Problem 27
Question
Solve each inequality. $$(k+7)^{2} \geq-9$$
Step-by-Step Solution
Verified Answer
The inequality \((k+7)^2 \geq -9\) is always true for any value of \(k\), since the square of any real number is non-negative. Therefore, the solution is all real numbers.
1Step 1: Analyzing the inequality
First, let's observe that the square of any real number is non-negative. Therefore, \((k+7)^2\) will always be greater than or equal to 0.
2Step 2: Compare with given inequality
We want to determine if \((k+7)^2 \geq -9\). Since \((k+7)^2\) is always greater than or equal to 0, and 0 is greater than -9, we can conclude that this inequality is always true.
3Step 3: Solution
For any value of k, the inequality \((k+7)^2 \geq -9\) will always be true. Hence, the solution to this inequality is all real numbers.
Key Concepts
Real NumbersAlgebraic ExpressionsInequality Solutions
Real Numbers
Real numbers include all the numbers on the number line. This encompasses both rational and irrational numbers.
- Rational numbers: These are numbers that can be expressed as a fraction, like \ \frac{1}{2} \, 4, or \ -7.\
- Irrational numbers: Numbers that cannot be expressed as a simple fraction, such as \( \pi \) and \( \sqrt{2} \).
Algebraic Expressions
An algebraic expression consists of numbers, variables, and operations like addition or multiplication.
The expression \((k+7)^{2}\) is a simple algebraic expression, where \(k\) is a variable, and \((k+7)\) is squared.
The expression \((k+7)^{2}\) is a simple algebraic expression, where \(k\) is a variable, and \((k+7)\) is squared.
- Variables represent unknown values.
- Expressions can be manipulated using algebraic rules to solve problems like inequalities.
Inequality Solutions
Inequalities, like equations, show the relationship between expressions. However, they tell us that one side is either greater or smaller than the other.
In our example, \((k+7)^2 \geq -9\), we are looking at a squared term that prompts us to examine the nature of square numbers.
In our example, \((k+7)^2 \geq -9\), we are looking at a squared term that prompts us to examine the nature of square numbers.
- Square values are always non-negative.
- This means \(\forall k, (k+7)^2 \geq 0 \), and 0 is indeed greater than -9.
Other exercises in this chapter
Problem 27
Solve. $$\frac{x}{x-4}-\frac{4}{x+4}=\frac{32}{x^{2}-16}$$
View solution Problem 27
Simplify. $$(2 x)^{4}(3 x)^{3}$$
View solution Problem 27
Identify the center of each hyperbola and graph the equation. $$\frac{y^{2}}{16}-\frac{x^{2}}{4}=1$$
View solution Problem 27
Solve each system. $$\begin{aligned} 9 x^{2}+y^{2} &=9 \\ x^{2}+y^{2} &=5 \end{aligned}$$
View solution