Problem 27
Question
Simplify each numerical expression. \(\left(4^{2} \cdot 5^{-1}\right)^{2}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{256}{25}\).
1Step 1: Apply the Power of a Power Rule
First, apply the power of a power rule, which states \((a^m)^n = a^{m \cdot n}\). In this case, apply it to each part of the expression \((4^2 \cdot 5^{-1})^2\). Simplify the exponents inside the parentheses, which results in \((4^{2 \cdot 2} \cdot 5^{-1 \cdot 2}) = (4^4 \cdot 5^{-2})\).
2Step 2: Simplify Each Term
Next, compute each term separately. Calculate \(4^4\), giving a result of 256, and \(5^{-2}\), which is equivalent to \(\frac{1}{5^2}\) or \(\frac{1}{25}\).
3Step 3: Multiply the Results
Multiply the results of the previous step together. You have \(256 \cdot \frac{1}{25}\), which simplifies to \(\frac{256}{25}\).
Key Concepts
Power of a Power RuleNegative ExponentsMultiplying Fractions
Power of a Power Rule
When you encounter expressions like \((a^m)^n\), they can look intimidating at first. But, there's a simple rule called the Power of a Power rule that can help simplify them. This rule states that you can multiply the exponents together: \((a^m)^n = a^{m \cdot n}\).
Let's break it down. Suppose you have \((4^2)^2\). According to this rule, you multiply the exponents, which are 2 and 2 in this case, giving you \(4^{2 \times 2} = 4^4\). It’s like repeatedly applying the base to itself, making it much simpler.
Remember, apply this rule to each part of the expression individually if there are multiple terms. For example, in \((4^2 \cdot 5^{-1})^2\), apply it to both 4 and 5 independently, resulting in \(4^4 \cdot 5^{-2}\). This step streamlines the process, making calculations easier in later steps.
Let's break it down. Suppose you have \((4^2)^2\). According to this rule, you multiply the exponents, which are 2 and 2 in this case, giving you \(4^{2 \times 2} = 4^4\). It’s like repeatedly applying the base to itself, making it much simpler.
Remember, apply this rule to each part of the expression individually if there are multiple terms. For example, in \((4^2 \cdot 5^{-1})^2\), apply it to both 4 and 5 independently, resulting in \(4^4 \cdot 5^{-2}\). This step streamlines the process, making calculations easier in later steps.
Negative Exponents
Negative exponents might seem tricky, but they are simply the inverse of their positive counterparts. The key thing to remember is that a negative exponent indicates the reciprocal. For example, \(a^{-n} = \frac{1}{a^n}\).
So, if you stumble upon something like \(5^{-2}\), it transforms into the fraction \(\frac{1}{5^2}\), or \(\frac{1}{25}\). This is because the negative exponent signifies that we're flipping the base to the denominator.
Taking care of negative exponents early can simplify further calculations. If your expression involves both negative and positive exponents, like our example, manage them one at a time to avoid confusion. This approach keeps the math neat and errors at bay.
So, if you stumble upon something like \(5^{-2}\), it transforms into the fraction \(\frac{1}{5^2}\), or \(\frac{1}{25}\). This is because the negative exponent signifies that we're flipping the base to the denominator.
Taking care of negative exponents early can simplify further calculations. If your expression involves both negative and positive exponents, like our example, manage them one at a time to avoid confusion. This approach keeps the math neat and errors at bay.
Multiplying Fractions
Multiplying fractions is a foundational skill that can simplify complex math problems. To multiply fractions:
Multiply straight across, top and bottom to get \(\frac{256 \times 1}{1 \times 25} = \frac{256}{25}\).
The result is already simplified if there are no common factors in the numerator and the denominator. Mastering this process makes dealing with fractions second nature and ensures your calculations are accurate.
- Multiply the numerators (the top numbers) together.
- Multiply the denominators (the bottom numbers) together.
Multiply straight across, top and bottom to get \(\frac{256 \times 1}{1 \times 25} = \frac{256}{25}\).
The result is already simplified if there are no common factors in the numerator and the denominator. Mastering this process makes dealing with fractions second nature and ensures your calculations are accurate.
Other exercises in this chapter
Problem 27
Express each of the following in simplest radical form. All variables represent positive real numbers. \(\sqrt{64 x^{3} y^{7}}\)
View solution Problem 27
Change each radical to simplest radical form. \(\sqrt{160}\)
View solution Problem 28
Write each of the following in ordinary decimal notation. For example, \((3.18)(10)^{2}=318\). \((5.2)(10)^{-2}\)
View solution Problem 28
Evaluate each numerical expression. \(-16^{\frac{3}{4}}\)
View solution