Problem 27
Question
Use the properties of logarithms to write the expression as a single logarithm. $$ \log _{2}(x)+\log _{4}(x) $$
Step-by-Step Solution
Verified Answer
The expression is \( \log_2(x^{3/2}) \).
1Step 1: Convert Base of Logarithms
To combine the logarithms, they need to have the same base. Use the change of base formula to convert \( \log_4(x) \) to base 2. Recall that the change of base formula is \( \log_b(a) = \frac{\log_c(a)}{\log_c(b)} \). So, \( \log_4(x) = \frac{\log_2(x)}{\log_2(4)} \). Since \( 4 = 2^2 \), \( \log_2(4) = 2 \). Therefore, \( \log_4(x) = \frac{\log_2(x)}{2} \).
2Step 2: Combine the Logarithms
Now that both logarithms have the same base, \( \log_2 \), they can be combined using the properties of logarithms. Specifically, \( \log_b(a) + \log_b(c) = \log_b(a \times c) \). So, we have \[ \log_2(x) + \frac{\log_2(x)}{2} = \frac{2\log_2(x)}{2} + \frac{\log_2(x)}{2} = \frac{3\log_2(x)}{2}. \]
3Step 3: Express as a Single Logarithm
The expression \( \frac{3\log_2(x)}{2} \) can be written as a single logarithm using the power rule of logarithms: \( a\log_b(c) = \log_b(c^a) \). Thus, \( \frac{3\log_2(x)}{2} = \log_2(x^{3/2}) \).
Key Concepts
Change of Base FormulaCombining LogarithmsPower Rule of Logarithms
Change of Base Formula
The change of base formula is a handy tool that allows you to convert a logarithm from one base to another. Imagine you're trying to read a recipe in a foreign language; the change of base formula is like a translation that helps you understand. The formula is given by:
\[\log_b(a) = \frac{\log_c(a)}{\log_c(b)}\]Here, you can change the logarithm of a number with base \(b\) to any new base \(c\). In the original exercise, we used this formula to convert \( \log_4(x)\) into a logarithm with base 2.
\[\log_b(a) = \frac{\log_c(a)}{\log_c(b)}\]Here, you can change the logarithm of a number with base \(b\) to any new base \(c\). In the original exercise, we used this formula to convert \( \log_4(x)\) into a logarithm with base 2.
- First, we needed \( \log_2(4) \). We noticed that 4 is the same as \( 2^2 \), so \( \log_2(4) = 2 \).
- The change of base formula helped us rewrite \( \log_4(x) \) as \( \frac{\log_2(x)}{2} \).
Combining Logarithms
Once you have logarithms with identical bases, you can combine them much more easily. In math, this is like having all your ingredients ready before cooking a meal—it makes the process smoother. The property used is:
\[ \log_b(a) + \log_b(c) = \log_b(a \times c) \]In our example, after converting \( \log_4(x) \) to base 2, we had:
\[\frac{2\log_2(x)}{2} + \frac{\log_2(x)}{2} = \frac{3\log_2(x)}{2}\]This combined expression re-arranges and simplifies the elements into a single entity, setting the stage for our final transformation.
\[ \log_b(a) + \log_b(c) = \log_b(a \times c) \]In our example, after converting \( \log_4(x) \) to base 2, we had:
- \( \log_2(x) + \frac{\log_2(x)}{2} \)
\[\frac{2\log_2(x)}{2} + \frac{\log_2(x)}{2} = \frac{3\log_2(x)}{2}\]This combined expression re-arranges and simplifies the elements into a single entity, setting the stage for our final transformation.
Power Rule of Logarithms
The power rule of logarithms is like a magical transformation that allows us to write multiplied logarithms as just one beautiful expression. It says:
\[ a\log_b(c) = \log_b(c^a) \]This rule enables us to bring any coefficients or factors within the logarithm itself. In our case, we had:
\( \frac{3\log_2(x)}{2} \)
\[ a\log_b(c) = \log_b(c^a) \]This rule enables us to bring any coefficients or factors within the logarithm itself. In our case, we had:
\( \frac{3\log_2(x)}{2} \)
- The power rule lets us move the \(\frac{3}{2}\) out of the front, and into the power position: \( \log_2(x^{3/2}) \).
Other exercises in this chapter
Problem 27
Solve the inequality analytically. $$ 10 \log \left(\frac{x}{10^{-12}}\right) \geq 90 $$
View solution Problem 27
In Exercises \(1-33,\) solve the equation analytically. $$ 7^{3+7 x}=3^{4-2 x} $$
View solution Problem 27
Evaluate the expression. \(\ln \left(e^{3}\right)\)
View solution Problem 28
Solve the inequality analytically. $$ 5.6 \leq \log \left(\frac{x}{10^{-3}}\right) \leq 7.1 $$
View solution