Problem 27
Question
Use an appropriate Half-Angle Formula to find the exact value of the expression. $$\sin \frac{9 \pi}{8}$$
Step-by-Step Solution
Verified Answer
The exact value of \( \sin \frac{9\pi}{8} \) is \( -\frac{\sqrt{2 - \sqrt{2}}}{2} \).
1Step 1: Identify the Half-Angle Formula for Sine
The half-angle formula for sine is \( \sin \frac{\theta}{2} = \pm \sqrt{\frac{1 - \cos \theta}{2}} \). To determine the correct sign, we need to consider the quadrant in which \( \frac{9\pi}{8} \) lies. Since \( \frac{9\pi}{8} \) is slightly more than \( \pi \) (which is equivalent to \( 180^{\circ} \)), it lies in the third quadrant where sine is negative.
2Step 2: Express Given Angle in Terms of Double the Angle
The half-angle formula requires us to express \( \frac{9\pi}{8} \) as \( \frac{\theta}{2} \), meaning \( \theta = 2 \times \frac{9\pi}{8} = \frac{9\pi}{4} \). Let's simplify \( \frac{9\pi}{4} \) into a more familiar angle.
3Step 3: Simplify \( \theta \) to a Known Angle
Since \( 2\pi = \frac{8\pi}{4} \), we can subtract from \( \frac{9\pi}{4} \) to find \( \frac{9\pi}{4} - 2\pi = \frac{9\pi}{4} - \frac{8\pi}{4} = \frac{\pi}{4} \). Therefore, \( \cos\theta \) is based on \( \theta = \frac{\pi}{4} \).
4Step 4: Use the Half-Angle Formula
Now, compute \( \cos \theta = \cos \frac{\pi}{4} = \frac{\sqrt{2}}{2} \). Substitute this into the half-angle formula: \( \sin \frac{9\pi}{8} = - \sqrt{\frac{1 - \cos \frac{\pi}{4}}{2}} = - \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{2}} \).
5Step 5: Simplify the Expression
To simplify \( - \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{2}} \), start with the numerator: \( 1 - \frac{\sqrt{2}}{2} = \frac{2}{2} - \frac{\sqrt{2}}{2} = \frac{2 - \sqrt{2}}{2} \). Now plug it back: \( \frac{1 - \frac{\sqrt{2}}{2}}{2} = \frac{2 - \sqrt{2}}{4} \). Therefore, \( \sin \frac{9\pi}{8} = - \sqrt{\frac{2 - \sqrt{2}}{4}} = - \frac{\sqrt{2 - \sqrt{2}}}{2} \).
Key Concepts
Trigonometric IdentitiesExact Trigonometric ValuesQuadrants of the Unit Circle
Trigonometric Identities
Trigonometric identities are mathematical equations that are always true for the relationships between various trigonometric functions.
These identities are crucial for simplifying and solving complex trigonometric equations. Let's look at some fundamental identities that are often used in trigonometry:
In our exercise, the half-angle formula is essential for calculating the sine of \( \frac{9\pi}{8} \). By using these identities, you can convert complex trigonometric expressions into simpler forms, making the calculations more manageable.
These identities are crucial for simplifying and solving complex trigonometric equations. Let's look at some fundamental identities that are often used in trigonometry:
- **Pythagorean Identities**: These include equations like \( \sin^2 \theta + \cos^2 \theta = 1 \).
- **Reciprocal Identities**: These define relationships such as \( \sin \theta = \frac{1}{\csc \theta} \).
- **Half-Angle Identities**: These provide a way to calculate the trigonometric functions of half angles, such as \( \sin \frac{\theta}{2} = \pm \sqrt{\frac{1 - \cos \theta}{2}} \).
In our exercise, the half-angle formula is essential for calculating the sine of \( \frac{9\pi}{8} \). By using these identities, you can convert complex trigonometric expressions into simpler forms, making the calculations more manageable.
Exact Trigonometric Values
Exact trigonometric values are specific numerical values for common angles that we often use in trigonometry.
These values are typically derived from special triangles like the 45°-45°-90° and 30°-60°-90° triangles and are important for solving trigonometric equations without a calculator.
In this exercise, we leveraged the exact trigonometric value of \( \cos \frac{\pi}{4} = \frac{\sqrt{2}}{2} \) to calculate \( \sin \frac{9\pi}{8} \) precisely without approximation.
These values are typically derived from special triangles like the 45°-45°-90° and 30°-60°-90° triangles and are important for solving trigonometric equations without a calculator.
- For example, the sine and cosine of 45° or \( \frac{\pi}{4} \) are both \( \frac{\sqrt{2}}{2} \), as used in our solution above.
- The values for 30° (or \( \frac{\pi}{6} \)) and 60° (or \( \frac{\pi}{3} \)) include \( \sin \frac{\pi}{6} = \frac{1}{2} \) and \( \cos \frac{\pi}{3} = \frac{1}{2} \).
In this exercise, we leveraged the exact trigonometric value of \( \cos \frac{\pi}{4} = \frac{\sqrt{2}}{2} \) to calculate \( \sin \frac{9\pi}{8} \) precisely without approximation.
Quadrants of the Unit Circle
The unit circle is a fundamental concept in trigonometry that helps us understand the sign and value of trigonometric functions at different angles.
It is a circle with a radius of 1 centered at the origin of a coordinate plane. The circle is divided into four quadrants, and each quadrant determines the sign of sine, cosine, and tangent values:
It was crucial for finding the correct sign of \( \sin \frac{9\pi}{8} \), as the angle was located in the third quadrant.
It is a circle with a radius of 1 centered at the origin of a coordinate plane. The circle is divided into four quadrants, and each quadrant determines the sign of sine, cosine, and tangent values:
- **First Quadrant (0 to \( \frac{\pi}{2} \))**: Here, both sine and cosine values are positive.
- **Second Quadrant (\( \frac{\pi}{2} \) to \( \pi \))**: The sine is positive, while the cosine is negative.
- **Third Quadrant (\( \pi \) to \( \frac{3\pi}{2} \))**: Both sine and cosine are negative. This is where \( \frac{9\pi}{8} \) falls, resulting in a negative sine value.
- **Fourth Quadrant (\( \frac{3\pi}{2} \) to \( 2\pi \))**: The sine is negative, and the cosine is positive.
It was crucial for finding the correct sign of \( \sin \frac{9\pi}{8} \), as the angle was located in the third quadrant.
Other exercises in this chapter
Problem 26
Prove the identity. $$\cos \left(x-\frac{\pi}{2}\right)=\sin x$$
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Simplify the trigonometric expression. $$\frac{\cos x}{\sec x+\tan x}$$
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Find all solutions of the given equation. $$\sqrt{2} \sin \theta+1=0$$
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An equation is given. (a) Find all solutions of the equation. (b) Find the solutions in the interval \([0,2 \pi)\) $$\sin 2 \theta=3 \cos 2 \theta$$
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