Problem 27
Question
Write each expression as a single logarithm. \(\log _{10} y-2 \log _{10}(y-1)\)
Step-by-Step Solution
Verified Answer
\( \log_{10} \left( \frac{y}{(y-1)^2} \right) \)
1Step 1: Apply Logarithm Power Rule
The expression given is \( \log_{10} y - 2 \log_{10} (y-1) \). The logarithm power rule states that \( a \log_b x = \log_b (x^a) \). Therefore, we can rewrite the second term as \( \log_{10} ((y-1)^2) \). This simplifies the expression to \( \log_{10} y - \log_{10} ((y-1)^2) \).
2Step 2: Use Logarithm Quotient Rule
The logarithm quotient rule tells us that \( \log_b a - \log_b c = \log_b \left(\frac{a}{c}\right) \). Applying this to our expression \( \log_{10} y - \log_{10} ((y-1)^2) \), we get \( \log_{10} \left( \frac{y}{(y-1)^2} \right) \).
Key Concepts
Logarithm Power RuleLogarithm Quotient RuleSimplifying Logarithmic Expressions
Logarithm Power Rule
Understanding the logarithm power rule can simplify many logarithmic expressions, and it's especially useful when dealing with exponential factors. The rule states that for any logarithm \( a \log_b x \), you can convert the expression to \( \log_b (x^a) \). Here, the coefficient becomes the exponent.
📌 **For example:**
📌 **For example:**
- Given an expression like \( 2 \log_{10}(y-1) \), apply the power rule to rewrite it as \( \log_{10}((y-1)^2) \).
Logarithm Quotient Rule
After applying the power rule, you might find yourself with expressions that subtract one logarithm from another. This is where the logarithm quotient rule comes in handy.
The quotient rule states that \( \log_b a - \log_b c = \log_b \left(\frac{a}{c}\right) \). This effectively converts a subtraction into the division inside a logarithm.
📌 **For example:**
The quotient rule states that \( \log_b a - \log_b c = \log_b \left(\frac{a}{c}\right) \). This effectively converts a subtraction into the division inside a logarithm.
📌 **For example:**
- Consider the expression \( \log_{10} y - \log_{10} ((y-1)^2) \). By the quotient rule, it transforms into \( \log_{10} \left( \frac{y}{(y-1)^2} \right) \).
Simplifying Logarithmic Expressions
Combining logarithm rules helps to condense expressions into simpler forms. Practicing this process increases familiarity with these transformations and aids in solving complex problems.
To simplify a logarithmic expression:
The expression \( \log_{10} y - 2 \log_{10}(y-1) \) beautifully illustrates this method by transforming into \( \log_{10} \left( \frac{y}{(y-1)^2} \right) \). Mastering these rules equips you with the ability to tackle any logarithmic challenge efficiently.
To simplify a logarithmic expression:
- Apply the power rule first to express any coefficients as exponents.
- Next, use the quotient rule or other relevant rules to combine terms.
The expression \( \log_{10} y - 2 \log_{10}(y-1) \) beautifully illustrates this method by transforming into \( \log_{10} \left( \frac{y}{(y-1)^2} \right) \). Mastering these rules equips you with the ability to tackle any logarithmic challenge efficiently.
Other exercises in this chapter
Problem 27
In \(24-35,\) for each given logarithm, find the antilogarithm, \(x .\) Write the answer to four decimal places. $$ \log x=1.7790 $$
View solution Problem 27
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ \log _{8} 8 $$
View solution Problem 28
In \(21-32,\) for each given logarithm, find \(x,\) the antilogarithm. Write the answer to four decimal places. $$ \ln x=-0.5373 $$
View solution Problem 28
In \(24-35,\) for each given logarithm, find the antilogarithm, \(x .\) Write the answer to four decimal places. $$ \log x=2.2030 $$
View solution