Problem 27
Question
The Boolean Expression \((\mathrm{p} \wedge-q) \vee q \vee(\sim p \wedge q)\) is equivalent to: (a) \(\mathrm{p} \vee \mathrm{q}\) (b) \(\mathrm{pv}-\mathrm{q}(\mathrm{c})-\mathrm{p} \wedge \mathrm{q} \quad\) (d) \(\mathrm{p} \wedge \mathrm{q}\)
Step-by-Step Solution
Verified Answer
The expression simplifies to \(q\), so option (a) \(\mathrm{p} \vee \mathrm{q}\) is correct.
1Step 1: Identify the Boolean Expression Components
The given Boolean expression is \((\mathrm{p} \wedge eg q) \vee q \vee(\sim p \wedge q)\). We need to simplify this to find an equivalent expression.
2Step 2: Apply Boolean Identities
To simplify the expression, we use the identity \(A \vee eg A = \text{True}\). Recognizing that one of our parts, \(q\), will cover \((\mathrm{p} \wedge eg q) \vee q \), makes the entire part \((\mathrm{p} \wedge eg q) \vee q\) become True when \(q\) is True.
3Step 3: Simplify the Expression
Considering the identity used, the expression becomes \(q \vee (\sim p \wedge q)\). By factoring \(q\) out, we get \((q \cdot (1 \vee \sim p))\), simplifying further to \((q \cdot 1)\). Hence it simplifies to just \(q\).
4Step 4: Compare with Options
Now that we have simplified the expression to \(q\), we compare it to the options given: (a) \(\mathrm{p} \vee \mathrm{q}\), (b) \(\mathrm{p} \vee eg \mathrm{q}\), (c) \(-\mathrm{p} \wedge \mathrm{q}\), (d) \(\mathrm{p} \wedge \mathrm{q}\). The simplest comparable choice is (a) \(\mathrm{p} \vee \mathrm{q}\) as it encapsulates \(q\).
Key Concepts
Boolean identitiesSimplification of expressionsLogic gatesTruth tables
Boolean identities
Boolean identities are crucial tools that simplify complex expressions. These identities consist of rules that express logical equivalences, much like arithmetic operations have properties and laws. In our exercise, we used one of the well-known identities:
- Distributive Identity: When you have an expression like \( A \vee eg A \), it equals to True. This is useful because it means that when you have a logical variable and its negation in an OR operation, one of them will always be true, making the entire expression true.
- Identity laws
- Negation laws
- Idempotent laws
- Universal bound laws
- Demorgan's laws
Simplification of expressions
Simplifying Boolean expressions involves reducing a given logical expression to its simplest form. The key here is utilizing Boolean identities effectively to make the expression shorter while still maintaining its logical integrity.
Our expression, \((\mathrm{p} \wedge eg q) \vee q \vee (\sim p \wedge q)\), was simplified step-by-step:
Our expression, \((\mathrm{p} \wedge eg q) \vee q \vee (\sim p \wedge q)\), was simplified step-by-step:
- Step 1: Identify portions that can be logically ignored or reduced using identities.
- Step 2: Apply identities to simplify these bits.
- Step 3: Factor common terms to see if further reduction is possible.
Logic gates
Logic gates are the building blocks of digital circuits. They implement Boolean functions, which are central in computing. Each logic gate corresponds to a specific Boolean operation, enabling complex computations to be handled
in a straightforward manner.
in a straightforward manner.
- AND gate: Performs the logical conjunction, returning true only if both inputs are true, represented as \( \wedge \).
- OR gate: Outputs true if at least one input is true, represented as \( \vee \).
- NOT gate: Inverts the input, represented as \( eg \).
Truth tables
Truth tables are a formal representation of the outputs of a Boolean expression based on all possible input values. They offer a clear depiction of how a logical expression evaluates under different input conditions.
To construct a truth table:
To construct a truth table:
- List all variables involved.
- Cover all possible input combinations (e.g., for two variables \( p \) and \( q \), there are four combinations: \( 00, 01, 10, \) and \( 11 \)).
- Calculate the output for each input combination according to the logic of the expression.
Other exercises in this chapter
Problem 24
Which of the following is a tautology? (a) \((\sim \mathrm{p}) \wedge(\mathrm{p} \vee \mathrm{q}) \rightarrow \mathrm{q} \quad\) (b) \((\mathrm{q} \rightarrow \
View solution Problem 25
The following statement \((p \rightarrow q) \rightarrow[(\sim p \rightarrow q) \rightarrow q]\) is : \(\begin{array}{ll}\text { (a) a fallacy } & \text { (b) a
View solution Problem 28
The negation of \(\sim \mathrm{s} \vee(\sim \mathrm{r} \wedge \mathrm{s})\) is equivalent to: (a) \(s \vee(r \vee \sim s)\) (b) s\wedger (c) \(\mathrm{s} \wedge
View solution Problem 29
The statement \(-(p \leftrightarrow-q)\) is: (a) a tautology (b) a fallacy (c) eqivalent to \(p \leftrightarrow q\) (d) equivalent to \(\sim p \leftrightarrow q
View solution