Problem 27
Question
Two cards are drawn from a standard deck of cards. Find each probability. \(P(\text { both jacks or both face cards) }\)
Step-by-Step Solution
Verified Answer
The probability is approximately 0.0498.
1Step 1: Identify Total Possible Outcomes
A standard deck of cards consists of 52 cards. If two cards are drawn, the total number of possible combinations is calculated using the combinations formula: \( \binom{52}{2} \). Thus, the total possible outcomes are 1326.
2Step 2: Calculate Probability Both Cards are Jacks
There are 4 Jack cards in the deck. To find the probability of drawing two Jacks, calculate the number of ways to choose 2 Jacks out of 4: \( \binom{4}{2} = 6 \). Divide by the total combinations: \( \frac{6}{1326} \approx 0.0045 \).
3Step 3: Calculate Probability Both Cards are Face Cards
There are 12 face cards in a deck (Jacks, Queens, Kings in each suit). The number of ways to choose 2 face cards is \( \binom{12}{2} = 66 \). Divide by the total combinations to find the probability: \( \frac{66}{1326} \approx 0.0498 \).
4Step 4: Calculate Combined Probability (once without Overlapping)
To find the probability of either drawing both Jacks or both face cards, use the previously calculated probabilities. However, note that 'both Jacks' are already counted in 'both face cards'. Thus, the probability is simply the same as the probability of drawing two face cards: \( 0.0498 \).
Key Concepts
Combinations FormulaStandard Deck of CardsFace Cards ProbabilityJack Cards Probability
Combinations Formula
When determining how many ways we can choose a certain number of items from a larger set, we use the combinations formula. This formula helps us find how many different ways we can draw two cards from a deck of 52 cards, for instance. The formula is written as \( \binom{n}{r} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
- \( \binom{52}{2} \): Here, we get the total number of ways to choose 2 cards from 52, resulting in 1326 possible combinations.
- \( \binom{4}{2} \): For finding how we can choose 2 Jacks out of the 4 available in the deck.
- \( \binom{12}{2} \): Used for finding the number of ways to pick 2 face cards from the 12 in the deck.
Standard Deck of Cards
A standard deck of cards is a familiar tool in probability questions. Understanding its structure is critical in these problems. It contains 52 cards divided into 4 suits: Hearts, Diamonds, Clubs, and Spades. Each suit consists of 13 cards, ranging from Ace to King. Within these 13:
- Numbered cards from 2 to 10.
- Face cards: Jack, Queen, and King.
Face Cards Probability
Face cards in a deck are the Jacks, Queens, and Kings. Each of these appears four times, once in each suit, totaling 12 face cards altogether. To find the probability of drawing two face cards:1. Use the combinations formula to select 2 cards from 12 face cards: \( \binom{12}{2} = 66 \).2. Divide by the total combinations of drawing any two cards: \( \frac{66}{1326} \approx 0.0498 \).This probability reflects how likely it is to draw two face cards in one draw.
Jack Cards Probability
Jacks are one subset of face cards, with each deck containing 4 Jacks — one per suit. To compute how likely it is to draw two Jack cards:1. Calculate the number of ways to select 2 Jacks out of 4: \( \binom{4}{2} = 6 \).2. Then, find the proportion of these specific Jacks selections to the total combinations: \( \frac{6}{1326} \approx 0.0045 \).The concept helps clarify the specific odds of drawing pairs of certain types of cards.
Other exercises in this chapter
Problem 27
Prisana guesses at all 10 true/false questions on her history test. Find each probability. \(P(\text { at most half correct })\)
View solution Problem 27
OPEN ENDED Sketch a positively skewed graph. Describe a situation in which you would expect data to be distributed this way.
View solution Problem 27
Anita scores well enough at a carnival game that she gets to randomly draw two prizes out a prize bag. There are 6 purple T-shirts, 8 yellow T-shirts, and 5 T-s
View solution Problem 27
Three students are selected at random from a group of 3 sophomores and 3 juniors. The table and relative-frequency histogram show the distribution of the number
View solution