Problem 27
Question
Solve the given quadratic equations using the quadratic formula. If there are no real roots, state this as the answer. Exercises \(3-6\) are the same as Exercises \(13-16\) of Section 7.2. $$x^{2}-0.20 x-0.40=0$$
Step-by-Step Solution
Verified Answer
The real roots are 0.74 and -0.54.
1Step 1: Identify the coefficients
For the quadratic equation \(ax^2 + bx + c = 0\), identify the coefficients \(a\), \(b\), and \(c\). Here, \(a = 1\), \(b = -0.20\), and \(c = -0.40\).
2Step 2: Write down the quadratic formula
The quadratic formula is given by \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). We will use this formula to find the roots of the given equation.
3Step 3: Calculate the discriminant
The discriminant of the quadratic equation is \(b^2 - 4ac\). Substituting the values, we have \((-0.20)^2 - 4(1)(-0.40)\). Calculate this expression.
4Step 4: Simplify the discriminant
Compute the value of the discriminant: \(0.04 + 1.60 = 1.64\). Since the discriminant is positive, there are two real roots.
5Step 5: Substitute into the quadratic formula
Substitute the values and discriminant into the quadratic formula: \(x = \frac{-(-0.20) \pm \sqrt{1.64}}{2 \, \cdot \, 1}\). Simplify to find \(x = \frac{0.20 \pm \sqrt{1.64}}{2}\).
6Step 6: Calculate the roots
Calculate \(\sqrt{1.64}\) which is 1.28. So the roots are \(x = \frac{0.20 + 1.28}{2}\) and \(x = \frac{0.20 - 1.28}{2}\).
7Step 7: Simplify the results
Simplify the expressions to find the roots: \(x = \frac{1.48}{2} = 0.74\) and \(x = \frac{-1.08}{2} = -0.54\). Thus, the roots of the equation are \(x = 0.74\) and \(x = -0.54\).
Key Concepts
Understanding the DiscriminantThe Quadratic Equation UnveiledExploring Real Roots
Understanding the Discriminant
The discriminant is a crucial part of solving quadratic equations using the quadratic formula. It is represented by the expression under the square root in the formula: \(b^2 - 4ac\). The discriminant helps in determining the nature of the roots of a quadratic equation.
- If the discriminant is positive (\(b^2 - 4ac > 0\)), the quadratic equation has two distinct real roots.
- If it is zero (\(b^2 - 4ac = 0\)), the equation has exactly one real root, also known as a repeated root since both roots are the same.
- If the discriminant is negative (\(b^2 - 4ac < 0\)), the equation has no real roots; instead, the roots are complex numbers.
The Quadratic Equation Unveiled
A quadratic equation is any polynomial equation of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. In these equations, \(a\) cannot be zero because if it were, the equation would not remain quadratic (instead, it becomes linear).
The graph of a quadratic equation is a parabola. The shape and direction of the parabola are determined by the coefficient \(a\). If \(a > 0\), the parabola opens upwards, but if \(a < 0\), it opens downwards.
The graph of a quadratic equation is a parabola. The shape and direction of the parabola are determined by the coefficient \(a\). If \(a > 0\), the parabola opens upwards, but if \(a < 0\), it opens downwards.
- The solutions or "roots" of the equation are the points where the parabola intersects the x-axis.
- These solutions can be obtained algebraically using various methods: factoring, completing the square, and, most broadly applicable, the quadratic formula.
Exploring Real Roots
Real roots of a quadratic equation are the solutions or values of \(x\) that satisfy the equation \(ax^2 + bx + c = 0\). These are essentially the x-values where the parabola intersects the x-axis.
- When solving using the quadratic formula, if the discriminant is positive, the equation will have two different real roots. This means the parabola intersects the x-axis at two distinct points.
- If the discriminant is zero, there is exactly one real root, signifying the parabola just touches the x-axis at one point, often referred to as the vertex of the parabola.
Other exercises in this chapter
Problem 26
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