Problem 27
Question
Solve each equation. \(\frac{2 a-3}{6}+\frac{3 a-2}{4}+\frac{5 a+6}{12}=4\)
Step-by-Step Solution
Verified Answer
The solution to the equation is \( a = 3 \).
1Step 1: Identify the Least Common Denominator (LCD)
The fractions in the equation have denominators 6, 4, and 12. To clear the fractions, we need the least common denominator. The least common multiple of 6, 4, and 12 is 12.
2Step 2: Eliminate Fractions
Multiply every term in the equation by 12, the LCD, to eliminate fractions: \[12 \left( \frac{2a-3}{6} \right) + 12 \left( \frac{3a-2}{4} \right) + 12 \left( \frac{5a+6}{12} \right) = 12 \times 4 \] Simplifying each term: \[ 2 \times (2a-3) + 3 \times (3a-2) + 1 \times (5a+6) = 48 \] This leads to: \[ 4a - 6 + 9a - 6 + 5a + 6 = 48 \]
3Step 3: Combine Like Terms
Combine the like terms in the equation: \[ (4a + 9a + 5a) + (-6 - 6 + 6) = 48 \] Which simplifies to: \[ 18a - 6 = 48 \]
4Step 4: Isolate the Variable
First, add 6 to both sides of the equation to remove the constant on the left side: \[ 18a - 6 + 6 = 48 + 6 \] Simplifying gives: \[ 18a = 54 \]
5Step 5: Solve for 'a'
Divide both sides by 18 to solve for 'a': \[ a = \frac{54}{18} \] Simplifying the fraction gives: \[ a = 3 \]
Key Concepts
Least Common DenominatorFraction EliminationCombining Like TermsIsolating the Variable
Least Common Denominator
The concept of the Least Common Denominator (LCD) is crucial when dealing with equations containing fractions. The LCD is the smallest number that each of the denominators in your equation can divide into equally. By determining the LCD, you can simplify and solve fractional equations more effectively.
For example, consider the denominators in the equation: 6, 4, and 12. To find the LCD, identify the least common multiple (LCM) of these numbers.
For example, consider the denominators in the equation: 6, 4, and 12. To find the LCD, identify the least common multiple (LCM) of these numbers.
- List the multiples of each number:
- Multiples of 6: 6, 12, 18, 24,...
- Multiples of 4: 4, 8, 12, 16,...
- Multiples of 12: 12, 24, 36,...
- The lowest common multiple shared by these numbers is 12.
Fraction Elimination
Once the Least Common Denominator is determined, you can proceed to the Fraction Elimination stage. This step is all about clearing the fractions from your equation to simplify the process of solving it.
To eliminate fractions, multiply every term in your equation by the LCD (in this case, 12). This transforms each fractional term into a whole number expression:
To eliminate fractions, multiply every term in your equation by the LCD (in this case, 12). This transforms each fractional term into a whole number expression:
- \[12 \times \left( \frac{2a-3}{6} \right) = 2 \times (2a-3)\]
- \[12 \times \left( \frac{3a-2}{4} \right) = 3 \times (3a-2)\]
- \[12 \times \left( \frac{5a+6}{12} \right) = 1 \times (5a+6)\]
Combining Like Terms
After eliminating fractions, the next step involves Combining Like Terms, which helps to further simplify the equation. Like terms are terms that contain the same variables raised to the same power.
In the equation:
In the equation:
- Identify and group terms with the same variable: \(4a + 9a + 5a\) and constants \(-6 - 6 + 6\).
- Combine these terms by summing or subtracting their coefficients: \((4a + 9a + 5a) = 18a\) and \((-6 - 6 + 6) = -6\).
Isolating the Variable
Isolating the Variable is the final step toward finding the solution to your equation. The goal in this step is to get the variable (in this case, \(a\)) on one side of the equation by itself.
Here’s how it’s done:
Here’s how it’s done:
- First, eliminate any constants from the side with the variable by performing the inverse operation. Add 6 to both sides: \[18a - 6 + 6 = 48 + 6\] which simplifies to \[18a = 54\].
- Next, isolate \(a\) by dividing both sides of the equation by 18, which gets you: \[a = \frac{54}{18}\].
- Simplify the fraction to find \(a = 3\).
Other exercises in this chapter
Problem 27
Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \(-7 x-3 \leq 4\)
View solution Problem 27
Solve each equation. \(0.1(x-0.1)-0.4(x+2)=-5.31\)
View solution Problem 27
Solve each equation. \(4 x-3+2 x=8 x-3-x\)
View solution Problem 28
Solve each equation and inequality. \(|5 x-7|=14\)
View solution