Problem 27
Question
$$ \text { Graph each function } $$ $$ f(x)=\left\\{\begin{array}{ll} 2 x-7 & \text { if } x \geq 4 \\ 2-x & \text { if } x<4 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
Graph the two lines for different intervals, ensuring correct domain restrictions.
1Step 1: Understand the Piecewise Function
The given function is a piecewise function, which means it has different expressions for different intervals of the domain. Here, the function has two parts: \( f(x) = 2x - 7 \) when \( x \geq 4 \) and \( f(x) = 2 - x \) when \( x < 4 \).
2Step 2: Identify the Domain for Each Piece
For the first piece \( 2x - 7 \), the domain is \( x \geq 4 \). For the second piece \( 2 - x \), the domain is \( x < 4 \). Understanding the domain helps in plotting the pieces correctly on the graph.
3Step 3: Plot the First Piece
For \( x \geq 4 \), the function is \( f(x) = 2x - 7 \). Calculate a few points such as \( x = 4 \), \( x = 5 \): \( f(4) = 2(4) - 7 = 1 \); \( f(5) = 2(5) - 7 = 3 \). Draw a line through these points, starting at \( x = 4 \) and extending to the right since \( x \) is greater than or equal to 4.
4Step 4: Plot the Second Piece
For \( x < 4 \), the function is \( f(x) = 2 - x \). Calculate a few points such as \( x = 3 \), \( x = 2 \): \( f(3) = 2 - 3 = -1 \); \( f(2) = 2 - 2 = 0 \). Draw a line through these points, stopping just before \( x = 4 \) to ensure the function does not include \( x = 4 \) in this interval.
5Step 5: Combine the Pieces on the Graph
On the graph, combine both pieces ensuring continuity in the correct domains: the line from Step 3 starts at \( x = 4 \) and extends to the right; the line from Step 4 extends to the left from just below \( x = 4 \). Check for any gaps or undefined points especially at the boundary \( x = 4 \).
Key Concepts
graphing piecewise functionsdomain of piecewise functionsplotting functions in intervals
graphing piecewise functions
Graphing piecewise functions involves plotting different equations within specific intervals on the same coordinate plane. These functions can be quite flexible, allowing different behaviors in different domains.
Start by analyzing the given piecewise function and identifying each distinct piece. Each piece will pertain to a section of the function's domain, often split by specific values of the variable, such as the condition of being less than or greater than a number. For example, in the function given,
Start by analyzing the given piecewise function and identifying each distinct piece. Each piece will pertain to a section of the function's domain, often split by specific values of the variable, such as the condition of being less than or greater than a number. For example, in the function given,
- The piece \( 2x - 7 \) applies when \( x \geq 4 \).
- The piece \( 2 - x \) applies when \( x < 4 \).
domain of piecewise functions
The domain of piecewise functions refers to the full set of input values for which the function is defined. For each segment of a piecewise function, the domain is explicitly given or implied by inequalities or conditions.
In our example, understanding the individual intervals of each piece is crucial to plot the function correctly.
In our example, understanding the individual intervals of each piece is crucial to plot the function correctly.
- The domain for \( 2x - 7 \) is \( x \geq 4 \). This means the function part will include points like \( x = 4, \ 5, \ 6,\) and extend infinitely toward positive infinity.
- The domain for \( 2 - x \) is \( x < 4 \), encompassing points such as \( x = 3,\ 2, \ 1,\) and so forth.
plotting functions in intervals
Plotting functions in intervals requires organizing your graph into segments according to specific intervals dictated by the function's definition. This involves calculating specific points within each defined interval to guide accurate plotting.
For piecewise functions, each function piece has its interval, which acts like boundaries:
For piecewise functions, each function piece has its interval, which acts like boundaries:
- For \( x \geq 4 \), calculate points such as \( f(4) = 1 \) and \( f(5) = 3 \). These points define a line segment starting at \( x = 4 \) and extending rightwards.
- For \( x < 4 \), compute points like \( f(3) = -1 \) and \( f(2) = 0 \). This creates a line segment extending leftwards from just below \( x = 4 \).
Other exercises in this chapter
Problem 27
Evaluate each expression without using a calculator. $$ \left(\frac{25}{36}\right)^{3 / 2} $$
View solution Problem 27
Graph each function "by hand." [Note: Even if you have a graphing calculator, it is important to be able to sketch simple curves by finding a few important poin
View solution Problem 28
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. \(y=\frac{2}{3}(x-3)\)
View solution Problem 28
Evaluate each expression without using a calculator. $$ \left(\frac{16}{25}\right)^{3 / 2} $$
View solution