Problem 27
Question
The position of an object in circular motion is modeled by the given parametric equations. Describe the path of the object by stating the radius of the circle, the position at time \(t=0,\) the orientation of the motion (clockwise or counterclockwise), and the time \(t\) that it takes to complete one revolution around the circle. $$x=\sin 2 t, \quad y=\cos 2 t$$
Step-by-Step Solution
Verified Answer
The circle has radius 1, initial position \((0,1)\), moves counterclockwise, and takes \(t=\pi\) for one revolution.
1Step 1: Identify the Parametric Equations
The given parametric equations are \(x = \sin 2t\) and \(y = \cos 2t\). These equations describe the motion of the object in terms of \(x\) and \(y\) coordinates as functions of time \(t\).
2Step 2: Express as a Circular Equation
To find the equation of the path, we use the trigonometric identity \(\sin^2 \theta + \cos^2 \theta = 1\). Thus, substitute \(x = \sin 2t\) and \(y = \cos 2t\) into this identity: \(x^2 + y^2 = \sin^2 2t + \cos^2 2t = 1\). This shows the path is a circle with equation \(x^2 + y^2 = 1\).
3Step 3: Determine the Radius of the Circle
The general form of a circle is \(x^2 + y^2 = r^2\). Comparing it with our equation \(x^2 + y^2 = 1\), we find the radius \(r = 1\).
4Step 4: Find the Initial Position at \(t=0\)
Substitute \(t = 0\) into the parametric equations: \(x = \sin(0) = 0\) and \(y = \cos(0) = 1\). Thus, the initial position is \((0, 1)\).
5Step 5: Determine the Orientation of the Motion
To find if the motion is clockwise or counterclockwise, check the derivatives: the derivative \(dx/dt = 2\cos 2t\) and \(dy/dt = -2\sin 2t\). At \(t = 0\), \(dx/dt = 2\) and \(dy/dt = 0\), indicating motion towards positive \(x\), which is counterclockwise around the circle.
6Step 6: Calculate the Time for One Revolution
Since the parameter \(2t\) completes a cycle from \(0\) to \(2\pi\), it takes \(2t = 2\pi\) for a full revolution. Therefore, \(t = \pi\) for one complete revolution.
Key Concepts
Circular MotionTrigonometric IdentityDerivatives
Circular Motion
Objects in circular motion follow a path that is defined by a constant distance from a fixed point, known as the center of the circle. This distance is referred to as the radius of the circle. In our case, the parametric equations given were
The initial position at time \( t = 0 \) is determined by substituting the value into the parametric equations, ensuring we start tracking the motion from a specific known point, here
- \( x = \sin 2t \)
- \( y = \cos 2t \)
The initial position at time \( t = 0 \) is determined by substituting the value into the parametric equations, ensuring we start tracking the motion from a specific known point, here
- Position at \( t = 0 \) is \( (0, 1) \)
Trigonometric Identity
Trigonometric identities serve as powerful tools to simplify and interpret functions that are modeled using trigonometric terms. One key identity applied in the context of circular motion is
In parametric equations representing circular motion, such as \( x = \sin 2t \) and \( y = \cos 2t \), replacing \( x \) and \( y \) in the trigonometric identity results in a standard form of a circle: \( x^2 + y^2 = 1 \).
This signifies the path is indeed circular, with a radius derived from comparing it to the general circle equation \( x^2 + y^2 = r^2 \). Adopting trigonometric identities not only provides proofs but also simplifies the equations to easily discern key characteristics of motion, like shape and size of its path.
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
In parametric equations representing circular motion, such as \( x = \sin 2t \) and \( y = \cos 2t \), replacing \( x \) and \( y \) in the trigonometric identity results in a standard form of a circle: \( x^2 + y^2 = 1 \).
This signifies the path is indeed circular, with a radius derived from comparing it to the general circle equation \( x^2 + y^2 = r^2 \). Adopting trigonometric identities not only provides proofs but also simplifies the equations to easily discern key characteristics of motion, like shape and size of its path.
Derivatives
In the study of parametric equations, derivatives give important information about the rate of change of the coordinates with respect to time, and thus about the path's orientation and dynamics.
The derivatives of the coordinates \( x \) and \( y \) with respect to time are
Furthermore, understanding how parameter \( 2t \) affects time enables calculation of the period, or time taken for a complete revolution around the circle. Here, \( 2t = 2\pi \) leads to \( t = \pi \), denoting the time for one full cycle.
The derivatives of the coordinates \( x \) and \( y \) with respect to time are
- \( \frac{dx}{dt} = 2\cos 2t \)
- \( \frac{dy}{dt} = -2\sin 2t \)
- \( \frac{dx}{dt} = 2 \)
- \( \frac{dy}{dt} = 0 \)
Furthermore, understanding how parameter \( 2t \) affects time enables calculation of the period, or time taken for a complete revolution around the circle. Here, \( 2t = 2\pi \) leads to \( t = \pi \), denoting the time for one full cycle.
Other exercises in this chapter
Problem 26
The position of an object in circular motion is modeled by the given parametric equations. Describe the path of the object by stating the radius of the circle,
View solution Problem 26
Sketch a graph of the polar equation. $$r=1+\sin \theta$$
View solution Problem 27
Sketch a graph of the polar equation. $$r=-3(1+\sin \theta)$$
View solution Problem 27
Find the rectangular coordinates for the point whose polar coordinates are given. $$(4, \pi / 6)$$
View solution