Problem 27
Question
Let \(\mathbf{x}=[1,1]^{\prime}\). Find \(\mathbf{y}\) so that \(\mathbf{x}\) and \(\mathbf{y}\) are perpendicular.
Step-by-Step Solution
Verified Answer
\( \mathbf{y} = [1, -1]' \) is perpendicular to \( \mathbf{x} = [1, 1]' \).
1Step 1: Understand Perpendicular Vectors
Two vectors are perpendicular if their dot product is zero. In this problem, the vectors \( \mathbf{x} \) and \( \mathbf{y} \) are perpendicular, meaning \( \mathbf{x} \cdot \mathbf{y} = 0 \).
2Step 2: Set Up Dot Product Equation
Let \( \mathbf{y} = [y_1, y_2]' \). The dot product \( \mathbf{x} \cdot \mathbf{y} \) is computed as \( 1 \cdot y_1 + 1 \cdot y_2 = y_1 + y_2 \). Therefore, the condition for perpendicularity becomes \( y_1 + y_2 = 0 \).
3Step 3: Solve for Components of \( \mathbf{y} \)
Given the equation \( y_1 + y_2 = 0 \), you can express \( y_2 \) in terms of \( y_1 \): \( y_2 = -y_1 \). Thus, any vector of the form \( \mathbf{y} = [y_1, -y_1]' \) will be perpendicular to \( \mathbf{x} = [1, 1]' \).
4Step 4: Choose Specific Solution for \( \mathbf{y} \)
Select a specific value for \( y_1 \) to find a particular solution. For simplicity, let \( y_1 = 1 \), then \( y_2 = -1 \), resulting in \( \mathbf{y} = [1, -1]' \).
Key Concepts
Dot ProductPerpendicular VectorsVector Components
Dot Product
The dot product is a fundamental concept in vector mathematics. It provides a method to multiply two vectors, yielding a scalar result. The dot product of two vectors \(\mathbf{a} = [a_1, a_2]'\) and \(\mathbf{b} = [b_1, b_2]'\) is calculated using the formula:\[\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2\]This calculation involves multiplying corresponding components and summing them. It serves as a useful tool to determine the relationship between vectors. One key application is identifying perpendicular vectors. Two vectors are perpendicular if their dot product equals zero. This means there is no alignment between them. In simpler terms, computing the dot product answers whether vectors point in orthogonal directions, forming a right angle between them.
Perpendicular Vectors
Perpendicular vectors, also known as orthogonal vectors, are vectors whose dot product is zero. This orthogonality implies that they form a right angle, or 90 degrees, with each other. In the context of the exercise, we determined that vectors \(\mathbf{x} = [1, 1]'\) and \(\mathbf{y} = [y_1, y_2]'\) are perpendicular if their dot product \(y_1 + y_2\) equals zero.
- Setting the dot product to zero gives the condition \(y_1 + y_2 = 0\).
- This equation implies that the sum of the vector components must cancel out to zero for perpendicularity.
Vector Components
Vector components refer to the individual elements that comprise a vector. Each vector in a 2-dimensional space, like \(\mathbf{y} = [y_1, y_2]'\), has two components that dictate its position and direction. Understanding these components is crucial, as they determine how a vector behaves under various operations like addition, subtraction, and the dot product.In the given problem, the components of \(\mathbf{y}\) need to satisfy the equation \(y_1 + y_2 = 0\) for \(\mathbf{y}\) to be perpendicular to \(\mathbf{x} = [1, 1]'\). This relationship highlights the importance of manipulating individual vector components:
- When \(y_1\) changes, \(y_2\) must adjust accordingly to maintain the perpendicularity condition.
- We can express \(y_2\) as \(-y_1\), showing a negative relationship between the components.
Other exercises in this chapter
Problem 26
Let $$A=\left[\begin{array}{rr} -1 & 0 \\ 1 & 2 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & 0 \\ -1 & -1 \end{array}\right], \quad C=\left[\begin{ar
View solution Problem 26
In Problems 25-28, find the augmented matrix and use it to solve the system of linear equations. $$ \begin{aligned} -x-2 y+3 z &=-9 \\ 2 x+y-z &=5 \\ 4 x-3 y+5
View solution Problem 27
Compute ax for each vector \(\mathbf{x}\) and scalar \(a\). Represent \(\mathbf{x}\) and ax in the plane, and explain graphically how you obtain \(a \mathrm{x}\
View solution Problem 27
Suppose that \(A\) is a \(3 \times 4\) matrix and \(B\) is a \(4 \times 2\) matrix. What is the size of the product \(A B\) ?
View solution