Problem 27
Question
Write each complex number in rectangular form. $$ 4 e^{i \frac{7 \pi}{4}} $$
Step-by-Step Solution
Verified Answer
The rectangular form is 2\( \sqrt{2} \) - 2i\( \sqrt{2} \).
1Step 1 - Understand Euler's Formula
Euler's formula states that any complex number in exponential form can be written as \[ z = re^{iθ} = r(\text{cos}(θ) + i \text{sin}(θ)) \] where \( r \) is the magnitude and \( θ \) is the angle.
2Step 2 - Identify the Magnitude and Angle
For the given complex number \( 4 e^{i \frac{7 \frac{7 \text{π} }{4}}} \), the magnitude is 4 and the angle is \( \frac{7 \text{π} }{4} \).
3Step 3 - Apply Trigonometric Functions
Using the magnitude and angle in Euler's formula, we get: \[ 4 (\text{cos}( \frac{7 \text{π} }{4}) + i \text{sin} ( \frac{7 \text{π} }{4} ))\]
4Step 4 - Find the Cosine and Sine Values
Calculate \(\text{cos} ( \frac{7 \text{π} }{4} )= \text{cos} ( - \frac{ \text{π} }{4} ) = \frac { \text{√2} }{2} \) and \( \text{sin} ( \frac{7 \text{π} }{4} ) = \text{sin} (- \frac{ \text{π} }{4} ) = - \frac { \text{√2} }{2} \).
5Step 5 - Substitute the Values
Now substitute the cosine and sine values into the equation: \[ 4 \times ( \frac { \text{√2} }{2} +i - \frac { \text{√2} }{2} ) \].
6Step 6 - Simplify
Simplify the expression to get the rectangular form: \[ 4 \times \frac { \text{√2} }{2} + 4 \times ( -i \frac { \text{√2} }{2}) = 2 \text{√2} - 2 i \text{√2} \].
Key Concepts
Euler's FormulaTrigonometric FunctionsMagnitude and Angle
Euler's Formula
Euler's formula is a key concept in understanding complex numbers in exponential form. It states that any complex number can be expressed as \[ z = re^{iθ} = r(\text{cos}(θ) + i \text{sin}(θ)) \]
- \( r \) is the magnitude of the complex number.
- \( θ \) is the angle or argument of the complex number.
Trigonometric Functions
Trigonometric functions play a crucial role when converting a complex number from its exponential form to its rectangular form. In this context, you'll frequently use the cosine and sine functions from Euler's formula: \( \text{cos}(θ) \) and \( \text{sin}(θ) \) .
\[ \text{cos}( \frac{7\text{π}}{4} ) = \text{cos}( - \frac{\text{π}}{4} ) = \frac{ \text{√2} }{2} \]
and
\[ \text{sin}( \frac{7\text{π}}{4} ) = \text{sin}( - \frac{\text{π}}{4} ) = - \frac{ \text{√2} }{2} \] . These values are then used to convert the given complex number to its rectangular form.
- The cosine function gives the real part.
- The sine function gives the imaginary part.
\[ \text{cos}( \frac{7\text{π}}{4} ) = \text{cos}( - \frac{\text{π}}{4} ) = \frac{ \text{√2} }{2} \]
and
\[ \text{sin}( \frac{7\text{π}}{4} ) = \text{sin}( - \frac{\text{π}}{4} ) = - \frac{ \text{√2} }{2} \] . These values are then used to convert the given complex number to its rectangular form.
Magnitude and Angle
Understanding the magnitude and angle is vital when working with complex numbers in exponential form.
\[ 4 (\text{cos}( \frac{7 \text{π}}{4}) + i \text{sin}( \frac{7 \text{π}}{4} )) \] .By substituting the trigonometric values computed earlier, we find:
\[ 4 \bigg( \frac{ \text{√2} }{2} - i \frac{ \text{√2} }{2} \bigg) = 2 \text{√2} - 2i \text{√2} \] .Thus, the rectangular form of the complex number is \( 2 \text{√2} - 2i \text{√2} \).
- The magnitude \( r \) is the distance from the origin to the point on the complex plane.
- The angle \( θ \) (also known as the argument) indicates the direction of the point relative to the positive real axis.
- The magnitude \( r = 4 \).
- The angle \( θ = \frac{7 \text{π}}{4} \).
\[ 4 (\text{cos}( \frac{7 \text{π}}{4}) + i \text{sin}( \frac{7 \text{π}}{4} )) \] .By substituting the trigonometric values computed earlier, we find:
\[ 4 \bigg( \frac{ \text{√2} }{2} - i \frac{ \text{√2} }{2} \bigg) = 2 \text{√2} - 2i \text{√2} \] .Thus, the rectangular form of the complex number is \( 2 \text{√2} - 2i \text{√2} \).
Other exercises in this chapter
Problem 27
Find a vector of magnitude 15 that is parallel to \(4 \mathbf{i}-3 \mathbf{j}\)
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The vector \(\mathbf{v}\) has initial point \(P\) and terminal point \(Q .\) Find its position vector. That is, express \(\mathbf{v}\) in the form \(a \mathbf{i
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Find a vector of magnitude 5 that is parallel to \(-12 \mathbf{i}+9 \mathbf{j}\)
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The vector \(\mathbf{v}\) has initial point \(P\) and terminal point \(Q .\) Find its position vector. That is, express \(\mathbf{v}\) in the form \(a \mathbf{i
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