Problem 27
Question
Solve each quadratic equation by completing the square. $$ 2 x^{2}+7 x-12=0 $$
Step-by-Step Solution
Verified Answer
Answer: The solutions are \(x = -\frac{7}{4} + \sqrt{\frac{145}{16}}\) and \(x = -\frac{7}{4} - \sqrt{\frac{145}{16}}\).
1Step 1: Rewrite the equation in the standard form
The given equation is already in the standard form:
$$
2x^2+7x-12=0
$$
2Step 2: Divide the equation by the coefficient of the x^2 term
Divide the entire equation by 2:
$$
x^2+\frac{7}{2}x-6=0
$$
3Step 3: Complete the square
To make a perfect square trinomial, we need to add the square of half of the coefficient of the x term:
$$
\left(\frac{\frac{7}{2}}{2}\right)^2 = \left(\frac{7}{4}\right)^2 = \frac{49}{16}
$$
Add \(\frac{49}{16}\) to both sides of the equation:
$$
x^2 + \frac{7}{2}x + \frac{49}{16} = 6 + \frac{49}{16}
$$
4Step 4: Rewrite the left side of the equation as a binomial squared
Now, we rewrite the left side of the equation as a binomial squared:
$$
\left(x+\frac{7}{4}\right)^2 = 6 + \frac{49}{16}
$$
5Step 5: Solve for x using square roots
Solve for x by taking the square root of both sides of the equation:
$$
x + \frac{7}{4} = \pm\sqrt{6 + \frac{49}{16}}
$$
Now, simplify the right side of the equation:
$$
x + \frac{7}{4} = \pm\sqrt{\frac{96 + 49}{16}} = \pm\sqrt{\frac{145}{16}}
$$
Finally, subtract \(\frac{7}{4}\) from both sides to solve for x:
$$
x = -\frac{7}{4} \pm\sqrt{\frac{145}{16}}
$$
The two solutions for x are:
$$
x = -\frac{7}{4} + \sqrt{\frac{145}{16}},\, -\frac{7}{4} - \sqrt{\frac{145}{16}}
$$
Key Concepts
Quadratic EquationsBinomial SquaredSolving Quadratic EquationsAlgebraic Manipulation
Quadratic Equations
To begin solving any quadratic equation by completing the square, it's essential to understand what a quadratic equation is. At its core, a quadratic equation is any equation that forms a parabola when graphed. It's typically written in the standard form of:
\[ ax^2 + bx + c = 0 \]
where:
\[ ax^2 + bx + c = 0 \]
where:
- \(a\), \(b\), and \(c\) are constants, with \(a\) not equal to zero.
- \(x\) represents the unknown variable.
Binomial Squared
A binomial squared is a perfect square trinomial that can be expressed in the form:
\[ (x + d)^2 \]
For example, \((x + 3)^2\) results in \(x^2 + 6x + 9\).
This technique is crucial in the process of completing the square because it allows us to simplify complex expressions into a format that is easy to solve using square roots.
When completing the square, you're transforming part of your quadratic equation into this structure. You do this by adding and subtracting the square of half the coefficient of the middle term \(b\) — it’s this manipulation that allows the expression to neatly fold into the squared form.
Building the intuition for recognizing a binomial squared helps streamline the solving process and sets the stage for finding solutions more easily.
\[ (x + d)^2 \]
For example, \((x + 3)^2\) results in \(x^2 + 6x + 9\).
This technique is crucial in the process of completing the square because it allows us to simplify complex expressions into a format that is easy to solve using square roots.
When completing the square, you're transforming part of your quadratic equation into this structure. You do this by adding and subtracting the square of half the coefficient of the middle term \(b\) — it’s this manipulation that allows the expression to neatly fold into the squared form.
Building the intuition for recognizing a binomial squared helps streamline the solving process and sets the stage for finding solutions more easily.
Solving Quadratic Equations
Solving quadratic equations by completing the square involves transforming your quadratic expression into an equation featuring a perfect square, making it possible to find the roots by taking square roots. Here’s a quick rundown of the steps you would ordinarily follow:
- First, ensure the quadratic equation is in the standard form.
- Divide the equation by the coefficient of \(x^2\) (if it’s not 1) to simplify it, thus preparing it for completing the square.
- Transform the rearranged quadratic into a binomial squared by adding/subtracting the necessary constant.
- Once in perfect square form, solve for \(x\) by taking the square root of both sides.
Algebraic Manipulation
Algebraic manipulation is all about rearranging and simplifying expressions to achieve the desired form or solution. It’s an invaluable skill when solving quadratic equations by completing the square.
Let’s break down what it involves:
Let’s break down what it involves:
- Rewriting: You might need to rewrite terms, such as separating or combining like terms or transforming expressions into equivalent forms.
- Balancing: When you add or subtract a number to one side of an equation, ensure you do the same operation to the other side to maintain equality.
- Simplifying: By completing the square, you simplify the quadratic expression to a format that essentially handles the variable manipulation for you.
Other exercises in this chapter
Problem 27
For the following problems, solve the equations. $$ 5 a^{2}-125=0 $$
View solution Problem 27
Three is added to an integer and that sum is doubled. When this result is multiplied by the original integer the product is 20 . Find the integer.
View solution Problem 27
For the following problems, solve the equations using the quadratic formula. $$ 5 a^{2}-2 a-3=0 $$
View solution Problem 27
For the following problems, solve the equations by completing the square. $$ 4 b^{2}-8 b=16 $$
View solution