Problem 27
Question
Solve equation. Check your solution. \(3 c+4.5=7.2-6 c\)
Step-by-Step Solution
Verified Answer
The solution is \(c = 0.3\).
1Step 1: Move Variable Terms to One Side
To isolate the variable term, let's add \(6c\) to both sides of the equation. This gives us:\[ 3c + 6c + 4.5 = 7.2 \]
2Step 2: Combine Like Terms
Combine the \(c\)-terms on the left side:\[ 9c + 4.5 = 7.2 \]
3Step 3: Isolate the Variable Term
Now, subtract \(4.5\) from both sides to isolate the term with the variable:\[ 9c = 7.2 - 4.5 \]This simplifies to:\[ 9c = 2.7 \]
4Step 4: Solve for the Variable
Divide both sides by \(9\) to solve for \(c\):\[ c = \frac{2.7}{9} \]Simplify the fraction:\[ c = 0.3 \]
5Step 5: Check the Solution
Substitute \(c = 0.3\) back into the original equation to verify:\[ 3(0.3) + 4.5 = 7.2 - 6(0.3) \]Calculate each side:Left side: \(0.9 + 4.5 = 5.4\)Right side: \(7.2 - 1.8 = 5.4\)Since both sides are equal, the solution \(c = 0.3\) is correct.
Key Concepts
AlgebraChecking SolutionsIsolating VariablesCombining Like Terms
Algebra
Algebra often revolves around finding the unknown, which is usually represented by a variable like \( c \). This branch of mathematics uses letters to represent numbers in equations, allowing us to solve for unknown values systematically. Understanding algebra involves performing operations such as addition, subtraction, multiplication, and division while maintaining balance on both sides of the equation.
When tackling algebraic equations, you'll frequently encounter the need to rearrange terms and isolate variables. This process helps in simplifying expressions, making the unknown easier to find. Algebra forms the backbone of advanced mathematics, and learning it sets the stage for tackling calculus and other mathematical fields.
When tackling algebraic equations, you'll frequently encounter the need to rearrange terms and isolate variables. This process helps in simplifying expressions, making the unknown easier to find. Algebra forms the backbone of advanced mathematics, and learning it sets the stage for tackling calculus and other mathematical fields.
Checking Solutions
After finding a solution to an equation, verifying its accuracy is crucial. This process, known as "checking solutions," ensures that the value derived for the variable satisfies the original equation. In our exercise, after finding \( c = 0.3 \), we substitute it back into the original equation:
- The left side becomes \( 3(0.3) + 4.5 = 0.9 + 4.5 = 5.4 \).
- The right side simplifies to \( 7.2 - 6(0.3) = 7.2 - 1.8 = 5.4 \).
Isolating Variables
Isolating the variable is a step in algebra where you aim to get the variable by itself on one side of the equation. This involves moving terms from both sides to achieve a simpler form, helping clarify what value the variable represents. In our exercise, we started with the equation \( 3c + 4.5 = 7.2 - 6c \).
To isolate \( c \), we first added \( 6c \) to both sides, which helped gather all terms with \( c \) on one side. This gave us \( 3c + 6c = 7.2 - 4.5 \), which simplifies further once we combine and simplify the terms. From here, we continued to solve for \( c \), following a clear path that ultimately simplified the equation in a way that made finding \( c \) straightforward.
To isolate \( c \), we first added \( 6c \) to both sides, which helped gather all terms with \( c \) on one side. This gave us \( 3c + 6c = 7.2 - 4.5 \), which simplifies further once we combine and simplify the terms. From here, we continued to solve for \( c \), following a clear path that ultimately simplified the equation in a way that made finding \( c \) straightforward.
Combining Like Terms
Combining like terms is an essential skill in solving algebraic equations. It involves simplifying expressions by adding or subtracting terms that have the same variable factor. For example, in our exercise, after moving all the \( c \) terms to one side, we had \( 3c + 6c \).
We then combined these to get \( 9c \), simplifying our equation to \( 9c + 4.5 = 7.2 \). This process helps reduce complexity and brings clarity to equations, making them easier to solve. Mastering the ability to combine like terms allows for a more efficient approach to problem-solving in algebra and lays a solid foundation for tackling more complex equations.
We then combined these to get \( 9c \), simplifying our equation to \( 9c + 4.5 = 7.2 \). This process helps reduce complexity and brings clarity to equations, making them easier to solve. Mastering the ability to combine like terms allows for a more efficient approach to problem-solving in algebra and lays a solid foundation for tackling more complex equations.
Other exercises in this chapter
Problem 27
Graph each inequality on a number line. $$w \leq 8$$
View solution Problem 27
Solve each inequality. Check your solution. Then graph the solution on a number line. $$6>\frac{x}{-7}$$
View solution Problem 27
Solve each inequality. Then graph the solution on a number line. $$-3+z>2$$
View solution Problem 28
Solve each inequality and check your solution. Then graph the solution on a number line. $$\frac{1}{2}(6-c)>5$$
View solution