Problem 27
Question
The point \((4,1)\) undergoes the following three successive transformations (A) Reflection about the line \(y=x-1\) (B) Translation through a distance 1 unit along the positive \(x\)-axis (C) Rotation through an angle \(\frac{\pi}{4}\) about the origin in the anti- clockwise direction. Then, the coordinates of the final point are (A) \((4,3)\) (B) \(\left(\frac{7}{2}, \frac{7}{2}\right)\) (C) \((0,3 \sqrt{2})\) (D) \((3,4)\)
Step-by-Step Solution
Verified Answer
None of the given options match the final coordinates. Check the calculations.
1Step 1: Reflection About Line
To reflect the point \((4, 1)\) about the line \(y = x - 1\), we consider the line's equation \(y = x - 1\) as \(y - x = -1\). Using the formula for reflection over a line defined by \(ax + by + c = 0\), the reflected point \((x', y')\) is found as:\[ x' = \frac{x - y + by - ax}{a^2 + b^2} + x, \]\[ y' = \frac{y - x + ax - by}{a^2 + b^2} + y. \]Here, \(a = -1\), \(b = 1\), \(c = -1\). Substitute these into the formulas to find the reflected point:\[ x' = \frac{4 - 1 + 1(1-4)}{1 + 1} + 4= \frac{2}{2} + 4 = 3, \]\[ y' = \frac{1 - 4 + 1(4-1)}{1 + 1} + 1= \frac{0}{2} + 1 = 1. \]Thus, the reflected point is \((3, 1)\).
2Step 2: Translation
To translate the point \((3, 1)\) along the positive \(x\)-axis by 1 unit, we add 1 to the x-coordinate:New point: \((3+1, 1) = (4, 1)\).
3Step 3: Rotation About the Origin
To rotate the point \((4, 1)\) by an angle of \(\frac{\pi}{4}\) around the origin in the anti-clockwise direction, we use the rotation matrix:\[x' = x\cos\theta - y\sin\theta \y' = x\sin\theta + y\cos\theta\]Substitute \(x = 4\), \(y = 1\), and \(\theta = \frac{\pi}{4}\):Using \(\cos\frac{\pi}{4} = \sin\frac{\pi}{4} = \frac{\sqrt{2}}{2}\), we have:\[ x' = 4 \times \frac{\sqrt{2}}{2} - 1 \times \frac{\sqrt{2}}{2} = 2\sqrt{2} - \frac{\sqrt{2}}{2} = \frac{4\sqrt{2} - \sqrt{2}}{2} = \frac{3\sqrt{2}}{2},\]\[ y' = 4 \times \frac{\sqrt{2}}{2} + 1 \times \frac{\sqrt{2}}{2} = 2\sqrt{2} + \frac{\sqrt{2}}{2} = \frac{5\sqrt{2}}{2}.\]So the point after rotation is \(\left(\frac{3\sqrt{2}}{2}, \frac{5\sqrt{2}}{2}\right)\).
Key Concepts
Reflection in LinesTranslation of PointsRotation of Points
Reflection in Lines
Reflecting a point across a line involves creating a mirror image of the point with respect to the line. In this scenario, the point \(4, 1\) is reflected over the line given by \(y = x - 1\). To determine the reflected point, we use the reflection formula for the line \(ax + by + c = 0\), where the line equation can be rewritten as \(y - x = -1\), giving us \(a = -1\), \(b = 1\), and \(c = -1\). By substituting these values into the reflection formula:
- \(x' = \frac{x - y + by - ax}{a^2 + b^2} + x\)
- \(y' = \frac{y - x + ax - by}{a^2 + b^2} + y\)
Translation of Points
Translation in coordinate geometry is the process of moving a point a certain distance in a given direction. For this exercise, the point \(3, 1\) is translated 1 unit along the positive \(x\)-axis. To translate a point involves adjusting its coordinates by adding or subtracting values depending on direction:
- Add to the \(x\)-coordinate if moving right, subtract if moving left.
- Add to the \(y\)-coordinate if moving up, subtract if moving down.
Rotation of Points
Rotation in coordinate geometry means turning a point around a fixed point, generally, the origin, by a specific angle. In our case, after translation, the point \(4, 1\) is rotated about the origin through an angle of \(\frac{\pi}{4}\) (45 degrees) in an anti-clockwise direction. The rotation transformations use the following matrix equations:
- \(x' = x\cos\theta - y\sin\theta\)
- \(y' = x\sin\theta + y\cos\theta\)
Other exercises in this chapter
Problem 24
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The distance between two parallel lines is unity. A point \(P\) lies between the lines at a distance \(a\) from one of them. The length of a side of an equilate
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Two points \(A\) and \(B\) are given. \(P\) is a moving point on one side of the line \(A B\) such that \(\angle P A B-\angle P B A\) is a positive constant \(2
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