Problem 27
Question
Solve each determinant equation for \(x\). $$\operatorname{det}\left[\begin{array}{rl}-0.5 & 2 \\\x & x\end{array}\right]=0$$
Step-by-Step Solution
Verified Answer
x = 0.
1Step 1: Set Up the Determinant Equation
The determinant of a 2x2 matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\) is calculated as \(ad - bc\). For the given matrix \(\begin{bmatrix} -0.5 & 2 \ x & x \end{bmatrix}\), set up the determinant equation: \(-0.5 \cdot x - (2 \cdot x) = 0\).
2Step 2: Simplify the Determinant Equation
Simplify the determinant equation from Step 1: \(-0.5x - 2x = 0\).
3Step 3: Combine Like Terms
Combine the terms: \(-0.5x - 2x\) to get \(-2.5x\). This simplifies the equation to \(-2.5x = 0\).
4Step 4: Solve for x
To solve \(-2.5x = 0\), divide both sides of the equation by -2.5: \(x = 0\).
5Step 5: Verify the Solution
Substitute \(x = 0\) back into the original determinant expression to verify: \((-0.5 \cdot 0) - (2 \cdot 0) = 0\). The determinant is zero, confirming that \(x = 0\) is correct.
Key Concepts
Understanding the 2x2 MatrixWorking with Matrix EquationsSolving Determinant Equations
Understanding the 2x2 Matrix
In the world of matrices, the 2x2 matrix is among the simplest yet important structures. A 2x2 matrix is a rectangular array of numbers arranged into 2 rows and 2 columns. Here's a generic form to visualize:
- First row: \(a, b\)
- Second row: \(c, d\)
Working with Matrix Equations
Matrix equations involve calculations with matrices to find unknowns. They are equations in which matrices play a critical role, either through their arrangement or involvement in determinant calculations.Consider this example using a 2x2 matrix:\[\operatorname{det}\left[\begin{array}{cc}-0.5 & 2 \x & x\end{array}\right] = 0\]The goal is to solve this matrix equation to find \(x\). To do so, we look at the determinant, which is a special number calculated from a matrix.The determinant for a 2x2 matrix is determined by the formula:\[ad - bc\]where \((a, b, c, d)\) are the elements of the matrix. By plugging these values from our example, the equation becomes:\(-0.5 \cdot x - 2 \cdot x = 0\). This simplifies to help us find the value of \(x\). The matrix equation approach can efficiently solve problems that involve finding unknowns when matrices and their arrangements are involved.
Solving Determinant Equations
Solving equations that involve determinants, especially for a 2x2 matrix, follows a systematic process. The determinant value provides a pathway to solve for unknowns within the matrix elements.Let's break down the steps:
- Firstly, express the determinant equation. For a 2x2 matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\), it's represented as \(ad - bc = 0\) if the determinant equals zero.
- Then, substitute the variables into this expression. In the given example, \(-0.5 \cdot x - 2 \cdot x = 0\)\ occurs.
- Combine like terms to simplify the expression: here, \(-2.5x = 0\).
- Finally, solve for the variable: divide both sides by the coefficient to isolate the unknown, giving \(x = 0\).
Other exercises in this chapter
Problem 26
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} 5 x-4 y+z &=9 \\ x+y\qu
View solution Problem 26
Solve each system by elimination. $$\begin{array}{l}-x+4 y=0 \\\2 x-4 y=6\end{array}$$
View solution Problem 27
Each augmented matrix is in row echelon form and represents a linear system. Use back-substitution to solve the system if possible. $$\left[\begin{array}{rrr|r}
View solution Problem 27
Graph each inequality. $$x^{2}+(y+3)^{2} \leq 16$$
View solution