Problem 27
Question
Use the Laws of Logarithms to expand the expression. $$ \log \left(\frac{x^{3} y^{4}}{z^{6}}\right) $$
Step-by-Step Solution
Verified Answer
The expanded expression is \( 3\log(x) + 4\log(y) - 6\log(z) \).
1Step 1: Apply the Quotient Rule of Logarithms
Using the quotient rule of logarithms, which states that \( \log\left(\frac{a}{b}\right) = \log(a) - \log(b) \), we can apply this rule to the expression: \( \log \left(\frac{x^{3} y^{4}}{z^{6}}\right) = \log(x^{3} y^{4}) - \log(z^{6}) \).
2Step 2: Apply the Product Rule of Logarithms
Next, use the product rule of logarithms, which states that \( \log(ab) = \log(a) + \log(b) \). Apply this rule to the expression inside the logarithm from Step 1. This gives: \( \log(x^{3} y^{4}) = \log(x^{3}) + \log(y^{4}) \).
3Step 3: Apply the Power Rule of Logarithms
Now apply the power rule of logarithms, which states that \( \log(a^{b}) = b \cdot \log(a) \). Apply this rule to each term in the expression: \( \log(x^{3}) = 3 \cdot \log(x) \) and \( \log(y^{4}) = 4 \cdot \log(y) \). Also, \( \log(z^{6}) = 6 \cdot \log(z) \).
4Step 4: Combine the Expanded Terms
Putting all the expanded terms together, we have: \( 3 \cdot \log(x) + 4 \cdot \log(y) - 6 \cdot \log(z) \). Thus, the expanded expression is: \( 3 \log(x) + 4 \log(y) - 6 \log(z) \).
Key Concepts
Quotient Rule of LogarithmsProduct Rule of LogarithmsPower Rule of Logarithms
Quotient Rule of Logarithms
When dealing with logarithms, the quotient rule is a powerful tool to simplify expressions. The rule states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator. In mathematical form, it is expressed as:
For example, in our original exercise, we applied the quotient rule like so: given \( \log \left( \frac{x^{3} y^{4}}{z^{6}} \right) \), we separated this into \( \log(x^{3} y^{4}) - \log(z^{6}) \). This is the first step towards simplifying complex logarithmic expressions.
- \( \log \left( \frac{a}{b} \right) = \log(a) - \log(b) \)
For example, in our original exercise, we applied the quotient rule like so: given \( \log \left( \frac{x^{3} y^{4}}{z^{6}} \right) \), we separated this into \( \log(x^{3} y^{4}) - \log(z^{6}) \). This is the first step towards simplifying complex logarithmic expressions.
Product Rule of Logarithms
The product rule of logarithms is another useful rule that helps in breaking down logarithmic expressions. According to this rule, the logarithm of a product is the sum of the logarithms of the individual factors. It can be written as:
In our example, we applied the product rule to \( \log(x^{3} y^{4}) \), allowing us to split it into \( \log(x^{3}) + \log(y^{4}) \). This step is essential to further simplify the expression by breaking down multiplied components into simpler parts.
- \( \log(ab) = \log(a) + \log(b) \)
In our example, we applied the product rule to \( \log(x^{3} y^{4}) \), allowing us to split it into \( \log(x^{3}) + \log(y^{4}) \). This step is essential to further simplify the expression by breaking down multiplied components into simpler parts.
Power Rule of Logarithms
The power rule of logarithms is pivotal when working with exponential terms inside logarithms. This rule states that if a variable inside a logarithm is raised to a power, the power can be brought in front as a coefficient. Mathematically, it is defined as:
In our exercise, we used this rule to transform \( \log(x^{3}) \) into \( 3 \cdot \log(x) \), \( \log(y^{4}) \) into \( 4 \cdot \log(y) \), and \( \log(z^{6}) \) into \( 6 \cdot \log(z) \). By using this rule, the expression is streamlined into simpler additive components, which are easier to handle or further manipulate if necessary.
- \( \log(a^{b}) = b \cdot \log(a) \)
In our exercise, we used this rule to transform \( \log(x^{3}) \) into \( 3 \cdot \log(x) \), \( \log(y^{4}) \) into \( 4 \cdot \log(y) \), and \( \log(z^{6}) \) into \( 6 \cdot \log(z) \). By using this rule, the expression is streamlined into simpler additive components, which are easier to handle or further manipulate if necessary.
Other exercises in this chapter
Problem 27
The hydrogen ion concentration of a sample of each substance is given. Calculate the pH of the substance. (a) Lemon juice: \(\left[\mathrm{H}^{+}\right]=5.0 \ti
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Solve the equation. $$ x^{2} 2^{x}-2^{x}=0 $$
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\(25-32\) Use the definition of the logarithmic function to find \(x\). $$ \begin{array}{ll}{\text { (a) } \log _{3} 243=x} & {\text { (b) } \log _{3} x=3}\end{
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An unknown substance has a hydrogen ion concentration of \(\left[\mathrm{H}^{+}\right]=3.1 \times 10^{-8} \mathrm{M} .\) Find the pH and classify the substance
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