Problem 27
Question
Use a graphing device to graph the ellipse. $$6 x^{2}+y^{2}=36$$
Step-by-Step Solution
Verified Answer
Graph the equation \( \frac{x^2}{6} + \frac{y^2}{36} = 1 \); it's an ellipse centered at the origin with a vertical major axis.
1Step 1: Write the Equation in Standard Form
We start with the given equation of the ellipse, which is in the form \( 6x^2 + y^2 = 36 \). To convert this into standard form, divide every term by 36 to get \( \frac{6x^2}{36} + \frac{y^2}{36} = 1 \). This simplifies to \( \frac{x^2}{6} + \frac{y^2}{36} = 1 \). This is the standard form of an ellipse centered at the origin.
2Step 2: Identify the Semi-Axes Lengths
From the standard form \( \frac{x^2}{6} + \frac{y^2}{36} = 1 \), we identify the denominators of the fractions as the squares of the semi-axis lengths. The term \( \frac{x^2}{6} \) indicates that \( a^2 = 6 \) (implying \( a = \sqrt{6} \)), and the term \( \frac{y^2}{36} \) indicates that \( b^2 = 36 \) (implying \( b = 6 \)). Hence, the semi-major axis length is 6 (along the y-axis), and the semi-minor axis length is \( \sqrt{6} \) (along the x-axis).
3Step 3: Determine the Orientation
Because \( b^2 > a^2 \), the major axis of the ellipse is vertical. This means the ellipse stretches more along the y-axis than the x-axis.
4Step 4: Use a Graphing Device
Enter the standard form equation \( \frac{x^2}{6} + \frac{y^2}{36} = 1 \) into a graphing device, ensuring the device is set to plot in Cartesian coordinates. Visually confirm the orientation and lengths of the semi-axes, observing an elongated shape along the y-axis.
Key Concepts
Standard Form of an EllipseSemi-Axes LengthsOrientation of Ellipse
Standard Form of an Ellipse
To graph an ellipse accurately, we need to convert its equation into standard form. The standard form of an ellipse centered at the origin is given by \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]where \(a\) and \(b\) are the semi-axes lengths. The given equation \(6x^2 + y^2 = 36\) can be rewritten by dividing each term by 36. This yields:
- \(\frac{6x^2}{36} + \frac{y^2}{36} = 1\)
- Simplifying gives \(\frac{x^2}{6} + \frac{y^2}{36} = 1\)
Semi-Axes Lengths
The semi-axes lengths of an ellipse are crucial for understanding its stretch. In the standard form \(\frac{x^2}{6} + \frac{y^2}{36} = 1\), the denominators represent the squares of the semi-axes lengths:
- The term \(\frac{x^2}{6}\) implies that \(a^2 = 6\), so \(a = \sqrt{6}\). This is the semi-minor axis along the x-axis.
- Similarly, \(\frac{y^2}{36}\) implies that \(b^2 = 36\), so \(b = 6\). This is the semi-major axis along the y-axis.
Orientation of Ellipse
The orientation of an ellipse describes how it is positioned in the plane. This is determined by comparing the lengths of the semi-major and semi-minor axes.
- If \(b^2 > a^2\), the ellipse is vertically oriented, meaning it stretches more along the y-axis. This is what happens for the given ellipse where \(b = 6\) and \(a = \sqrt{6}\).
- If \(a^2 > b^2\), the ellipse would stretch horizontally instead.
Other exercises in this chapter
Problem 27
Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find th
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Find an equation for the hyperbola that satisfies the given conditions. Foci \((\pm 5,0),\) vertices \((\pm 3,0)\)
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Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus \(F(-8,0)\)
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Find parametric equations for the ellipse $$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$$
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