the following exercises, simplify. $$ (3-\sqrt{7})(5-\sqrt{7}) $$
Step-by-Step Solution
Verified Answer
Short answer here
1Step 1: Use the distributive property
To multiply the two binomials, apply the distributive property:
2Step 2: Multiply each term
Multiply each term in the first binomial by each term in the second binomial:
3Step 3: Simplify the expression
Combine like terms to simplify the expression:
Key Concepts
Distributive PropertyMultiplying BinomialsCombining Like Terms
Distributive Property
The distributive property is a key concept in algebra. It's useful when you need to multiply one term by each term in a parenthesis. When you see an expression like \(a(b + c)\), the distributive property lets you rewrite it as \(ab + ac\). This technique helps simplify complex expressions.
For example, when multiplying two binomials, \((3-\sqrt{7})(5-\sqrt{7})\), you first apply the distributive property: you multiply each term in the first binomial by each term in the second binomial.
For example, when multiplying two binomials, \((3-\sqrt{7})(5-\sqrt{7})\), you first apply the distributive property: you multiply each term in the first binomial by each term in the second binomial.
Multiplying Binomials
Multiplying binomials requires using the distributive property twice. It involves four multiplications in total. For the given problem, you multiply each term in the first binomial \((3-\sqrt{7})\) by each term in the second binomial \((5-\sqrt{7})\).
Here's how:
\[ = 3 \cdot 5 + 3 \cdot (-\sqrt{7}) + (-\sqrt{7}) \cdot 5 + (-\sqrt{7}) \cdot (-\sqrt{7}) \]
Breaking it down step-by-step makes it manageable:
This exercise uses multiplication rules straightforwardly, contributing to simpler expressions.
Here's how:
\[ = 3 \cdot 5 + 3 \cdot (-\sqrt{7}) + (-\sqrt{7}) \cdot 5 + (-\sqrt{7}) \cdot (-\sqrt{7}) \]
Breaking it down step-by-step makes it manageable:
- First multiply 3 and 5 to get 15.
- Then multiply 3 and \(-\sqrt{7}\) to get \-3\sqrt{7}\.
- After that, multiply \(-\sqrt{7}\) and 5 to get \-5\sqrt{7}\.
This exercise uses multiplication rules straightforwardly, contributing to simpler expressions.
Combining Like Terms
After multiplying out the binomials, the next step is to combine like terms. Like terms have the same variables raised to the same power. In this case, combining like terms simplifies your expression.
From the previous section, we had \[15 - 3\sqrt{7} - 5\sqrt{7} +(\sqrt{7})^2 \]
This makes your final simplified expression \[ = 22 - 8\sqrt{7} \]. Taking many steps makes the expression clearer and simpler.
From the previous section, we had \[15 - 3\sqrt{7} - 5\sqrt{7} +(\sqrt{7})^2 \]
- First, notice that \(\sqrt{7} \cdot \sqrt{7} \) simplifies to \ 7\.
- Adding these gives \[15 - 3\sqrt{7} - 5\sqrt{7} + 7 \].
- Then, combine the constant terms 15 and 7 to get 22.
- Lastly, simplify \(- 3 + (- 5) = - 8\sqrt{7} \).
This makes your final simplified expression \[ = 22 - 8\sqrt{7} \]. Taking many steps makes the expression clearer and simpler.
Other exercises in this chapter
Problem 274
In the following exercises, simplify. $$ (8-\sqrt{2})(3+\sqrt{2}) $$
View solution Problem 275
In the following exercises, simplify. $$ (9-\sqrt{2})(6+\sqrt{2}) $$
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In the following exercises, simplify. $$ (5-\sqrt{7})(4-\sqrt{7}) $$
View solution Problem 278
In the following exercises, simplify. $$ (1+3 \sqrt{10})(5-2 \sqrt{10}) $$
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