Problem 27
Question
Solve each of the equations. $$\frac{n}{150-n}=\frac{1}{2}$$
Step-by-Step Solution
Verified Answer
The solution is \( n = 50 \).
1Step 1: Cross-Multiply
The given equation is \( \frac{n}{150-n} = \frac{1}{2} \). To eliminate the fractions, cross-multiply: \( n \times 2 = (150-n) \times 1 \). This results in the equation \( 2n = 150 - n \).
2Step 2: Isolate the Variable
Add \( n \) to both sides of the equation to combine like terms: \( 2n + n = 150 \). This simplifies to \( 3n = 150 \).
3Step 3: Solve for \( n \)
Divide both sides of the equation by 3 to solve for \( n \): \( n = \frac{150}{3} \). This simplifies to \( n = 50 \).
4Step 4: Verify the Solution
Substitute \( n = 50 \) back into the original equation to ensure it satisfies the condition: \( \frac{50}{150-50} = \frac{50}{100} = \frac{1}{2} \). The original equation is satisfied, confirming the solution is correct.
Key Concepts
Cross-MultiplicationIsolate the VariableVerify the Solution
Cross-Multiplication
When solving fractions in an equation, cross-multiplication is a handy tool that can help simplify the process. Imagine you have an equation like \( \frac{n}{150-n} = \frac{1}{2} \). The idea here is to eliminate the fractions by multiplying each denominator by the numerator on the opposite side of the equation.
This gives rise to a new equation without fractions: \( n \times 2 = (150-n) \times 1 \).
Cross-multiplication transforms a fraction-based problem into a simple algebraic equation, making it easier to solve.
This gives rise to a new equation without fractions: \( n \times 2 = (150-n) \times 1 \).
Cross-multiplication transforms a fraction-based problem into a simple algebraic equation, making it easier to solve.
- Multiply the numerator of one fraction by the denominator of the other fraction.
- Do the same for the other side.
Isolate the Variable
To solve any equation, the main goal is often to isolate the variable—get it by itself on one side of the equation. After cross-multiplying, you end up with an equation like \( 2n = 150 - n \).
At this stage, you want to move all the terms involving your variable, \( n \), to one side.
The first thing you can do here is add \( n \) to both sides of the equation. Doing so gives \( 2n + n = 150 \) which simplifies to \( 3n = 150 \).
At this stage, you want to move all the terms involving your variable, \( n \), to one side.
The first thing you can do here is add \( n \) to both sides of the equation. Doing so gives \( 2n + n = 150 \) which simplifies to \( 3n = 150 \).
- Combine like terms, often by adding or subtracting terms from both sides.
- Get the variable by itself by using inverse operations, like addition, subtraction, multiplication, or division.
Verify the Solution
Once you've isolated the variable and found a solution, your work isn't quite done yet. It’s time to verify the solution to ensure it is correct. For our equation \( n = 50 \), we substitute back into the original equation to check our work.
Plug \( n = 50 \) into \( \frac{n}{150-n} = \frac{1}{2} \), which gives us \( \frac{50}{150-50} = \frac{50}{100} = \frac{1}{2} \).
Notice that both sides are equal, meaning the solution satisfies the original equation.
Plug \( n = 50 \) into \( \frac{n}{150-n} = \frac{1}{2} \), which gives us \( \frac{50}{150-50} = \frac{50}{100} = \frac{1}{2} \).
Notice that both sides are equal, meaning the solution satisfies the original equation.
- Substitute your solution back into the original equation.
- Check to see if both sides of the equation are equal.
Other exercises in this chapter
Problem 27
For Problems 11-32, use the geometric formulas given in this section to help solve the problems. (Objective 3 ) Find the volume and total surface area of a righ
View solution Problem 27
Set up an equation and solve each problem. (Objectives 2 and 3) Suppose that Jack bought a \(\$ 32\) putter on sale for \(35 \%\) off. How much did he pay for t
View solution Problem 28
The perimeter of a triangle is 40 centimeters. The longest side is 1 centimeter longer than twice the shortest side. The other side is 2 centimeters shorter tha
View solution Problem 28
Suppose that a square and an equilateral triangle have the same perimeter. Each side of the equilateral triangle is 6 centimeters longer than each side of the s
View solution